Explanation Given information : The equation of the plane to be sketched is − 4 ( x − 5 ) + 2 ( y + 3 ) + 8 ( z − 4 ) =0 . Method/formula used : The equation of plane that makes interceptsa , b , and c on X-axis, Y-axis, and Z-axis respectively is given by x a + y b + z c =1 . That means the planes passes through points ( a , 0 , 0 ) ( 0 , b , 0 ) , and ( 0 , 0 , c ) . Calculations and Graph: The given plane is − 4 ( x − 5 ) + 2 ( y + 3 ) + 8 ( z − 4 ) =0 ...(1) The given plane passes through point ( 5 , − 3 , 4 ) and the direction ratios of the normal to the plane are - 4, 2, and 8 or - 2, 1, and 4. The equation (1) also can be written as − 4 x + 2 y + 8 z =6 , or − 4 x 6 + 2 y 6 + 8 z 6 =1 , Or x − 1

Student's Solution and Survival Manual for Calculus

7th Edition

ISBN: 9781524934040

Author: STRAUSS MONTY J, TODA MAGDALENA DANIELE, SMITH KARL J

Publisher: Kendall Hunt Publishing

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Chapter 9.6, Problem 10PS

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Tograph:The given plane.

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Chapter 9 Solutions

Student's Solution and Survival Manual for Calculus

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Tograph: The given plane.

Solution Summary: The author explains the equation of the given plane that makes interceptsa, b, and c on X-axis. The equation can be written as -4x+2y+8z

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