Chapter 9.7, Problem 6E

Interpretation Introduction

Interpretation:

Equal-mass mixtures possess a positive or negative excess volume at 20°C has to be determined.

Concept introduction:

The molar volume of a pure substance:

${\underset{\_}{V}}_i=\frac{M_i}{{\rho }_i}$

Here, density of a pure substance is ${\rho }_i$ and molar mass of a pure substance is $M_i$.

The excess volume equal mass mixture:

$V^E=\frac{x_1{M}_1+x_2{M}_2}{{\rho }_m}-x_1{\underset{\_}{V}}_1-x_2{\underset{\_}{V}}_2$

Here, density of the mixture is ${\rho }_m$, mole fraction of components 1 and 2 is $x_1\text{and}{x}_2$,