Principles of Foundation Engineering
9th Edition
ISBN: 9780357684832
Author: Das
Publisher: Cengage Learning US
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Chapter 9, Problem 9.8P
To determine
Find the elastic settlement of the foundation.
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Question 1) For a shallow foundation measuring (1.7 m x 2.2 m) as shown below: ,
A. Estimate the elastic settlement proposed by Mayerhof. Then,
B. Estimate the elastic settlement proposed by Bowles, if the water table rises 1.5 m. Then,
Use yw=10 kN/m³
qnet= 1.2 MN/m2
G.S
1.5 m
Sand
Yd=16 kN/m³ Ysat= 17 kN/m3
%3D
2.5 m
N60=52
V W.T.
Silty Sand Ya=18 kN/m³ Ysat = 18.5 kN/m?
N60=52
3.5 m
Sand
Ya=19 kN/m3
Ysat = 22 kN/m³
e, = 0.4, Ae=0.04 , o'= 194 kN/m2
5 m
Cc= 0.3, Cs= 0.2 , Ca= 0.05 N60=60
CS Scanned with CamScanner
Q3c. The soil profile at a new construction site for a shallow foundation is shown in Figure Q3.
Prior to construction, a uniformly distributed load of 120 kN/m² is applied to the surface of
the soil. By using C, equal to 0.133C.
Sand
Y = 14 kN/m?
3m
Ground water table
3m
Ysat = 18 kN/m
Sand
Ysat = 19 kN/m?
Void ratio e = 0.8
3m
Clay
LL = 40
Sand
Figure Q3
(i)
Calculate the settlement of the clay layer caused by primary consolidation if the clay is
normally consolidated.
(ii)
Calculate the settlement of the clay layer caused by primary consolidation if the
preconsolidation pressure (o'.) = 170 kN/m².
A rigid shallow foundation 1 m 1 m in plan is shown in Figure below. Calculate the elastic settlement at the center
of the foundation.
Ag = 200 kN/m2
1 m
1m x1 m
E, (kN/m²)|
+ 8000
Hy = 0.3
2
+ 6000 -
3
+ 10,000
6/3/2021
ECG 4313 FOUNDATION DESIGN
Chapter 9 Solutions
Principles of Foundation Engineering
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Similar questions
- Example 5.7 Consider a rectangular foundation 2 mx 4 m in plan at a depth of 1.2 m in a sand deposit, as shown in Figure 5.23a. Given: y = 17.5 kN/m³; ā = 145 kN/m², and the following approximated variation of qc with z: 1.2 m q=145 kN/m² ++++y=17.5 kN/m³ z (m) 9c (kN/m²) B=2m- 0-0.5 2250 L=4 m 0.5-2.5 3430 2.5-5.0 2950 Estimate the elastic settlement of the foundation using the strain influence factor method.arrow_forwardRefer to Figure 7.1. A flexible foundation measuring 1.5 m x 3 m is supported by a saturated clay. Given: Df = 1.2 m, H = 3 m, Es (clay) = 600 kN/m2, and qo = 150 kN/m2. Determine the average elastic settlement of the foundation.arrow_forwardRefer to Figure 5.2 and consider a rectangular foundation. Given: B = 1.5 m, L = 2.5 m, Df = 1.2 m, H = 0.9 m, Φ' = 40º, c' = 0, and γ = 17 kN/m3. Using a factor of safety of 3, determine the gross allowable load the foundation can carry. Use Eq. (5.3).arrow_forward
- ELABORATE Try solving the following problem: Practice Problem: A rigid foundation is subjected to a vertical column load, P = 550 kN, as shown in Figure 4.9. Estimate the elastic settlement due to the net applied pressure, Ao, at the center of the foundation. Given: B = 2 m; L = 3 m; Df = 1.5 m; H = 5 m; Es = 13,500 kN/m²; and μs = 0.5. SAP Foundation BXL D Soil H, Poisson's ratio. E₂ -modulus of elasticity H Rock Figure 4.9 Ag Cengage Leaming 2014arrow_forwardFor the rigid shallow foundation (2*4m) shown in Fig, calculate Immediate settlement the center of the foundation if . (net pressure qo = 100 kPa. Assume 0.3 X 2 m 0.5 m 3.5 m W.T Q=2000 kN 6 m-3 m y=22 kN/m² Ce=0.805 C₁ = 0.3 e=0.753 OCR = 1.4 G. s Dense Sand Y = 22 kN/m³ Silty Clay Silty Sand Y = 18 kN/m²arrow_forwardA rigid foundation is subjected to a vertical column load, P = 355 kN, as shown in Figure 1. Estimate the elastic settlement due to the net applied pressure, Ao, on the foundation. Given: B = 2m; L= 3m; Df=1.5m; H = 4m; Es = 13,500 kN/m²; and µs = 0.4. P Foundation Ao. B× L Soil µ = Poisson's ratio E, modulus of elasticity: H Rockarrow_forward
- 10. A flexible foundation is subjected to a uniformly distributed load of q-500 kN/m². Table 3 could be useful. Determine the increase in vertical stress, in kPa, Aoz at a depth of z=3m under point F. B 4m 3m 6m E 10m Table 10.3 Variation of I, with m and n m 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 0.1 0.0047 0.0092 0.0270 0.0279 0.2 0.0132 0.0092 0.0179 0.0259 0.0132 0.0259 0.0374 0.0222 0.0242 0.0435 0.0474 0.0629 0.0686 0.0258 0.0504 0.0528 0.0547 0.3 0.0731 0.0766 0.0794 0.4 0.1013 0.5 0.0198 0.0387 0.1202 0.6 0.0222 0.0435 0.7 0.0242 0.0474 0.0947 0.1069 0.1168 0.1247 0.1311 0.1361 0.1365 0.1436 0.1491 0.1537 0.1598 0.0168 0.0198 0.0328 0.0387 0.0474 0.0559 0.0168 0.0328 0.0474 0.0602 0.0711 0.0801 0.0873 0.0931 0.0977 0.0559 0.0711 0.0840 0.0947 0.1034 0.1104 0.1158 0.0629 0.0801 0.0686 0.0873 0.1034 0.8 0.0258 0.0504 0.0731 0.0931 0.1104 0.9 0.0270 0.0528 0.0766 0.0977 0.1158 0.0794 0.1013 0.1202 0.0832 0.1263 1.4 0.1300 1.6 0.0306 0.0599 0.0871 0.1114 0.1324 1.8 0.0309 0.0606…arrow_forwardProblem 1: For the data shown below (figure of problem. 1) for shallow foundation, determine the elastic settlement of the foundation. using the improved equation? DE1.0m 9-210 kN/m Er = 15x 10° kN/m2 t=0.23 B-1.0m L=2.0m H=2.0m Silty sand layer As = 0.4 E, = 9000 kN/m2 k = 500 kN/m²/m Rigid layer Figure problem 1.arrow_forwardProblem 1. A column foundation (Figure below) is 3 m × 2 m in plan. The load on the column, including the weight of the foundation is 4500 kN. Determin the average vertical stress increase 4 m beneath the corner of the foundation in the soil layer due to the foundation loading by: a) Boussinesq equations b) 2:1 method Given: Df = 1.5 m, Ø'= 25°, c'= 70 kN/m². 1.5 m 1 m 3m x 2m y = 17 kN/m³ Water level Ysat 19.5 kN/m³arrow_forward
- 3 Given: T- shape foundation as shown in figure is loaded with a uniform load of 120 kN/m². Required: the increment in vertical stress at point (P) at a depth of 5m. 0.6 0.6 0.6 0.6 3m m n I, 1.5 0.3 0.0629 1.2 0.1431 9m 3m 0.1069arrow_forwardRefer to Figure 5.12. For a rectangular foundation on layered sand, given:●● B = 4 ft, L = 6 ft, H = 2 ft, Df = 3 ft●● γ1 = 98 lb/ft3, Φ'1 = 30º, c'1 = 0●● γ2 = 108 lb/ft3, Φ'2 = 38º, c'2 = 0Using a factor of safety of 4, determine the gross allowable load the foundation can carry.arrow_forward|A rigid shallow foundation 1m x 1m in plan is shown in the following figure. Calculate the elastic settlement at the center and corner of the foundation. Ao = 200 kN/m2 1 m 1 m X 1 m E, (kN/m?) + 8000 Hy = 0.3 + 6000 3 10,000 Rock (m).arrow_forward
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