The estimation of standard deviation using 95% data range .

Question

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Answer 1

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 9, Problem 4CRP

(a)

To determine

To find: The estimation of standard deviation using 95% data range.

(b)

To determine

To find:

The probability that the oxygen demand would fall below 8mg/L.

(c)

To determine

To find:

The probability that the oxygen demand is greater than 12mg/L.

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Answer 2

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 9, Problem 4CRP

(a)

To determine

To find: The estimation of standard deviation using 95% data range.

(b)

To determine

To find:

The probability that the oxygen demand would fall below 8mg/L.

(c)

To determine

To find:

The probability that the oxygen demand is greater than 12mg/L.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 9, Problem 4CRP

(a)

To determine

To find: The estimation of standard deviation using 95% data range.

(b)

To determine

To find:

The probability that the oxygen demand would fall below 8mg/L.

(c)

To determine

To find:

The probability that the oxygen demand is greater than 12mg/L.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 9, Problem 4CRP

(a)

To determine

To find: The estimation of standard deviation using 95% data range.

(b)

To determine

To find:

The probability that the oxygen demand would fall below 8mg/L.

(c)

To determine

To find:

The probability that the oxygen demand is greater than 12mg/L.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 9, Problem 4CRP

(a)

To determine

To find: The estimation of standard deviation using 95% data range.

(b)

To determine

To find:

The probability that the oxygen demand would fall below 8mg/L.

(c)

To determine

To find:

The probability that the oxygen demand is greater than 12mg/L.

Answer 6

Chapter 9, Problem 4CRP

(a)

To determine

To find: The estimation of standard deviation using 95% data range.

Answer 7

Chapter 9, Problem 4CRP

(a)

To determine

To find: The estimation of standard deviation using 95% data range.

Answer 8

(b)

To determine

To find:

The probability that the oxygen demand would fall below 8mg/L.

Answer 9

(b)

To determine

To find:

The probability that the oxygen demand would fall below 8mg/L.

Answer 10

(c)

To determine

To find:

The probability that the oxygen demand is greater than 12mg/L.

Answer 11

(c)

To determine

To find:

The probability that the oxygen demand is greater than 12mg/L.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

The estimation of standard deviation using 95% data range .

Solution Summary: The author calculates the standard deviation using a random variable x having normal distribution with mean mu =9.9mg/L.

To find: The estimation of standard deviation using 95% data range.

To find:

The probability that the oxygen demand would fall below 8mg/L.

To find:

The probability that the oxygen demand is greater than 12mg/L.

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Chapter 9 Solutions

The estimation of standard deviation using 95% data range .

Solution Summary: The author calculates the standard deviation using a random variable x having normal distribution with mean mu =9.9mg/L.

To find: The estimation of standard deviation using 95% data range.

To find: The probability that the oxygen demand would fall below 8mg/L.

To find: The probability that the oxygen demand is greater than 12mg/L.

Want to see the full answer?

Chapter 9 Solutions

To find:

The probability that the oxygen demand would fall below 8mg/L.

To find:

The probability that the oxygen demand is greater than 12mg/L.