Explanation Given Information: The probability distribution function is, f ( x ) = 4 3 − 2 3 x where interval is [ 0 , 1 ] . Formula used: The formula to find the mean of probability distribution function is: μ = ∫ a b x f ( x ) d x where, μ is mean or expected value of probability distribution function f ( x ) , [ a , b ] is given interval. The formula to find the median, for probability distribution function f ( x ) is median of x is number m such that ∫ a m f ( x ) d x = 0.5 . Calculation: Consider the given equation, f ( x ) = 4 3 − 2 3 x ; x ∈ [ 0 , 1 ] Consider the primary equation to find mean μ = ∫ a b x f ( x ) d x Now substitute 4 3 − 2 3 x for f ( x ) and interval [ a , b ] ≡ [ 0 , 1 ] is primary equation. μ = ∫ 0 1 x [ 4 3 − 2 3 x ] d x = 4 3 [ x 2 ] 0 1 2 − 2 3 [ x 2 ] 0 1 3 = 2 3 [ 1 2 − 0 ] − 2 9 [ 1 − 0 ] = 2 3 − 2 9 Solve further, μ = ∫ 0 1 x [ 4 3 − 2 3 x ] d x = 4 9 Substitute 4 3 − 2 3 x for f ( x ) and a = 0 , b = 1 in the given formula

Calculus: An Applied Approach (Providence College: MTH 109)

9th Edition

ISBN: 9781285142616

Author: Ron Larson

Publisher: CENGAGE C

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Definition Definition Probability of occurrence of a continuous random variable within a specified range. When the value of a random variable, Y, is evaluated at a point Y=y, then the probability distribution function gives the probability that Y will take a value less than or equal to y. The probability distribution function formula for random Variable Y following the normal distribution is: F(y) = P (Y ≤ y) The value of probability distribution function for random variable lies between 0 and 1.

Chapter 9.3, Problem 26E

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To calculate: The mean and median of the probability density functions f(x)=43−23x.

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Chapter 9.3, Problem 25E

Chapter 9.3, Problem 27E

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Chapter 9 Solutions

Calculus: An Applied Approach (Providence College: MTH 109)

Ch. 9.1 - Checkpoint 1 Worked-out solution available at...Ch. 9.1 - Prob. 2CP Ch. 9.1 - Prob. 3CP Ch. 9.1 - Prob. 4CP Ch. 9.1 - Prob. 5CP Ch. 9.1 - Prob. 6CP Ch. 9.1 - Prob. 1SWU Ch. 9.1 - Prob. 2SWU Ch. 9.1 - Prob. 3SWU Ch. 9.1 - Prob. 4SWU

Ch. 9.1 - Prob. 5SWU Ch. 9.1 - Prob. 6SWU Ch. 9.1 - Prob. 7SWU Ch. 9.1 - Prob. 8SWU Ch. 9.1 - Prob. 9SWU Ch. 9.1 - Prob. 10SWU Ch. 9.1 - Prob. 1E Ch. 9.1 - Prob. 2E Ch. 9.1 - Prob. 3E Ch. 9.1 - Prob. 4E Ch. 9.1 - Prob. 5E Ch. 9.1 - Prob. 6E Ch. 9.1 - Prob. 7E Ch. 9.1 - Random Selection A card is chosen at random from a...Ch. 9.1 - Prob. 9E Ch. 9.1 - Prob. 10E Ch. 9.1 - Identifying Probability Distributions In Exercises...Ch. 9.1 - Prob. 12E Ch. 9.1 - Prob. 13E Ch. 9.1 - Prob. 14E Ch. 9.1 - Prob. 15E Ch. 9.1 - Using Probability Distributions In Exercises 1518,...Ch. 9.1 - Prob. 17E Ch. 9.1 - Prob. 18E Ch. 9.1 - Prob. 19E Ch. 9.1 - Children The table shows the probability...Ch. 9.1 - Prob. 21E Ch. 9.1 - Die Roll Consider the experiment of rolling a...Ch. 9.1 - Prob. 23E Ch. 9.1 - Prob. 24E Ch. 9.1 - Prob. 25E Ch. 9.1 - Prob. 26E Ch. 9.1 - Prob. 27E Ch. 9.1 - Prob. 28E Ch. 9.1 - Prob. 29E Ch. 9.1 - Personal Income The probability distribution of...Ch. 9.1 - Insurance An insurance company needs to determine...Ch. 9.1 - 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Prob. 21E Ch. 9.2 - Prob. 22E Ch. 9.2 - Prob. 23E Ch. 9.2 - Prob. 24E Ch. 9.2 - Prob. 25E Ch. 9.2 - Finding a Probability In Exercises 19-26, sketch...Ch. 9.2 - Prob. 27E Ch. 9.2 - Prob. 28E Ch. 9.2 - Prob. 29E Ch. 9.2 - Demand The daily demand for gasoline x (in...Ch. 9.2 - Prob. 31E Ch. 9.2 - Prob. 32E Ch. 9.2 - Using the Exponential Density Function In...Ch. 9.2 - Prob. 34E Ch. 9.2 - Using the Exponential Density Function In...Ch. 9.2 - Prob. 36E Ch. 9.2 - Prob. 37E Ch. 9.2 - Demand The weekly demand x (in tons) for a certain...Ch. 9.2 - Prob. 39E Ch. 9.3 - Prob. 1CP Ch. 9.3 - Find the variance and standard deviation of the...Ch. 9.3 - Use a symbolic integration utility to find the...Ch. 9.3 - Prob. 4CP Ch. 9.3 - Prob. 5CP Ch. 9.3 - Prob. 6CP Ch. 9.3 - Prob. 7CP Ch. 9.3 - Prob. 1SWU Ch. 9.3 - Prob. 2SWU Ch. 9.3 - Prob. 3SWU Ch. 9.3 - Prob. 4SWU Ch. 9.3 - Prob. 5SWU Ch. 9.3 - Prob. 6SWU Ch. 9.3 - Finding Expected Value, Variance, and Standard...Ch. 9.3 - Prob. 2E Ch. 9.3 - Prob. 3E Ch. 9.3 - 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Prob. 38E Ch. 9.3 - Prob. 39E Ch. 9.3 - Prob. 40E Ch. 9.3 - Transportation The arrival time t (in minutes) of...Ch. 9.3 - Prob. 42E Ch. 9.3 - Prob. 43E Ch. 9.3 - Prob. 44E Ch. 9.3 - Prob. 45E Ch. 9.3 - License Renewal The waiting time t (in minutes) at...Ch. 9.3 - Demand The daily demand x for a certain product...Ch. 9.3 - Prob. 48E Ch. 9.3 - Demand The daily demand x for water (in millions...Ch. 9.3 - Prob. 50E Ch. 9.3 - Prob. 54E Ch. 9.3 - Prob. 55E Ch. 9.3 - Education For high school graduates from 2012...Ch. 9.3 - Prob. 57E Ch. 9 - Prob. 1RE Ch. 9 - Prob. 2RE Ch. 9 - Prob. 3RE Ch. 9 - Prob. 4RE Ch. 9 - Prob. 5RE Ch. 9 - Prob. 6RE Ch. 9 - Prob. 7RE Ch. 9 - Prob. 8RE Ch. 9 - Prob. 9RE Ch. 9 - Prob. 10RE Ch. 9 - Prob. 11RE Ch. 9 - Prob. 12RE Ch. 9 - Prob. 13RE Ch. 9 - Prob. 14RE Ch. 9 - Prob. 15RE Ch. 9 - Prob. 16RE Ch. 9 - Revenue A publishing company introduces a new...Ch. 9 - Prob. 18RE Ch. 9 - Prob. 19RE Ch. 9 - Prob. 20RE Ch. 9 - Prob. 21RE Ch. 9 - Prob. 22RE Ch. 9 - Prob. 23RE Ch. 9 - 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The mean and median of the probability density functions f ( x ) = 4 3 − 2 3 x .

Solution Summary: The author explains how to calculate the mean and median of the probability density functions.

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To calculate: The mean and median of the probability density functions f(x)=43−23x.

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Chapter 9 Solutions