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- 7. The resistor in an R-L series circuit has a voltage drop of 53 V, and the inductor has a voltage drop of 28 V. What is the applied voltage of the circuit?arrow_forwardFill in all the missing values. Refer to the formulas that follow. Resistance Capacitance Time constant Total time 150 k 100 F 350 k 35 s 350 pF 10 s 0.05 F 1.2 M 0.47 F 12F 0.05 s 86 k 1.5 s 120 k 470 pF 250 nF 100 ms 8 F 150 s 100 k 150 ms 33 k 4 F =RCR=CC=R Totaltime=5arrow_forwardThe circuit in Figure 24-2 is connected to a 120-V, 60-Hz line. The resistor has a resistance of 36 , the inductor has an inductive reactance of 40 , and the capacitor has a capacitive reactance of 50 . ET120VITZVAPFERIRR36PELILXL40VARsLLECICXC50VARsCCarrow_forward
- What is the minimum KVAR rating of each capacitor in Question 11? (Round off the value to the nearest KVAR.)arrow_forwardWhat is the unit of measurement for the strength of a capacitor? microamp microtorque microfarad microwattarrow_forwardThe current in the circuit shown is known to be io=5e−2000t(2cos 4000t+sin 4000t) for t≥0+. Find v1(0+) and v2(0+).arrow_forward
- The current through a 100-uF capacitor is i(t) = 50 sin 120 πt mA. Calculate the voltage across it at t =1 ms and t = 5ms. Take v(0) = 0.arrow_forwardThe voltage across a 5uF capacitor is v(t)= 10 cos 5000t V. Calculate the current through it.arrow_forwardL1 = 20.0 mH, L2 = 5.0 mH, L3 =4.0 mH. What is the total inductance between A and B? A 8.33 mH B 6.25 mH C 8.0 mH D 29.0 mHarrow_forward
- Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningElectricity for Refrigeration, Heating, and Air C...Mechanical EngineeringISBN:9781337399128Author:Russell E. SmithPublisher:Cengage Learning