Chapter 9, Problem 9.18P

A golf ball m = 0.11 kg strikes a vertical concrete wall elastically with a horizontal velocity of v = 23 m/s.  Randomized Variables: m = 0.11 kgv = 23 m/s (a)  Write an expression for the magnitude of the impulse I experienced by the ball.  (b)  If the ball was in contact with the wall for t = .1s, what is the magnitude of the force F the ball experienced in N? (c)  If the ball rebounds with only half the velocity it comes in with, what is the magnitude of the impulse in kg m/s? (d)  Determine the magnitude of the change in kinetic energy in the above situation. Give your answer in joules.

A golf ball of mass m = 0.18 kg is dropped from a height h. It interacts with the floor for t = 0.11 s, and applies a force of F = 17.5 N to the floor when it elastically collides with it. Randomized Variablesm = 0.18 kgt = 0.11 sF= 17.5 N Write an expression for the ball's velocity, v, in terms of the variables m, t, and F, just after it rebounds from the floor. (Hint: The fact that the collision is elastic is important when solving this problem.) What is the magnitude of the ball's velocity v, in meters per second, right after it rebounds? How high h, in meters, will the ball travel on the rebound?

A 64.5 kgkg astronaut is doing a repair in space on the orbiting space station. She throws a 2.35 kgkg tool away from her at 3.60 m/sm/s relative to the space station.   With what speed will she begin to move? Express your answer with the appropriate units.     n what direction will she begin to move? In what direction will she begin to move? She moves in the direction in which she throws the tool. She moves opposite to the direction in which she throws the tool.

How much kinetic energy is lost in the inelastic collisions? Where does it go? Is it still in the “closed system” or has it been lost to surroundings?

A student throws a 120 g snowball at 7.5 m/s at the side of the schoolhouse, where it hits and sticks. What is the magnitude of the average force on the wall if the duration of the collision is 0.15 s?

A car's suspension is modeled by the overdamped oscillator L=(D−1)(D−2)L=(D−1)(D−2).  (a) Find the impulse response of the suspension. (That is, solve Ly=δ(t),y′(0)=y(0)=0Ly=δ(t),y′(0)=y(0)=0.) (b) What happens to the car if the car rolls over three evenly spaced sharp bumps? (That is, solve Ly=δ(t)+δ(t−1)+δ(t−2)Ly=δ(t)+δ(t−1)+δ(t−2).) Hint: convolve with the impulse response.

A student of mass m1= 57 kg stands on a long cart of mass m2=135 kg initially at text. He begins to run in the cart with a speed relative to the ground of v1=3.3 m/s. Randomized Varibles M1= 57 kg M2= 135 Kg V1= 3.3 m/s (A) write an expression for the horizontal component of the carts velocity relative to the ground while the student is running, in terms of the variables given in the problem statement. Assume the student is running in the positive X direction. (B)  what is the velocity in meters per second? (C) what is the horizontal component of the students velocity relative to the cart, in meters per second? Use a coordinate system fixed to the cart which has the same orientation for the X axis as a system fix to the ground we defined in part (a).

Two manned satellites approaching one another, at a relative speed of 0.250 m/s, intending to dock. The first has a mass of 4.00×103kg, and the second a mass of 7.50×103kg. (a) Calculate the final velocity (after docking) by using the frame of reference in which the first satellite was originally at rest. (b) What is the loss of kinetic energy in this inelastic collision? (c) Repeat both parts by using the frame of reference in which the second satellite was originally at rest. Explain why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both.

A rod 2 meters long has a linear density of p(x) = 8 - 3x. How far, in meters, is the center of mass of the rod if measured from the left?