EBK PRECALCULUS W/LIMITS
EBK PRECALCULUS W/LIMITS
4th Edition
ISBN: 9781337516853
Author: Larson
Publisher: CENGAGE CO
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Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
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Question
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Chapter A.7, Problem 59E

a.

To determine

To verify: y1=y2 analytically.

a.

Expert Solution
Check Mark

Explanation of Solution

Given Information:

   y 1 = x 2 ( 1 3 ) ( x 2 +1) −2/3 (2x)+ ( x 2 +1) 1/3 (2x)y2=2x(4x2+3)3(x2+1)2/3

Calculation:

  y1=x2(13)(x2+1)−2/3(2x)+(x2+1)1/3(2x)

  ⇒y1=23x(x2+1)−2/3[x2+(x2+1)3](Factoring out 23x(x2+1)−2/3 )

  ⇒y1=23x(x2+1)−2/3(x2+3x2+3)

  ⇒y1=2x(4x2+3)3(x2+1)2/3=y2

Hence verified.

b.

To determine

To complete: The given table and to demonstrate the equality in part (a) numerically.

b.

Expert Solution
Check Mark

Answer to Problem 59E

  y−values are same for the given x−values .

Explanation of Solution

Given Information:

   y 1 = x 2 ( 1 3 ) ( x 2 +1) −2/3 (2x)+ ( x 2 +1) 1/3 (2x)y2=2x(4x2+3)3(x2+1)2/3

and an incomplete table is given.

Table:

  x−2−1−1201252y1−8.7−2.9−1.10.02.98.712.5y2−8.7−2.9−1.10.02.98.712.5

Demonstration:

Clearly, y−values are same for the given x−values .

c.

To determine

To verify: The equality in part (a) using a graphing utility.

c.

Expert Solution
Check Mark

Answer to Problem 59E

Equality in part (a) is verified using graph.

Explanation of Solution

Given Information:

   y 1 = x 2 ( 1 3 ) ( x 2 +1) −2/3 (2x)+ ( x 2 +1) 1/3 (2x)y2=2x(4x2+3)3(x2+1)2/3 .

Graph:

  EBK PRECALCULUS W/LIMITS, Chapter A.7, Problem 59E

Interpretation:

Graphs of both y1 and y2 coincide.

Thus, equality in part (a) is verified.

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Chapter A.7, Problem 58E
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Chapter A.7, Problem 60E

Chapter A Solutions

EBK PRECALCULUS W/LIMITS

Ch. A.1 - Prob. 1ECh. A.1 - Prob. 2ECh. A.1 - Prob. 3ECh. A.1 - Prob. 4ECh. A.1 - Prob. 5ECh. A.1 - Prob. 6ECh. A.1 - Prob. 7ECh. A.1 - Prob. 8ECh. A.1 - Prob. 9ECh. A.1 - Prob. 10E
Ch. A.1 - Prob. 11ECh. A.1 - Prob. 12ECh. A.1 - Prob. 13ECh. A.1 - Prob. 14ECh. A.1 - Prob. 15ECh. A.1 - Prob. 16ECh. A.1 - Prob. 17ECh. A.1 - Prob. 18ECh. A.1 - Prob. 19ECh. A.1 - Prob. 20ECh. A.1 - Prob. 21ECh. A.1 - Prob. 22ECh. A.1 - Prob. 23ECh. A.1 - Prob. 24ECh. A.1 - Prob. 25ECh. A.1 - Prob. 26ECh. A.1 - Prob. 27ECh. A.1 - Prob. 28ECh. A.1 - Prob. 29ECh. A.1 - Prob. 30ECh. A.1 - Prob. 31ECh. A.1 - Prob. 32ECh. A.1 - Prob. 33ECh. A.1 - Prob. 34ECh. A.1 - Prob. 35ECh. A.1 - Prob. 36ECh. A.1 - Prob. 37ECh. A.1 - Prob. 38ECh. A.1 - Prob. 39ECh. A.1 - Prob. 40ECh. A.1 - Prob. 41ECh. A.1 - Prob. 42ECh. A.1 - Prob. 43ECh. A.1 - Prob. 44ECh. A.1 - Prob. 45ECh. A.1 - Prob. 46ECh. A.1 - Prob. 47ECh. A.1 - Prob. 48ECh. A.1 - Prob. 49ECh. A.1 - Prob. 50ECh. A.1 - Prob. 51ECh. A.1 - Prob. 52ECh. A.1 - Prob. 53ECh. A.1 - Prob. 54ECh. A.1 - Prob. 55ECh. A.1 - Prob. 56ECh. A.1 - Prob. 57ECh. A.1 - Prob. 58ECh. A.1 - Prob. 59ECh. A.1 - Prob. 60ECh. A.1 - Prob. 61ECh. A.1 - Prob. 62ECh. 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