Introduction To Quantum Mechanics
3rd Edition
ISBN: 9781107189638
Author: Griffiths, David J., Schroeter, Darrell F.
Publisher: Cambridge University Press
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Question
Chapter 9, Problem 9.15P
To determine
The allowed energies of a particle in the logarithmic potential
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Check out a sample textbook solutionStudents have asked these similar questions
Consider the "step" potential:
V(x) =
(a) Calculate the reflection coefficient, for the case E 0.
(b) Calculate the reflection coefficient for the case E > Vo.
(c) For a potential such as this, which does not go back to zero to the right of
the barrier, the transmission coefficient is not simply |F12/A2 (with A the
-Vo
AV(x)
Scattering from a "cliff"
incident amplitude and F the transmitted amplitude), because the transmitted
wave travels at a different speed. Show that
T =
E-Vo F1²
E |A|²
X
for E> Vo. Hint: You can figure it out using Equation
gantly, but less informatively-from the probability current (
What is T, for E Vo, calculate the transmission coefficient for the step potential, and
check that T + R = 1.
A triangle in the xy plane is defined with
corners at (x, y) = (0,0), (0, 2) and
(4, 2). We want to integrate some
function f(x, y) over the interior of this
triangle.
Choosing dx as the inner integral, the
required expression to integrate is given
by:
Select one:
o Sro S-o f(x, y) dx dy
x=0
2y
y=0
O S-o So F(x, y) dæ dy
O o S f(x, y) dy dæ
O So So F(x, y) dx dy
x/2
=0
Problem 7. 1. Calculate the energy of a particle subject to the potential V(x) =
Vo + câ?/2 if the particle is in the third excited state.
2. Calculate the energy eigenvalues for a particle moving in the potential V(x) =
câ2/2+ bx.
%3!
Chapter 9 Solutions
Introduction To Quantum Mechanics
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Similar questions
- Problem 3.36. Consider an Einstein solid for which both N and q are much greater than 1. Think of each oscillator as a separate "particle." (a) Show that the chemical potential is N+ - kT ln N (b) Discuss this result in the limits N > q and N « q, concentrating on the question of how much S increases when another particle carrying no energy is added to the system. Does the formula make intuitive sense?arrow_forwardThis is the solution to problem 7.36 . Could you explain the yellow marked place ? How we got <0|y|1> and <x^2>0 ?arrow_forwardCalculate the values of ⟨x3⟩v and ⟨x4⟩v for a harmonic oscillator by using the properties of the Hermite polynomials given in Table 7E.1; follow the approach used in the text.arrow_forward
- Question 2 2.1 Consider an infinite well for which the bottom is not flat, as sketched here. If the slope is small, the potential V = 6 |x|/ a may be considered as a perturbation on the square- well potential over -a/2 ≤x≤a/2. -8 W V(x) a/2 -a/2 X Calculate the ground-state energy, correct to first order in perturbation theory. Given (0) = √²/co COS Ground state of box of size a: = Ground state energy: E(0) = 4²k² 2ma². 0 Yarrow_forwardProblem #1 (Problem 5.3 in book). Come up with a function for A (the Helmholtz free energy) and derive the differential form that reveals A as a potential: dA < -SdT – pdV [Eqn 5.20]arrow_forwardA charged particle is bound to a harmonic oscillator potential 1ky2 kx?. The system is placed in an external electric field E that is constant in space and time. Calculate the change in energy from the ground state to second order. Hint: Consider the electric field in the X direction.arrow_forward
- PROBLEM 2. Consider a spherical potential well of radius R and depth Uo, so that the potential is U(r) = -Uo at r R. Calculate the minimum value of Uc for which the well can trap a particle with l = 0. This means that SE at Uo > Uc has at least one bound ground state at l = 0 and E < 0. At Ug = Uc the bound state disappears.arrow_forwardFor each positive integer n, define the set A, (2 (2n – 1): ieZ>o}. (a) Prove that P = {A1.A2,.. is a partition of the set Zo of positive integers.arrow_forwardWrite down the equations and the associated boundary conditions for solving particle in a 1-D box of dimension L with a finite potential well, i.e., the potential energy U is zero inside the box, but finite outside the box. Specifically, U = U₁ for x L. Assuming that particle's energy E is less than U, what form do the solutions take? Without solving the problem (feel free to give it a try though), qualitatively compare with the case with infinitely hard walls by sketching the differences in wave functions and probability densities and describing the changes in particle momenta and energy levels (e.g., increasing or decreasing and why), for a given quantum number.arrow_forward
- Show that a gaussian psi (x) = e ^(-ax^2) can be an eigenfunction of H(hat) for harmonic oscillator 1. Compute T(hat)*psi 2. Compute Vhat* psi - assume V operator is 1/2w^2x^2 3. Write out Hbar*psi and identify terms so Hber*psi=E*psi is true 4. From cancellation find a 5. insert back a to Schrodinger eq above and find Earrow_forwardFind A and B so that f(x, y) = x2 + Ax + y? + B has a local minimum at the point (4, 0), with z-coordinate 5. A = B =arrow_forwardwhere and kyk₂ I 2 k 2m E 2 ħ² 2m ħ² (V-E) 3 Show that the solutions for region II can also be written as 2/₁₂ (²) = Ccas (₁₂²) + D sin (k₂²) for Z≤ 1W/ 4 Since the potential well Vez) is symmetrical, the possible eigen functions In You will be symmetrical, so Yn will be either even or odd. a) write down the even solution for region. II b) write down the odd solution region for on II In problem 2, explain why A=G=0₁arrow_forward
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