Explanation Given: The hypotheses are: H 0 : μ = 12 H a : μ ≠ 12 Formula used: The test statistic formula for one sample − t test is, t = x ¯ − μ s n The standard deviation formula is: s d = ∑ ( x i − x ¯ ) 2 n − 1 For Sample 1: The summary of the statistics is: Population mean ( μ ) = 12.000 Sample mean ( x ¯ ) = 11.9587 Sample standard deviation ( s ) = 0.2204 Sample size ( n ) = 30 The test statistic value is, t = x ¯ − μ s n = 11.9587 − 12 0.2204 30 = − 0.0413 0.0402 = − 1.03 The degree of freedom is, d f = n − 1 = 30 − 1 = 29 Compute p -value. p − value = P ( t > | − 1.03 | ) = 0.3127 The following is the decision rule: Reject H o if p < 0.01 or accept the null hypothesis. Here, the obtained p-value is greater than the given significance level. Thus, the null hypothesis is not rejected and it could be concluded that mean is not different from 12. For Sample 2: Sample mean ( x ¯ ) = 12.0287 Sample standard deviation ( s ) = 0.2204 The test statistic value is, t = x ¯ − μ s n = 12.0287 − 12 0.2204 30 = 0.7125 The degree of freedom is, d f = n − 1 = 30 − 1 = 29 Compute p -value

Essentials of Modern Business Statistics with Microsoft Office Excel (Book Only)

7th Edition

ISBN: 9781337298353

Author: David R. Anderson, Dennis J. Sweeney, Thomas A. Williams

Publisher: South-Western College Pub

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Chapter 9, Problem 9.1.1CP

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To perform:The hypothesis testingto compute the p-value and test statistic. Also, suggest the corrective actions that should be taken, if required.

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Chapter 9 Solutions

Essentials of Modern Business Statistics with Microsoft Office Excel (Book Only)

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To perform: The hypothesis testingto compute the p-value and test statistic. Also, suggest the corrective actions that should be taken, if required.

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To perform:The hypothesis testingto compute the p-value and test statistic. Also, suggest the corrective actions that should be taken, if required.

Chapter 9 Solutions