Explanation Given: A right-angled triangle of height 3 m and base 2 m is submerged in water vertically with its upper vertex located at the depth of 4 m. Formula Used: The fluid force F on the side is obtained by the following formula: F = ρ g ∫ a b y f ( y ) d y … ( 1 ) Where, Water density ρ = 1000 kg/m 3 and Acceleration of gravity g = 9.8 m/s 2 Calculation: Consider the following figure of the given right-angled triangle: By similar triangle property, we have f ( y ) y − 4 = 2 3 f ( y ) = 2 3 ( y − 4 ) Now, from the equation (1), the fluid force on one side of the triangle is: F = ρ g ∫ 4 7 y f ( y ) d y = ρ g ∫ 4 7 y [ 2 3 ( y − 4 )

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Author: Rogawski

Publisher: MAC HIGHER

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Chapter 9, Problem 19CRE

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The fluid force on the side of the right-angled triangle.

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Chapter 9, Problem 18CRE

Chapter 9, Problem 20CRE

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