WebAssign Printed Access Card for Larson's Calculus: An Applied Approach, 10th Edition, Single-Term
10th Edition
ISBN: 9781337652308
Author: Ron Larson
Publisher: Brooks Cole
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Chapter A5, Problem 36E
To determine
To calculate: The simplified form of the expression
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Check out a sample textbook solutionStudents have asked these similar questions
Use rational exponents to simplify.
(Vab)
14
14
(Simplify your answer.)
(Ya5) “
Make Sense? In Exercises 135–138, determine whether each
statement makes sense or does not make sense, and explain your
reasoning.
135. Knowing the difference between factors and terms is
important: In (3x?y)“, I can distribute the exponent 2 on
each factor, but in (3x² + y)', I cannot do the same thing
on each term.
136. I used the FOIL method to find the product of x + 5 and
x + 2x + 1.
137. Instead of using the formula for the square of a binomial
sum, I prefer to write the binomial sum twice and then
apply the FOIL method.
138. Special-product formulas have patterns that make
their multiplications quicker than using the FOIL
method.
Make Sense? In Exercises 135–138, determine whether each
statement makes sense or does not make sense, and explain your
reasoning.
135. I use the same ideas to multiply (V2 + 5) (V2 + 4) that I
did to find the binomial product (x + 5)(x + 4).
136. I used a special-product formula and simplified as follows:
(V2 + V5)? = 2 + 5 = 7.
137. In some cases when I multiply a square root expression and
its conjugate, the simplified product contains a radical.
138. I use the fact that 1 is the multiplicative identity to both
rationalize denominators and rewrite rational expressions
with a common denominator.
Chapter A5 Solutions
WebAssign Printed Access Card for Larson's Calculus: An Applied Approach, 10th Edition, Single-Term
Ch. A5 - Prob. 1CPCh. A5 - Prob. 2CPCh. A5 - Prob. 3CPCh. A5 - Prob. 4CPCh. A5 - Prob. 5CPCh. A5 - Prob. 6CPCh. A5 - Prob. 7CPCh. A5 - Prob. 1ECh. A5 - Prob. 2ECh. A5 - Prob. 3E
Ch. A5 - Prob. 4ECh. A5 - Prob. 5ECh. A5 - Prob. 6ECh. A5 - Prob. 7ECh. A5 - Prob. 8ECh. A5 - Prob. 9ECh. A5 - Prob. 10ECh. A5 - Prob. 11ECh. A5 - Prob. 12ECh. A5 - Prob. 13ECh. A5 - Prob. 14ECh. A5 - Prob. 15ECh. A5 - Prob. 16ECh. A5 - Prob. 17ECh. A5 - Prob. 18ECh. A5 - Prob. 19ECh. A5 - Prob. 20ECh. A5 - Prob. 21ECh. A5 - Prob. 22ECh. A5 - Prob. 23ECh. A5 - Prob. 24ECh. A5 - Prob. 25ECh. A5 - Prob. 26ECh. A5 - Prob. 27ECh. A5 - Prob. 28ECh. A5 - Prob. 29ECh. A5 - Prob. 30ECh. A5 - Prob. 31ECh. A5 - Prob. 32ECh. A5 - Prob. 33ECh. A5 - Prob. 34ECh. A5 - Prob. 35ECh. A5 - Prob. 36ECh. A5 - Prob. 37ECh. A5 - Prob. 38ECh. A5 - Prob. 39ECh. A5 - Prob. 40ECh. A5 - Prob. 41ECh. A5 - Prob. 42E
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- 3x² - 2x-8 25x² - 100 Simplifurahional expression 4.arrow_forwardSimplify the difference quotient by rationalizing the numerator. Vx + h – 3 - Vx - 3 Read more about Topic 15: Rationalizing the numerator or denominatorarrow_forwardAlgebra 2 Name © 2022 Kuta Software LLC. All rights reserved. Assignment Simplify. Your answer should contain only positive exponents. 2x6y³ 3n 1) 2) 6x y*. 2xy-¹ 3m³n® . 4m*n -3u³v-1 -6u²y6.5v² 2yx³ 2yx3.-6y4 6a *b.6b³ -3x²y-³ -yx-³.4y³ 6ba³ 5u³. u² 3x³y-5 -5x³y+-6x²y6 6x³y² -x²-yx² 2y-2 6x³-4x+y6 -2xx-³ 3) 5) 7) - 9) 11) 4) 10) 12) -4u³v -би -5 Date ID: 1 Periodarrow_forward
- rationalizing the denominator.arrow_forwardWrite 1 · 2 · 3 · 4 · 5 · 6 in factorial notation.arrow_forwardAlgebra 2 Name © 2022 Kuta Software LLC. All rights reserved. Assignment Simplify. Your answer should contain only positive exponents. 3n 2) 3m³n® . 4m*n -3u³v-1 -6u²y6.5v² 2yx² 2yx³.-6y4 -3x²y-3 -yx-³.4y5 6a *b.6b³ 6ba³ 5u³. u² 3x³y-5 -5x³y+-6x²y6 6x³y² -x²-yx² 2y2 6x³-4x+y6 4x6 -2xx-3 3) 5) 7) - 9) 11) 4) 10) 12) 4u³v -5 -6u Date ID: 1 Periodarrow_forward
- In Exercises 106–108, factor and simplify each algebraic expression. 106. 16x + 32r4 107. (x² – 4)(x² + 3) - (r? – 4)°(x² + 3)2 108. 12x+ 6xarrow_forwardUse the technique to rationalize the numerator to the simplify the expressionarrow_forwardExploration In Exercises 91 and 92, find the constant csuch that the denominator will divide evenly into the numerator. x3+4x23x+cx5arrow_forward
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