Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 9.4, Problem 37PPS

a.

To determine

To write and graph the rational function representing Kristina’s average monthly cost as a function of number of months she uses the phone

a.

Expert Solution
Check Mark

Answer to Problem 37PPS

The rational function that represents Liam’s average cost per customer as a function of number of parking lots is f(x)=50x+4500x and graph for this function is represented

Explanation of Solution

Given information:

Kristina bought a new cell phone cost $150 with internet access.

Her monthly usage charge is $30 plus $10 for the internet access

Asume that the number of months kristina uses her phone as 'x'

Thus, the total cost on usage of cell phone is 150+(30+10)x

This means that the average cost for x usage of cell phone is,

  150+(30+10)xx150+40xx

Therefore, the rational function that represents Kristina’s average monthly cost as a function of the number of months she uses the phone is,

  f(x)=150+40xx

The graph of the function can be represented as,

  Algebra 2, Chapter 9.4, Problem 37PPS

b.

To determine

To find out the asymptotes of the graph

b.

Expert Solution
Check Mark

Answer to Problem 37PPS

The vertical asymptote is x=0

Explanation of Solution

Given information:

Kristina bought a new cell phone cost $150 with internet access.

Her monthly usage charge is $30 plus $10 for the internet access

The rational function that represents Kristina’s average monthly cost as a function of the number of months she uses the phone is,

  f(x)=150+40xx Here, 'x' is the number of months Kristina uses her phone

To find the vertical asymptotes, set the denominator equal to zero

So, put x=0

Therefore, the vertical asymptote is x=0

c.

To determine

To explain why the first quadrant in the graph is the only relevant quadrant

c.

Expert Solution
Check Mark

Answer to Problem 37PPS

The first quadrant in the graph is only relevant because 'x' represents a number of months Kristina uses the phone, thus 'x' is positive number and its value cannot be negative

Explanation of Solution

Given information:

Kristina bought a new cell phone cost $150 with internet access.

Her monthly usage charge is $30 plus $10 for the internet access

At first note that the number of months Kristina uses the phone is 'x' . In part (a) it is determined that the rational function modelling the average monthly cost is,

  f(x)=150+40xx

Therefore, it can be said that only first quadrant is relevant because 'x' represents a number of months Kristina uses the phone, thus 'x' is positive numberand its value cannot be negative

d.

To determine

To find out that after how many months the average monthly charge will be $45

d.

Expert Solution
Check Mark

Answer to Problem 37PPS

The average monthly cost will be $45 after 30 months

Explanation of Solution

Given information:

Kristina bought a new cell phone cost $150 with internet access.

Her monthly usage charge is $30 plus $10 for the internet access

The average monthly cost is given by the function f(x)=150+40xx

To find the number of months it will take for the monthly average cost to be $45, set f(x) to 45

Now the solution for x can be obtained as,

  f(x)=150+40xx45=150+40xxx(45)=150+40x45x40x=1505x=150x=1505x=30

Therefore, the average monthly cost will be $45 after 30 months

Chapter 9 Solutions

Algebra 2

Ch. 9.1 - Prob. 5BCYPCh. 9.1 - Prob. 6ACYPCh. 9.1 - Prob. 6BCYPCh. 9.1 - Prob. 1CYUCh. 9.1 - Prob. 2CYUCh. 9.1 - Prob. 3CYUCh. 9.1 - Prob. 4CYUCh. 9.1 - Prob. 5CYUCh. 9.1 - Prob. 6CYUCh. 9.1 - Prob. 7CYUCh. 9.1 - Prob. 8CYUCh. 9.1 - Prob. 9CYUCh. 9.1 - Prob. 10CYUCh. 9.1 - Prob. 11CYUCh. 9.1 - Prob. 12CYUCh. 9.1 - Prob. 13PPSCh. 9.1 - Prob. 14PPSCh. 9.1 - Prob. 15PPSCh. 9.1 - Prob. 16PPSCh. 9.1 - Prob. 17PPSCh. 9.1 - Prob. 18PPSCh. 9.1 - Prob. 19PPSCh. 9.1 - Prob. 20PPSCh. 9.1 - Prob. 21PPSCh. 9.1 - Prob. 22PPSCh. 9.1 - Prob. 23PPSCh. 9.1 - Prob. 24PPSCh. 9.1 - Prob. 25PPSCh. 9.1 - Prob. 26PPSCh. 9.1 - Prob. 27PPSCh. 9.1 - Prob. 28PPSCh. 9.1 - Prob. 29PPSCh. 9.1 - Prob. 30PPSCh. 9.1 - Prob. 31PPSCh. 9.1 - Prob. 32PPSCh. 9.1 - Prob. 33PPSCh. 9.1 - Prob. 34PPSCh. 9.1 - Prob. 35PPSCh. 9.1 - Prob. 36PPSCh. 9.1 - Prob. 37PPSCh. 9.1 - Prob. 38PPSCh. 9.1 - Prob. 39PPSCh. 9.1 - Prob. 40PPSCh. 9.1 - Prob. 41PPSCh. 9.1 - Prob. 42PPSCh. 9.1 - Prob. 43PPSCh. 9.1 - Prob. 44PPSCh. 9.1 - Prob. 45PPSCh. 9.1 - 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