Concept explainers
(a)
Interpretation:
The number of equivalents and milliequivalents in
Concept introduction:
The amount of electrical charge for salts is expressed in the units of equivalents. On dissociation of salt, one equivalent of a salt is equal to the amount of one mole of positive charge or negative charge.
Answer to Problem 9.76E
The number of equivalents and milliequivalents of
Explanation of Solution
The given amount of
Substitute the values of given mass and molar mass in the given formula.
Thus, the number of moles of
On dissociation of
Thus,
Therefore,
For the calculation of milliequivalents the conversion factor is,
For
Thus, the number of milliequivalents of
The number of equivalents and milliequivalents of
(b)
Interpretation:
The number of equivalents and milliequivalents in
Concept introduction:
The amount of electrical charge for salts is expressed in the units of equivalents. On dissociation of salt, one equivalent of a salt is equal to the amount of one mole of positive charge or negative charge.
Answer to Problem 9.76E
The number of equivalents and milliequivalents of
Explanation of Solution
The given amount of
Substitute the values of given mass and molar mass in the given formula.
Thus, the number of moles of
On dissociation of
Thus,
Therefore,
For the calculation of milliequivalents, the conversion factor is,
For
Thus, the number of milliequivalents of
The number of equivalents and milliequivalents of
(c)
Interpretation:
The number of equivalents and milliequivalents in
Concept introduction:
The amount of electrical charge for salts is expressed in the units of equivalents. On dissociation of salt, one equivalent of a salt is equal to the amount of one mole of positive charge or negative charge.
Answer to Problem 9.76E
The number of equivalents and milliequivalents of
Explanation of Solution
The given amount of
Substitute the values of given mass and molar mass in the given formula.
Thus, the number of moles of
On dissociation of
Thus,
Therefore,
For the calculation of milliequivalents the conversion factor is,
For
Thus, the number of milliequivalents of
The number of equivalents and milliequivalents of
(d)
Interpretation:
The number of equivalents and milliequivalents in
Concept introduction:
The amount of electrical charge for salts is expressed in the units of equivalents. On dissociation of salt, one equivalent of a salt is equal to the amount of one mole of positive charge or negative charge.
Answer to Problem 9.76E
The number of equivalents and milliequivalents of
Explanation of Solution
The given amount of
Substitute the values of given mass and molar mass in the given formula.
Thus, the number of moles of
On dissociation of
Thus,
Therefore,
For the calculation of milliequivalents the conversion factor is,
For
Thus, the number of milliequivalents of
The number of equivalents and milliequivalents of
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Chapter 9 Solutions
LMS Integrated OWLv2, 4 terms (24 months) Printed Access Card for Seager/Slabaugh/Hansen’s Chemistry for Today: General, Organic, and Biochemistry, 9th
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- Hydrazine, N2H4, can interact with water in two steps. N2H4(aq) + H2O() N2H5+(aq) + OH(aq) Kb1 = 8.5 107 N2H5+(aq) + H2O() N2H62+(aq) + OH(aq) Kb2 = 8.9 1016 (a) What is the concentration of OH, N2H5+ and N2H62+ in a 0.010M aqueous solution of hydrazine? (b) What is the pH of the 0.010M solution hydrazine?arrow_forward12.17 Which of the following is more likely to precipitate sulfate ions? PbSO4(s) Pb*+(aq) + SO42’(aq) K = 1.8 X IO"8 CaSO4(s) i=i Ca2+(aq) + SO42'(aq) K = 9.1 X 10-6arrow_forwardTwo strategies are also followed when solving for the pH of a base in water. What is the strategy for calculating the pH of a strong base in water? List the strong bases mentioned in the text that should be committed to memory. Why is calculating the pH of Ca(OH)2 solutions a little more difficult than calculating the pH of NaOH solutions? Most bases are weak bases. The presence of what element most commonly results in basic properties for an organic compound? What is present on this element in compounds that allows it to accept a proton? Table 13-3 and Appendix 5 of the text list Kb values for some weak bases. What strategy is used to solve for the pH of a weak base in water? What assumptions are made when solving for the pH of weak base solutions? If the 5% rule fails, how do you calculate the pH of a weak base in water?arrow_forward
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- Determine the molar concentration of each ion present in the solutions that result from each of the following mixture: (Disregard the concentration of H+ and OH- from water and assume that volumes are additive.) (d) 10.8 mL of 0.649 M NaCl and 21.7 mL of 0.177 M Ca(C2H3O2)2arrow_forwardHow many ml of 0.560 M NaOH solution would it take to completely neutralize 280.0 ml of 0.200 M oxalic acid solution? Oxalic acid (H2C2O4) is a diprotic acid. Volume = _________ mlarrow_forwardWhat is the pOH for a solution at 25 °C that has a H3O+ concentration of 6.57 ×10-6 M? A 34.1 % (NH4 )2SO4 (molar mass = 132.1 g mol−1) has a density of 1.15 g mL−1. What is the molarity of this solution? (the answer should be entered with 3 significant figures; do not enter units; give answer in normal notation--examples include 1.23 and 120. and -123 and 123. and 12.3) Determine the boiling point of a solution that contains 78.5 g of compound W (molar mass = 132.5 g mol–1) dissolved in 1088.6 g benzene (C6H6; molar mass = 84.156 g mol–1; Kb = 2.53 °C m–1; boiling point of pure benzene = 80.1 °C). (the answer should be entered with 3 significant figures; do not enter units; give answer in normal notation--examples include 1.23 and 120. and -123 and 123. and 12.3) NEED HELP ASAP NO WORK NEEDEDarrow_forward
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