# Solve Exercises 27-30 graphically: The sum of two resistances is 14 Ω . Their difference is 6 Ω . Find the two resistances. If we let R 1 and R 2 be the two resistances, the equation is R 1 + R 2 = 14 R 1 − R 2 = 6

### Elementary Technical Mathematics

12th Edition
Dale Ewen
Publisher: Cengage Learning
ISBN: 9781337630580

Chapter
Section

### Elementary Technical Mathematics

12th Edition
Dale Ewen
Publisher: Cengage Learning
ISBN: 9781337630580
Chapter 9.1, Problem 27E
Textbook Problem
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## Solve Exercises 27-30 graphically:The sum of two resistances is 14 Ω . Their difference is 6 Ω . Find the two resistances. If we let R 1 and R 2 be the two resistances, the equation is R 1 + R 2 = 14 R 1 − R 2 = 6

To determine

To calculate: The value of two resistances R1 and R2 whose sum is 14Ω and the difference is 6Ω.

### Explanation of Solution

Given Information:

The provided equations are,

R1+R2=14,R1R2=6

Calculation:

Consider the provided equations,

R1+R2=14 ...... (1)

And,

R1R2=6 ...... (2)

Solve the equation (1) for R2,

R2=14R1 ...... (3)

Find three solutions for the equation R2=14R1,

R1R2=14R1R24144106146881486

The solutions for the first equation in the form of (R1,R2) are (4,10),(6,8),(8,6).

Plot these three points on the graph and connect them with a line as follows,

Now, solve the second equation for R2,

R1R2=6R2=6R1

Or,

R2=R16 .....

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