Chapter A.2, Problem 31AYU

To determine

To find: The volume $V$ and surface area $S$ of a closed rectangular box with length 8 feet, width 4 feet, and height 7 feet.

Answer to Problem 31AYU

$V=224 {\text{ft}}^3$ and $S=232 {\text{ft}}^2$.

Explanation of Solution

Formula Used:

Volume $V=lbh$ and surface area $S=2lh+2wh+2lw$.

Volume of a rectangular box $V=lbh=8\times 4\times 7=224 {\text{ft}}^3$.

Surface area of a rectangular box.

$S=2lh+2wh+2lw=2\times 8\times 7+2\times 4\times 7+2\times 8\times 4=232 {\text{ft}}^2$