Whether the viewing rectangle results in a square screen for X min = − 3 X max = 5 X scl = 1 Y min = − 2 Y max = 3 Y scl = 1 . Solution: Yes . The viewing rectangleresults in a square screen. Given information: X min = − 3 X max = 5 X scl = 1 Y min = − 2 Y max = 3 Y scl = 1 Explanation: The selections for X min , X max , Y min , and Y max must be adjusted so that the ratio of x to y must be 8 : 5 , in order to acquire the square screen. X min = − 3 Y min = − 2 X max = 5 Y max = 3 Then, the ratio of x to y is: ⇒ X max − X min Y max − Y min = 5 − ( − 3 ) 3 − ( − 2 ) = 8 5 Therefore, the viewing rectangle results in a square screen.

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Answer 1

Question

Chapter B.5, Problem 7E

To determine

Whether the viewing rectangle results in a square screen for

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1.

Solution:

Yes. The viewing rectangleresults in a square screen.

Given information:

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1

Explanation:

The selections for Xmin , Xmax , Ymin , and Ymax must be adjusted so that the ratio of x to y must be 8:5, in order to acquire the square screen.

Xmin = −3Ymin = −2Xmax = 5 Ymax = 3

Then, the ratio of x to y is:

⇒Xmax−XminYmax−Ymin=5−(−3)3−(−2)=85

Therefore, the viewing rectangle results in a square screen.

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Answer 2

Question

Chapter B.5, Problem 7E

To determine

Whether the viewing rectangle results in a square screen for

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1.

Solution:

Yes. The viewing rectangleresults in a square screen.

Given information:

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1

Explanation:

The selections for Xmin , Xmax , Ymin , and Ymax must be adjusted so that the ratio of x to y must be 8:5, in order to acquire the square screen.

Xmin = −3Ymin = −2Xmax = 5 Ymax = 3

Then, the ratio of x to y is:

⇒Xmax−XminYmax−Ymin=5−(−3)3−(−2)=85

Therefore, the viewing rectangle results in a square screen.

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Answer 3

Question

Chapter B.5, Problem 7E

To determine

Whether the viewing rectangle results in a square screen for

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1.

Solution:

Yes. The viewing rectangleresults in a square screen.

Given information:

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1

Explanation:

The selections for Xmin , Xmax , Ymin , and Ymax must be adjusted so that the ratio of x to y must be 8:5, in order to acquire the square screen.

Xmin = −3Ymin = −2Xmax = 5 Ymax = 3

Then, the ratio of x to y is:

⇒Xmax−XminYmax−Ymin=5−(−3)3−(−2)=85

Therefore, the viewing rectangle results in a square screen.

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Answer 4

Question

Chapter B.5, Problem 7E

To determine

Whether the viewing rectangle results in a square screen for

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1.

Solution:

Yes. The viewing rectangleresults in a square screen.

Given information:

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1

Explanation:

The selections for Xmin , Xmax , Ymin , and Ymax must be adjusted so that the ratio of x to y must be 8:5, in order to acquire the square screen.

Xmin = −3Ymin = −2Xmax = 5 Ymax = 3

Then, the ratio of x to y is:

⇒Xmax−XminYmax−Ymin=5−(−3)3−(−2)=85

Therefore, the viewing rectangle results in a square screen.

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Answer 5

Chapter B.5, Problem 7E

To determine

Whether the viewing rectangle results in a square screen for

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1.

Solution:

Yes. The viewing rectangleresults in a square screen.

Given information:

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1

Explanation:

The selections for Xmin , Xmax , Ymin , and Ymax must be adjusted so that the ratio of x to y must be 8:5, in order to acquire the square screen.

Xmin = −3Ymin = −2Xmax = 5 Ymax = 3

Then, the ratio of x to y is:

⇒Xmax−XminYmax−Ymin=5−(−3)3−(−2)=85

Therefore, the viewing rectangle results in a square screen.

Answer 6

Chapter B.5, Problem 7E

To determine

Whether the viewing rectangle results in a square screen for

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1.

Solution:

Yes. The viewing rectangleresults in a square screen.

Given information:

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1

Explanation:

The selections for Xmin , Xmax , Ymin , and Ymax must be adjusted so that the ratio of x to y must be 8:5, in order to acquire the square screen.

Xmin = −3Ymin = −2Xmax = 5 Ymax = 3

Then, the ratio of x to y is:

⇒Xmax−XminYmax−Ymin=5−(−3)3−(−2)=85

Therefore, the viewing rectangle results in a square screen.

Answer 7

Chapter B.5, Problem 7E

To determine

Whether the viewing rectangle results in a square screen for

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1.

Solution:

Yes. The viewing rectangleresults in a square screen.

Given information:

Xmin = −3Xmax = 5Xscl = 1Ymin = −2Ymax = 3Yscl = 1

Explanation:

The selections for Xmin , Xmax , Ymin , and Ymax must be adjusted so that the ratio of x to y must be 8:5, in order to acquire the square screen.

Xmin = −3Ymin = −2Xmax = 5 Ymax = 3

Then, the ratio of x to y is:

⇒Xmax−XminYmax−Ymin=5−(−3)3−(−2)=85

Therefore, the viewing rectangle results in a square screen.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Solution Summary: The author explains that the viewing rectangle results in a square screen.

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