Chapter 9, Problem 9PEB

(a)

To determine

The type of the reaction ${\text{ZnCO}}_3\left(s\right)\to \text{ZnO}\left(s\right)+{\text{CO}}_2\uparrow$.

Answer to Problem 9PEB

The reaction ${\text{ZnCO}}_3\left(s\right)\to \text{ZnO}\left(s\right)+{\text{CO}}_2\uparrow$ is a decomposition reaction.

Explanation of Solution

In reaction ${\text{ZnCO}}_3\left(s\right)\to \text{ZnO}\left(s\right)+{\text{CO}}_2\uparrow$, one molecule of ${\text{ZnCO}}_3$ decompose into molecules of $\text{ZnO}$ and ${\text{CO}}_2$. The reaction is a decomposition reaction.

(b)

To determine

The type of the reaction $2\text{NaBr}\left(aq\right)+{\text{Cl}}_2\left(g\right)\to 2\text{NaCl}\left(aq\right)+{\text{Br}}_2\left(g\right)$.

Answer to Problem 9PEB

The reaction $2\text{NaBr}\left(aq\right)+{\text{Cl}}_2\left(g\right)\to 2\text{NaCl}\left(aq\right)+{\text{Br}}_2\left(g\right)$ is a replacement reaction.

Explanation of Solution

In reaction $2\text{NaBr}\left(aq\right)+{\text{Cl}}_2\left(g\right)\to 2\text{NaCl}\left(aq\right)+{\text{Br}}_2\left(g\right)$, the bromine is replaced by the chlorine. The reaction is a replacement reaction.

(c)

To determine

The type of the reaction $2\text{Al}\left(s\right)+3{\text{Cl}}_2\left(g\right)\to 2{\text{AlCl}}_3\left(s\right)$.

Answer to Problem 9PEB

The reaction $2\text{Al}\left(s\right)+3{\text{Cl}}_2\left(g\right)\to 2{\text{AlCl}}_3\left(s\right)$ is a combination reaction.

Explanation of Solution

In reaction $2\text{Al}\left(s\right)+3{\text{Cl}}_2\left(g\right)\to 2{\text{AlCl}}_3\left(s\right)$, aluminum and chlorine combine to form ${\text{AlCl}}_3$. The reaction is a combination reaction.

(d)

To determine

The type of the reaction $\text{Ca}{\left(\text{OH}\right)}_2\left(aq\right){\text{+H}}_2{\text{SO}}_4\left(aq\right)\to {\text{CaSO}}_4\left(aq\right)+{\text{2H}}_2\text{O}\left(l\right)$.

Answer to Problem 9PEB

The reaction $\text{Ca}{\left(\text{OH}\right)}_2\left(aq\right){\text{+H}}_2{\text{SO}}_4\left(aq\right)\to {\text{CaSO}}_4\left(aq\right)+{\text{2H}}_2\text{O}\left(l\right)$ is an ion exchange reaction.

Explanation of Solution

In reaction $\text{Ca}{\left(\text{OH}\right)}_2\left(aq\right){\text{+H}}_2{\text{SO}}_4\left(aq\right)\to {\text{CaSO}}_4\left(aq\right)+{\text{2H}}_2\text{O}\left(l\right)$, ions of $\text{Ca}{\left(\text{OH}\right)}_2$ interact with the ions of ${\text{H}}_2{\text{SO}}_4$, forming ${\text{CaSO}}_4$ that comes out of solution The reaction is an ion exchange reaction.

(e)

To determine

The type of the reaction $\text{Pb}{\left({\text{NO}}_3\right)}_2\left(aq\right){\text{+H}}_2\text{S}\left(g\right)\to 2{\text{HNO}}_3\left(aq\right)+\text{PbS}\downarrow$.

Answer to Problem 9PEB

The reaction $\text{Pb}{\left({\text{NO}}_3\right)}_2\left(aq\right){\text{+H}}_2\text{S}\left(g\right)\to 2{\text{HNO}}_3\left(aq\right)+\text{PbS}\downarrow$ is an ion exchange reaction.

Explanation of Solution

In reaction $\text{Pb}{\left({\text{NO}}_3\right)}_2\left(aq\right){\text{+H}}_2\text{S}\left(g\right)\to 2{\text{HNO}}_3\left(aq\right)+\text{PbS}\downarrow$, ions of $\text{Pb}{\left({\text{NO}}_3\right)}_2$ interact with the ions of ${\text{H}}_2\text{S}$, forming $\text{PbS}$ that comes out of solution. The reaction is an ion exchange reaction.

(f)

To determine

The type of the reaction $\text{C}\left(s\right)+\text{ZnO}\left(s\right)\to \text{Zn}\left(s\right)+\text{CO}\uparrow$.

Answer to Problem 9PEB

The reaction $\text{C}\left(s\right)+\text{ZnO}\left(s\right)\to \text{Zn}\left(s\right)+\text{CO}\uparrow$ is a replacement reaction.

Explanation of Solution

In reaction $\text{C}\left(s\right)+\text{ZnO}\left(s\right)\to \text{Zn}\left(s\right)+\text{CO}\uparrow$, replacement takes place. The reaction is a replacement reaction.