Chapter 9.1, Problem 2GP

To determine

To find: The distance travelled by the golf ball on Sharon’s first hit.

Answer to Problem 2GP

The distance travelled by the golf ball on Sharon’s first hit is $10.77$ feet.

Explanation of Solution

Given:

The given coordinates are:

  $\begin{array}{l}\left(-3,12\right)\\ \left(1,2\right)\end{array}$

Model the situation. If the basket is at $\left(0,0\right)$ , then the location of the disc is $\left(-3,12\right)$ . The location after the first put is $\left(1,2\right)$ .

The distance between each pair of points with the given coordinates is given as:

  $d=\sqrt{{\left(x_2-x_1\right)}^2+{\left(y_2-y_1\right)}^2}$

The distance is calculated as:

  $\begin{array}{c}d=\sqrt{{\left(1-\left(-3\right)\right)}^2+{\left(2-12\right)}^2}\\ =\sqrt{{\left(4\right)}^2+{\left(-10\right)}^2}\\ =\sqrt{116}\\ =10.77\end{array}$

Therefore the distance is $10.77$ feet.