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3. Refer to the results of Cross 3 (reproduced in the table immediately below) to answer the following questions. No. Prop. Prop. Prop. Cross Mating Between P':'O' Black Black Noéfph:c 7 Choc. Nobzggow Yellow e Pups Pups Pups Pups 3 (z{,‘f;’&;’ %‘l’;’é’k? 51 26 0.510 14 0.275 1 0.216 a. Explain why the expected phenotypic proportions of this cross (see Question 3) differ from the observed proportions of actual puppies born from Cross 3. It's unlikely that the actual numbers of offspring produced of each type would be exactly the same, as the fertilization rate was too small of a specific sample size. b. If Cross 3 resulted in 5000 puppies, rather than 51, do you think the observed and expected values would more or less similar? Explain your answer. Less similar, as there would have been even more possibilities. 4. Assume the parents from Question 3 (Group D), have just one puppy. a. What is the probability that that puppy is a female purebred chocolate lab (bbEE)? (When two purebred parents are mated, the phenotypes of their offspring are always the same as the parents’.) 1/32 (because P(chocolate lab)=1/16 and P(female lab)=1/2) b. Is the “AND” rule or the “OR” rule most useful to answer this question? Explain your answer. “AND" rule, because the lab must be both female and chocolate, not female or chocolate — it is not an either or situation. 5. Can a yellow lab be the parent of a purebred chocolate puppy? Explain why or why not. Yes, because it has a different genotype compared to the offspring — the genotype for a purebred chocolate lab must be either Ee or EE, and a yellow lab only contains the genotype ee.
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pls answer no. 1, 2 and 3 pleaseee. thank u in advance!!
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1_30*_SP23 - General Biology I (for majors
4
I of
evious page
A 1:2:1 genotypic ratio will occur when which of the following crosses is done?
F1
Select one:
O a. GgTt x GgTt
O b.
TTx TT
O c.
tt x tt
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O e.
O f.
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tt x Tt
GGtt x ggTT
GGTT x ggtt
TT x tt
Tt x Tt
F2
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F5
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F6
A
F7
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Last edit was 4 minutes ago
-BI A E E-
Arial Narrow
14
P.
R.
In flies, long wings (W) are dominant to short wings (w). Two homozygous recessive
flies are crossed.
Homozygous
Recessive Fly
Phenotype
Probability (%)
Long Wings:
Short Wings:
In rabbits, black fur (B) is dominant to white fur (b). A purebred (homozygous)
10.
Lioak t rdnAloto hed with a
omalo that has the recessive white fur
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8.
Recessive Fly
Homozygous
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Chapter 10: Dihybrid Cross Worksheet
In rabbits, gray hair is dominant to white hair. Also in rabbits, black eyes are dominant to red eyes. These letters
represent the genotypes of the rabbits:
GG = gray hair
Gg = gray hair
gg = white hair
BB = black eyes
Bb = black eyes
bb = red eyes
1. What are the phenotypes (descriptions) of rabbits that have the following genotypes?
Ggbb
ggbb
GgBb
2. A male rabbit with the genotype GGbb is crossed with a female rabbit with the genotype ggBb the square is
set up below. Fill it out and determine the phenotypes and proportions in the offspring.
Gb
Gb
How many out of 16 have gray fur
and black eyes?
gB
How many out of 16 have gray fur and red
eyes?
gB
How many out of 16 have white fur
and black eyes?
gb
How many out of 16 have white fur
and red eyes
gb
3. A male rabbit with the genotype GgBb is crossed with a female rabbit with the genotype GgBb
The square is set up below. Fill it out and determine the phenotypes and proportions of offspring
GB
Gb
gB…
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9:31 Dh
O N ll 97%
20220331_200252.jpg
Phoblims
84 In Drovphila a chros was made buetween females ell enprening
the 3X- linkage, recuesive thaits, Slut bristus (sc), Scale body (5)
and vermillion eye (v) and wild type males. On the FI, ell
femalis cuere wild type whil all mals enprunid ell the matonttraits.
The Chos was labrid to the F2 generation Ond 1000 offspring
were countid arith resalt shoued beloo:
Phonatype
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D aleulate the Caeffeicint of Coincidence.
62 Femole hutrazygous for ehony le/e), searlit (st"/st)
end spineles sst/ss) were itest chomud ord the following F
praginy wrere olitainid:-
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Scarlt fineles - e st so
Ebony
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6help please answer in text form with proper workings and explanation for each and every part and steps with concept and introduction no AI no copy paste remember answer must be in proper format with all working
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W
O () ENG
9:37 am
O GENBIO-1ST-SEM-MIDTERN X
9 Schoology
G karyotype of a certain huma x
6 BigBlueButton - GNBIO
Messenger
My Questions | bartleby
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A app.schoology.com/common-assessment-delivery/start/5385424680?action=Donresume&submissionld=643190401
The diagram below shows a karyotype of a certain human.
8.
10
11
12
13
14
15
16
17
18
19
21
22
X Y
Based on the karyotype, which of the following statements is most likely true?
O The individual has a genetic condition caused by a nondisjunction event.
The individual has a genetic condition caused by the X and Y chromosomes being different
sizes.
O The individual has a genetic condition caused by a chromosomal duplication.
O The individual has a genetic condition caused chromosomes number one being different sizes.
GENBIO-1ST-SEM-.pdf
O 245180335_56899...jpg
Show all
...
TID N
DAD ×
IDD .
I ID.
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Please answer only question D i.e 4d alone.
Other were answered in my previous post.
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An individual has the following genotype. Gene loci (A) and (B) are 15 m.u. apart. What are the correct frequencies of some of the gametes that car
be made by this individual?
Bl
a
O A. Ab = 7.5%; AB = 42.5%
B. ab = 25%; aB = 50%
O C. AB = 7.5%; aB = 42.5%
O D. aB = 15%; Ab = F0%
E. aB = 70%; Ab = 15%
Reset Selection
OMark for Review What's This?
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Open with -
Mutation: Incomplete Wing Veins
P generation Phenotypes:
Normal
female X
Incomplete
male
Fi generation
Phenotvoe
Females
Males
Total
Ratio
Normal
0.
Incomplete
8.
8.
F, XF, Phenotypes:
Incomplete
Incomplete
female X
male
F2 generation
Phenotvoe
Females
Males
Total
Ratio
Normal
Incomplete
F. Punnett square
FEPunnett square
Pars
399F
OMCO
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Trivla Game Show
_Make Your Own Tri
ngston.schoology.com/common-assessment-delivery/start/4789189591?action=onresume&submissionld=463322566
Dillon WF
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In guinea pigs, black hair (B) is dominant to white hair (b) and rough hair (R) is dominant to smooth hair (r). What are all the possible genotypes of a
guinea pig that has black, rough hair? (Select all that apply.)
O BBRR
BBRr
BBrr
BBRR
BbRr
O bbRR
O bbRr
O bbrr
O Black
O White
O Rough
OSmooth
O Rough
O Smooth
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What is the answer to this question?
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Câu 10
The following chart shows the results of different matings between jimsonweed plants that had either purple or
white flowers and spiny or smooth pods. Determine the dominant allele for the two traits and indicate the
genotypes of the parents for each of the crosses.
Parents
Offspring
Purple White Purple White
Spiny Spiny Smooth Smooth
a. purple spiny x purple spiny
94
32
28
11
b. purple spiny
purple smooth
40
0
38
0
c. purple spiny
white spiny
34
30
0
0
d. purple spiny
white spiny
89
92
31
27
e. purple smooth x purple smooth
0
。
0
36
11
f. white spiny
white spiny
0
45
0
16
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4. please answer this
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inment de x
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Maya Salem-
app.wizer.me/learn/00E0A8
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a
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50% Curly: 50%
Straight
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In humans, wavy hair (CS) results by the incomplete dominant situation of curly hair (C) and
straight hair (S). What are the genotypic ratios of offspring if a curly-haired man and wavy-haired
woman reproduce?
b
50% Curly: 50% Wavy
A Assignment de x
50% CS: 50% SS
Interactive Wo X
Dashboard
C 50% Wavy: 50%
Straight
d
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dominance is this?
Enter class code
50% CC; 50% SS
Go
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A A
EE v E v E E
12
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AaBbCcDdE AaBb
AaBbCcDdEe
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Q4. Assume eye colour in humans is controlled by a pair of alleles of a gene where the allele
giving brown eyes is dominant to the allele giving blue eyes. Both parents of a blue-eyed man,
John, were brown-eyed. He married a brown-eyed woman, Sara, whose father had brown eyes
and mother blue eyes. Sara had a blue-eyed sister. John and Sara had a brown-eyed child.
1) Fill in the boxes and circles on the family tree below to show the genotype of each individual.
John
Sara
Q5. When Mendel crossed a large number of tall pea plants with short pea plants all E1 plants
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both parents are dominant tall name 4 possible offspring
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3
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Please find the attachment
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No. 10 only, thank you?
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Romeo and Juliet Act
X 2 Romeo and Juliet: Sun x
G Esther say upset her a x +
essons/1533886/variants/1533886/take/7/
unnett Squares Practice
* Practice
MULTIPLE CHOICE
In mice, agouti fur color is dominant over albino fur. What is the geno-
type of a homozygous dominant mouse?
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CROSS- RR X IT
RESULTS-
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GENOTYPE- RR IT
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1. To determine the results of this experiment, complete the Punnett squares below by
writing the correct allele(s) in the space provided
P Generation
PHENOTYPE- Round seeds
x Wrinkled seeds
F4
R
1, a
r
Rr
F5
Rr
RR
Rr
RR
R
X
Rr
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Rr
Rr
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IT
IT
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F1
F2
F2
KEY
CROSS-RrxRr
RESULTS
ace provid GENOTYPE
2. hat phenotypes are present in the F₁ generation? What gen'otypes are present?
F7
3. What phenotypes are present in the F2 generation? In what ratio are they present?
PHENOTYPE
4. Does your analysis support or refute Mendel's hypothesis of dominant and recessive
inheritance? Explain.
DII
F8
Title
F9
Aa BbCcDdEe
Focus
Subtitle
E
E
1
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Offspring phenotype
Purple
Terminal
32
38
Question
Purple
Axial
99
112
Cross
White
White
Axial
29
114
Terminal
12
40
1(a)
1(b)
1(c)
1(d)
1(e)
Purple, Axial x Purple, Axial
White, Axial x Purple, Axial
Purple, Terminal x White, Axial
Purple, Terminal x White, Axial
White, Terminal x White,
Terminal
150
155
100
99
101
104
192
a) i) Referring to the data above, determine the genotype both parents for the cross between
"White, Axial x Purple, Axial". Note: P = purple, p = white, A = axial, a = terminal.
11) Referring to the data above, determine the genotype both parents for the cross between
"Purple, Terminal x White, Axial". Note: P = purple, p =white, A = axial, a = terminal
i11) Referring to the data above, determine the genotype both parents for the cross between
"Purple, Terminal x White, Axial". Note: P = purple, p = white, A = axial, a = terminal.
iv) Referring to the data above, determine the genotype both parents for the cross between
"White, Terminal x White, Terminal". Note: P…
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what is the parental genotype: female___ x___ male?
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pls kindly answer no 5,6, and 7
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- How do you solve this problem?arrow_forwardpls answer no. 1, 2 and 3 pleaseee. thank u in advance!!arrow_forward1_30*_SP23 - General Biology I (for majors 4 I of evious page A 1:2:1 genotypic ratio will occur when which of the following crosses is done? F1 Select one: O a. GgTt x GgTt O b. TTx TT O c. tt x tt O d. O e. O f. Og. Oh. Oi. TTx Tt tt x Tt GGtt x ggTT GGTT x ggtt TT x tt Tt x Tt F2 80 F3 F4 F5 MacBook Air F6 A F7arrow_forward
- Is Add-ons Help Last edit was 4 minutes ago -BI A E E- Arial Narrow 14 P. R. In flies, long wings (W) are dominant to short wings (w). Two homozygous recessive flies are crossed. Homozygous Recessive Fly Phenotype Probability (%) Long Wings: Short Wings: In rabbits, black fur (B) is dominant to white fur (b). A purebred (homozygous) 10. Lioak t rdnAloto hed with a omalo that has the recessive white fur %S4 MN 8. Recessive Fly Homozygousarrow_forwardChapter 10: Dihybrid Cross Worksheet In rabbits, gray hair is dominant to white hair. Also in rabbits, black eyes are dominant to red eyes. These letters represent the genotypes of the rabbits: GG = gray hair Gg = gray hair gg = white hair BB = black eyes Bb = black eyes bb = red eyes 1. What are the phenotypes (descriptions) of rabbits that have the following genotypes? Ggbb ggbb GgBb 2. A male rabbit with the genotype GGbb is crossed with a female rabbit with the genotype ggBb the square is set up below. Fill it out and determine the phenotypes and proportions in the offspring. Gb Gb How many out of 16 have gray fur and black eyes? gB How many out of 16 have gray fur and red eyes? gB How many out of 16 have white fur and black eyes? gb How many out of 16 have white fur and red eyes gb 3. A male rabbit with the genotype GgBb is crossed with a female rabbit with the genotype GgBb The square is set up below. Fill it out and determine the phenotypes and proportions of offspring GB Gb gB…arrow_forward9:31 Dh O N ll 97% 20220331_200252.jpg Phoblims 84 In Drovphila a chros was made buetween females ell enprening the 3X- linkage, recuesive thaits, Slut bristus (sc), Scale body (5) and vermillion eye (v) and wild type males. On the FI, ell femalis cuere wild type whil all mals enprunid ell the matonttraits. The Chos was labrid to the F2 generation Ond 1000 offspring were countid arith resalt shoued beloo: Phonatype Se S V Set st yt. Set s v- Sc st v+ Sc st v Sct s vt. s vt. 314 280 156 46 30 10 14 Sc sct st v- To00 Uing the nommelature, detumine genatyps of Pond Fl patnt. D Osder f genes ond mapdistonce. 9 Aru there moto or fuver double crou thon onfectid D aleulate the Caeffeicint of Coincidence. 62 Femole hutrazygous for ehony le/e), searlit (st"/st) end spineles sst/ss) were itest chomud ord the following F praginy wrere olitainid:- Preginy Phenolypt Wild type e st ss - et st ss.- 67 8. 68 347 Spiniless - e st sst Scarlt fineles - e st so Ebony Ebony seorlet- ct set ss Ehgrny…arrow_forward
- 6help please answer in text form with proper workings and explanation for each and every part and steps with concept and introduction no AI no copy paste remember answer must be in proper format with all workingarrow_forwardW O () ENG 9:37 am O GENBIO-1ST-SEM-MIDTERN X 9 Schoology G karyotype of a certain huma x 6 BigBlueButton - GNBIO Messenger My Questions | bartleby + A app.schoology.com/common-assessment-delivery/start/5385424680?action=Donresume&submissionld=643190401 The diagram below shows a karyotype of a certain human. 8. 10 11 12 13 14 15 16 17 18 19 21 22 X Y Based on the karyotype, which of the following statements is most likely true? O The individual has a genetic condition caused by a nondisjunction event. The individual has a genetic condition caused by the X and Y chromosomes being different sizes. O The individual has a genetic condition caused by a chromosomal duplication. O The individual has a genetic condition caused chromosomes number one being different sizes. GENBIO-1ST-SEM-.pdf O 245180335_56899...jpg Show all ... TID N DAD × IDD . I ID.arrow_forwardPlease answer only question D i.e 4d alone. Other were answered in my previous post.arrow_forward
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