a.
Find the value of frequency f in hertz.
a.
Answer to Problem 1P
The value of frequency in hertz is
Explanation of Solution
Given data:
The given sinusoidal current is,
Formula used:
Consider the general expression for sinusoidal current.
Here,
Calculation:
Compare equation (1) with equation (2), that is
Conclusion:
Thus, the value of frequency in hertz is
b.
Find the value of period in milliseconds.
b.
Answer to Problem 1P
The value of period in milliseconds is
Explanation of Solution
Calculation:
Consider the general expression for time period.
Substitute
Conclusion:
Thus, the value of period in milliseconds is
c.
Find the maximum amplitude of the current.
c.
Answer to Problem 1P
The maximum amplitude of the current is
Explanation of Solution
Calculation:
Compare equation (1) with equation (2), that is
Conclusion:
Thus, the maximum amplitude of the current is
d.
Find the value of voltage
d.
Answer to Problem 1P
The value of voltage
Explanation of Solution
Calculation:
Substitute 0 for
Conclusion:
Thus, the value of voltage
e.
Find the value of phase angle in terms of degrees and radians.
e.
Answer to Problem 1P
The value of phase angle in terms of degrees and radians are
Explanation of Solution
Calculation:
Compare equation (1) with equation (2), that is
Convert phase angle in terms of radians.
Conclusion:
Thus, the value of phase angle in terms of degrees and radians are
f.
Find the smallest possible value of
f.
Answer to Problem 1P
The smallest possible value of
Explanation of Solution
Calculation:
Substitute 0 for
Simplify the equation as follows.
Conclusion:
Thus, the smallest possible value of
g.
Find the smallest possible value of
g.
Answer to Problem 1P
The smallest possible value of
Explanation of Solution
Calculation:
Apply differentiation on both sides of equation (1) as follows.
Substitute 0 for
Simplify the equation as follows.
Conclusion:
Thus, the smallest possible value of
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Chapter 9 Solutions
EBK ELECTRIC CIRCUITS
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