EBK CONCEPTS OF GENETICS
12th Edition
ISBN: 9780134818979
Author: Killian
Publisher: YUZU
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Chapter 9, Problem 6PDQ
Predict the results of a cross between ascospores from a segregational petite strain and a neutral petite strain. Indicate the
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Indicate the percentage of tetrads that would have 0,1, 2, 3, or 4 viable spores after Saccharomycescerevisiae a / α diploids of the following genotypesare sporulated:a. A true-breeding wild-type strain (with no mutations in any gene essential for viability).b. A strain heterozygous for a null (completely inactivating) mutation in a single essential gene.For the remaining parts of this problem, considercrosses between yeast strains of the form a × b, wherea and b are both temperature-sensitive mutations indifferent essential genes. The cross is conducted under permissive (low-temperature) conditions. Indicatethe percentage of tetrads that would have 0, 1, 2, 3, or4 viable spores subsequently measured under restrictive (high-temperature) conditions.c. a and b are unlinked, and both are 0 m.u. from thecentromere.d. a and b are unlinked; a is 0 m.u. from the centromere, while b is 10 m.u. from the centromere.e. a and b are 0 m.u. apart.f. a and b are 10 m.u. apart. Assume all…
Which of the pedigree diagrams below is most likely to show a family with Haemophilia A?
In considering the formation of the A–P and D–V axes inDrosophila, we noted that, for mutations such as bcd,homozygous mutant mothers uniformly produce mutant offspring with segmentation defects. This outcomeis always true regardless of whether the offspring themselves are bcd+/bcd or bcd/bcd. Some other maternaleffect lethal mutations are different, in that the mutantphenotype can be “rescued” by introducing a wild-typeallele of the gene from the father. In other words, forsuch rescuable maternal-effect lethals, mut+/mut animals are normal, whereas mut/mut animals have the mutant defect. Explain the difference between rescuableand nonrescuable maternal-effect lethal mutations.
Chapter 9 Solutions
EBK CONCEPTS OF GENETICS
Ch. 9 - Chlamydomonas, a eukaryoric green alga, may be...Ch. 9 - In aerobically cultured yeast, a petite mutant is...Ch. 9 - DNA in human mitochondria encodes 22 different...Ch. 9 - Prob. 4NSTCh. 9 - Why did Marcia choose mitochondrial testing to...Ch. 9 - Marcia saw an ad on television for ancestry DNA...Ch. 9 - How much importance should we place on the results...Ch. 9 - HOW DO WE KNOW? In this chapter, we focused on...Ch. 9 - Review the Chapter Concepts list on page 196. The...Ch. 9 - Streptomycin resistance in Chlamydomonas may...
Ch. 9 - A plant may have green, white, or green-and-white...Ch. 9 - In diploid yeast strains, sporulation and...Ch. 9 - Predict the results of a cross between ascospores...Ch. 9 - In Lymnaea, what results would you expect in a...Ch. 9 - In a cross of Lymnaea, the snail contributing the...Ch. 9 - In Drosophila subobscura, the presence of a...Ch. 9 - A male mouse from a true-breeding strain of...Ch. 9 - Consider the case where a mutation occurs that...Ch. 9 - What is the endosymbiotic theory, and why is this...Ch. 9 - In an earlier Problems and Discussion section (see...Ch. 9 - Mitochondrial replacement therapy (MRT) offers a...Ch. 9 - The specification of the anteriorposterior axis in...Ch. 9 - The maternal-effect mutation bicoid (bcd) is...Ch. 9 - (a) In humans the mitochondrial genome encodes a...Ch. 9 - Mutations in mitochondrial DNA appear to be...Ch. 9 - Researchers examined a family with an interesting...Ch. 9 - Payne, B. A. et al. (2013) present evidence that a...Ch. 9 - As mentioned in Section 9.3, mtDNA accumulates...Ch. 9 - Because offspring inherit the mitochondrial genome...
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- Draw a diagram of a cross between Dura and Pisifera. F1 and F2 and their genotypic and phenotypic ratios. draw the picture and the cross chessboard.arrow_forwardContrast the fertility of an allotetraploid with an autotriploid and an autotetraploid.arrow_forwardPlease solve this problem using the test cross branch diagram without a punnet square.arrow_forward
- From a cross between e+ f+ g+ and e− f − g− strains ofNeurospora, recombination between these linkedgenes resulted in a few octads containing the followingordered set of spores:e+ f+ g+e+ f+ g+e+ f − g+e+ f − g+e− f − g−e− f − g−e− f − g−e− f − g−a. Where was recombination initiated?b. Did crossing-over occur between genes e and g?Explain.c. Why do you end up with 2 f+ : 6 f − but 4 e+: 4 e−and 4g+: 4g−?d. Could you characterize these unusual octads as MIor MII for any of the three genes involved?Explain.arrow_forwardFrom the fungal cross arg-6 ⋅ al-2 × arg-6+ ⋅ al-2+, whatwill the spore genotypes be in unordered tetrads thatare (a) parental ditypes? (b) tetratypes? (c) nonparental ditypes?arrow_forwardAt the molecular level (with regard to loss-of-function alleles), explain why the ttvv homozygote has an ovate seed capsule.arrow_forward
- The life cycle of the haploid fungus Ascobolus is similar tothat of Neurospora. A mutational treatment producedtwo mutant strains, 1 and 2, both of which when crossedwith wild type gave unordered tetrads, all of the followingtype (fawn is a light brown color; normally, crosses produce all black ascospores):spore pair 1 black spore pair 3 fawnspore pair 2 black spore pair 4 fawna. What does this result show? Explain.The two mutant strains were crossed. Most of the unordered tetrads were of the following type:spore pair 1 fawn spore pair 3 fawnspore pair 2 fawn spore pair 4 fawnb. What does this result suggest? Explain.When large numbers of unordered tetrads were screenedunder the microscope, some rare ones that containedblack spores were found. Four cases are shown here:Case A Case B Case C Case Dspore pair 1 black black black blackspore pair 2 black fawn black abortspore pair 3 fawn fawn abort fawnspore pair 4 fawn fawn abort fawn(Note: Ascospores with extra genetic material…arrow_forwardWhen the Ascomycetes fungus reproduces sexually, mating type A fungi cross fertilize mating type a fungi. The resulting zygotes undergo meiotic and then mitotic division to produce asci with eight ascospores. The ascospores in the asci are ordered and reflect the position of the parental nuclei in the zygote. Use the passage to answer the question. Although ascospores are produced by mitotic division, none of the spores develop into fungi that are identical to either parental hyphae. What is the BEST explanation for this observation? A. The spores inherit half their genes from each parent. B. The spores inherit haploid nuclei from their parents. C. The spores inherit mutations as a result of meiosis. D. The spores inherit mutations as a result of mitosis.arrow_forwardIf Emmer wheat (Figure 17-9) is crossed to another wildwheat CC (not shown), what would be the constitution ofa sterile product of this cross? What amphidiploid couldarise from the sterile product? Would the amphidiploidbe fertile?arrow_forward
- On chromosome 4 in Nuerospora, the allele pyr-1 results in a pyrimidine requirement for growth. A cross is made between a pyr-1 and pyr+ strain and the following results were obtained: 26 of a 2:4:2 pattern of pyr-1:pyr+:pyr-1 25 of a 2:4:2 pattern of pyr+:pyr-1:pyr+ 24 of a 2:2:2:2 pattern of pyr-1:pyr+:pyr-1:pyr+ 457 of a 4:4 pattern of pyr-1:pyr+ 27 of a 2:2:2:2 pattern of pyr+:pyr-1:pyr+:pyr-1 452 of a 4:4 pattern of pyr+:pyr-1 What is the distance of the pyr locus to the centromere? Show your work.arrow_forwardA cross was performed between a yeast strain that requires methionine and lysine for growth (met− lys−)and another yeast strain, which is met+ lys+. One hundred asci were dissected, and colonies were grownfrom the four spores in each ascus. Cells from thesecolonies were tested for their ability to grow on petriplates containing either minimal medium (min), min+ lysine (lys), min + methionine (met), or min + lys+ met. The asci could be divided into two groupsbased on this analysis:Group 1: In 89 asci, cells from two of the four spore colonies couldgrow on all four kinds of media, while the other two spore coloniescould grow only on min + lys + met.Group 2: In 11 asci, cells from one of the four spore colonies couldgrow on all four kinds of petri plates. Cells from a second one ofthe four spore colonies could grow only on min + lys plates andon min + lys + met plates. Cells from a third of the four sporecolonies could only grow on min + met plates and on min + lys+ met. Cells from the…arrow_forwardNeurospora of genotype a + c are crossed withNeurospora of genotype + b +. (Here, + is shorthandfor the wild-type allele.) The following tetrads areobtained (note that the genotype of the four sporepairs in an ascus are listed, rather than listing alleight spores):a + c a b c + + c + b c a b + a + ca + c a b c a + c a b c a b + a b c+ b + + + + + b + + + + + + c + + ++ b + + + + a b + a + + + + c + b +137 141 26 25 2 3a. In how many cells has meiosis occurred to yieldthese data?b. Give the best genetic map to explain these results.Indicate all relevant genetic distances, both betweengenes and between each gene and the centromere.c. Diagram a meiosis that could give rise to oneof the three tetrads in the class at the far right inthe listarrow_forward
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