Chapter 9, Problem 8PEB

(a)

To determine

The balanced chemical equation for the unbalanced reaction $\text{NO}+{\text{O}}_2\to {\text{NO}}_2$.

Answer to Problem 8PEB

The balanced chemical equation is $\text{2NO}+{\text{O}}_2\to 2{\text{NO}}_2$.

Explanation of Solution

For a balanced chemical equation the number of atoms for each element on the reactant and product side should be same.

The balanced chemical equation for unbalanced reaction $\text{NO}+{\text{O}}_2\to {\text{NO}}_2$ is given below.

    $\text{2NO}+{\text{O}}_2\to 2{\text{NO}}_2$

(b)

To determine

The balanced chemical equation for the unbalanced reaction ${\text{KClO}}_{\text{3}}\to \text{KCl}+{\text{O}}_2$.

Answer to Problem 8PEB

The balanced chemical equation is ${\text{2KClO}}_{\text{3}}\to 2\text{KCl}+{\text{O}}_2$.

Explanation of Solution

For a balanced chemical equation the number of atoms for each element on the reactant and product side should be same.

The balanced chemical equation for unbalanced reaction ${\text{KClO}}_{\text{3}}\to \text{KCl}+{\text{O}}_2$ is given below.

    ${\text{2KClO}}_{\text{3}}\to 2\text{KCl}+{\text{O}}_2$

(c)

To determine

The balanced chemical equation for the unbalanced reaction ${\text{NH}}_4\text{CL}+\text{Ca}{\left(\text{OH}\right)}_2\to {\text{CaCl}}_2{\text{+NH}}_3{\text{+H}}_2\text{O}$.

Answer to Problem 8PEB

The balanced chemical equation is ${\text{2NH}}_4\text{CL}+\text{Ca}{\left(\text{OH}\right)}_2\to {\text{CaCl}}_2{\text{+2NH}}_3{\text{+2H}}_2\text{O}$.

Explanation of Solution

For a balanced chemical equation the number of atoms for each element on the reactant and product side should be same.

The balanced chemical equation for the unbalanced reaction ${\text{NH}}_4\text{CL}+\text{Ca}{\left(\text{OH}\right)}_2\to {\text{CaCl}}_2{\text{+NH}}_3{\text{+H}}_2\text{O}$ is given below.

    ${\text{2NH}}_4\text{CL}+\text{Ca}{\left(\text{OH}\right)}_2\to {\text{CaCl}}_2{\text{+2NH}}_3{\text{+2H}}_2\text{O}$

(d)

To determine

The balanced chemical equation for unbalanced reaction ${\text{NaNO}}_3+{\text{H}}_2{\text{SO}}_4\to {\text{Na}}_2{\text{SO}}_4+{\text{HNO}}_3$.

Answer to Problem 8PEB

The balanced chemical equation is ${\text{2NaNO}}_3+{\text{H}}_2{\text{SO}}_4\to {\text{Na}}_2{\text{SO}}_4+2{\text{HNO}}_3$.

Explanation of Solution

For a balanced chemical equation the number of atoms for each element on the reactant and product side should be same.

The balanced chemical equation for unbalanced reaction ${\text{NaNO}}_3+{\text{H}}_2{\text{SO}}_4\to {\text{Na}}_2{\text{SO}}_4+{\text{HNO}}_3$ is given below.

    ${\text{NaNO}}_3+{\text{H}}_2{\text{SO}}_4\to {\text{Na}}_2{\text{SO}}_4+{\text{HNO}}_3$

(e)

To determine

The balanced chemical equation for unbalanced reaction $\text{PbS}+{\text{H}}_{\text{2}}{\text{O}}_2\to {\text{PbSO}}_4+{\text{H}}_{\text{2}}\text{O}$.

Answer to Problem 8PEB

The balanced chemical equation is $\text{PbS}+4{\text{H}}_{\text{2}}{\text{O}}_2\to {\text{PbSO}}_4+4{\text{H}}_{\text{2}}\text{O}$.

Explanation of Solution

For a balanced chemical equation the number of atoms for each element on the reactant and product side should be same.

The balanced chemical equation for unbalanced reaction $\text{PbS}+{\text{H}}_{\text{2}}{\text{O}}_2\to {\text{PbSO}}_4+{\text{H}}_{\text{2}}\text{O}$ is given below.

    $\text{PbS}+4{\text{H}}_{\text{2}}{\text{O}}_2\to {\text{PbSO}}_4+4{\text{H}}_{\text{2}}\text{O}$

(f)

To determine

The balanced chemical equation for unbalanced reaction ${\text{Al}}_2{\left({\text{SO}}_{\text{4}}\right)}_3+{\text{BaCl}}_{\text{2}}\to {\text{AlCl}}_3+{\text{BaSO}}_{\text{4}}$.

Answer to Problem 8PEB

The balanced chemical equation is ${\text{Al}}_2{\left({\text{SO}}_{\text{4}}\right)}_3+3{\text{BaCl}}_{\text{2}}\to 2{\text{AlCl}}_3+2{\text{BaSO}}_{\text{4}}$.

Explanation of Solution

For a balanced chemical equation the number of atoms for each element on the reactant and product side should be same.

The balanced chemical equation for unbalanced reaction ${\text{Al}}_2{\left({\text{SO}}_{\text{4}}\right)}_3+{\text{BaCl}}_{\text{2}}\to {\text{AlCl}}_3+{\text{BaSO}}_{\text{4}}$ is given below.

    ${\text{Al}}_2{\left({\text{SO}}_{\text{4}}\right)}_3+3{\text{BaCl}}_{\text{2}}\to 2{\text{AlCl}}_3+2{\text{BaSO}}_{\text{4}}$