Explanation Given: ‖ 2 ( i − j + k ) − 3 ( 2 i + j − k ) ‖ 2 Concept Used: A scalar k is multiplied with a vector v = x i + y j + z k as: k ( x i + y j + z k ) = ( k x ) i + ( k y ) j + ( k z ) k Difference of two vectors v = x 1 i + y 1 j + z 1 k and w = x 2 i + y 2 j + z 2 k : v − w = ( x 1 − x 2 ) i + ( y 1 − y 2 ) j + ( z 1 − z 2 ) k Magnitude of a vector v = x i + y j + z k is: ‖ x i + y j + z k ‖ = x 2 + y 2 + z 2 Calculation: To evaluate ‖ 2 ( i − j + k ) − 3 ( 2 i + j − k ) ‖ 2

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

6th Edition

ISBN: 9781524908102

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 9.3, Problem 22PS

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To evaluate ‖2(i−j+k)−3(2i+j−k)‖2 .

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Chapter 9.3, Problem 21PS

Chapter 9.3, Problem 23PS

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Chapter 9 Solutions

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

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To evaluate ‖ 2 ( i − j + k ) − 3 ( 2 i + j − k ) ‖ 2 .

Solution Summary: The author explains how the scalar k is multiplied with a vector v=xi+y

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To evaluate ‖2(i−j+k)−3(2i+j−k)‖2 .

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Chapter 9 Solutions