Chapter 9.5, Problem 79E

a.

To determine

To complete the table.

Answer to Problem 79E

Solutions	Factors	Quadratic equation
3,4	(x-3),(x-4)	$x^2-7x+12=0$
-1,6	(x+1),(x-6)	$x^2-5x-6=0$
0,2	(x),(x-2)	$x^2-2x=0$
-$\frac{1}{2}$,5	(x+ $\frac{1}{2}$),(x-5)	$x^2-\frac{9x}{2}-\frac{5}{2}=0$

Explanation of Solution

Given information:

Solutions	Factors	Quadratic equation
3,4	(x-3),(x-4)	$x^2-7x+12=0$
-1,6
0,2
-$\frac{1}{2}$,5

Formula used: substitution

Calculation:

Solutions	Factors	Quadratic equation
$3,4$	(x-3),(x-4)	$x^2-7x+12=0$
-1,6	(x+1),(x-6)	$x^2-5x-6=0$
0,2	(x),(x-2)	$x^2-2x=0$
-$\frac{1}{2}$,5	(x+ $\frac{1}{2}$),(x-5)	$x^2-\frac{9x}{2}-\frac{5}{2}=0$

b.

To determine

To graph the functions

Explanation of Solution

Given information:

The functions are,

  $x^2-7x+12=0$ ,

  $x^2-5x-6=0$ ,

  $x^2-2x=0$ ,

  $x^2-\frac{9x}{2}-\frac{5}{2}=0$

Calculation:

For $x^2-7x+12=0$ ,

  

Concluding from the graph,

The zeroes are $3,4$

For $x^2-5x-6=0$ ,

  

Concluding from the graph,

The zeroes are $-1,6$

For $x^2-2x=0$ ,

  

Concluding from the graph,

The zeroes are $0,2$

For $x^2-\frac{9x}{2}-\frac{5}{2}=0$ ,

  

Concluding from the graph,

The zeroes are $-0.5,5$