Biochem I Problem Set 6a(1) (1)
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Biochemistry I – Problem Set #6a
Answer the following questions briefly
and precisely
The following 6 questions refer to the mechanism of the reaction catalyzed by Chymotrypsin, as
discussed on pages 204-208 in
Lehninger
.
1.
What reaction does the enzyme catalyze?
2.
Assuming an average M.W. of 110 for each amino acid residue, approximately how many
residues would you estimate that Chymotrypsin has? _______
3.
Which residue(s) participate(s) directly in general acid-base catalysis? ____________
(Identify the amino acid and its position; e.g., Cys
107
)
4.
Which residue(s) participate(s) directly in covalent catalysis? ______________
5.
Which residue(s) participate(s) assist in the catalytic process by stabilizing transition states?
______________
6.
Chymotrypsin acts on polypeptides at points adjacent to Phe, Trp and Tyr.
Based on the
structure and function of this enzyme, how do you explain this specificity?
The following two questions refer to hexokinase, discussed on pp. 209-210 of
Lehninger
.
7.
What reaction does this enzyme catalyze?
8.
Water, a much smaller molecule than the normal substrate of this enzyme, can easily enter
and fit into the active site of this enzyme.
Why does this enzyme not readily add phosphate
to water, and which of the 4 factors contributing to binding energy (Refer to lectures, and pp.
182-186 of
Lehninger
) is this an example of?
The following two questions refer to enolase, discussed on p. 210 of
Lehninger
.
9.
Of the 3 general types of catalysis (Refer to lectures, and pp. 186-188 of
Lehninger
), which
is/are involved in the reaction catalyzed by enolase?
10.
What cofactor(s) is/are involved in this reaction?
Biochemistry I, P.S. #6
Page 2
The following two questions refer to HIV protease, discussed on pp. 208-209 of
Lehninger
.
11.
What reaction does this enzyme catalyze?
12.
Name 4 HIV protease inhibitors.
13.
What part of the inhibitors acts as a transition state analog, mimicking an intermediate in the
reaction catalyzed by the protease?
14.
What part of the inhibitors is structurally similar to the site of action of the protease, and thus
helps the inhibitors bind to the active site of the enzyme?
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correct answer should be 20.6 but how?
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Biochemistry topic question:
An enzyme catalyzes a reaction with a with a Km value of 1 × 10–6 M and V max =20mmol/min.
At a concentration of 1 × 10–6 M substrate, the rate of the reaction will be:
See attached image.
Please help. Thank you
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I. Buffer Preparation
A researcher in Biochemistry is isolating α-glucosidase enzyme from malted wheat flour. The protocol requires the use of 2.00L of 0.225 M of lactate buffer with pH of 4.25. How will he/she prepare this buffer from 2.00 M lactic acid solution and solid sodium lactate (NaC3H5O3) The Ka of lactic acid is 1.38 x 10-4. [ Na=23.0, C=12.0, H=1.01, O=16.0 g/mol]
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Quantitative Estimation of Amino Acids by Ninhydrin
http://vlab.amrita.edu/?sub=3&brch=63&sim=156&cnt=2
can u help me with question 2 of the assignment questions
Based on the experimental data provided, estimate the amount of amino acid in the given unknown solution by Ninhydrin method.
SI No.
Volume of standard amino acid solution (ml)
Amount of amino acid (µg)
OD at 570nm
1
Blank
0
2
0.2
0.12
3
0.4
0.25
4
0.6
0.45
5
0.8
0.55
6
1.0
100
0.68
7
Unknown (0.5ml)
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P3D.2 In biological cells, the energy released by the oxidation of foods is
stored in adenosine triphosphate (ATP or ATP“).The essence of ATP's action
is its ability to lose its terminal phosphate group by hydrolysis and to form
adenosine diphosphate (ADP or ADP):
ATP* (aq) + H,O() → ADP* (aq) + HPO (aq) + H,O*(aq)
At pH = 7.0 and 37°C (310K, blood temperature) the enthalpy and
Gibbs energy of hydrolysis are A,H =-20kJ mol and A,G=-31 kJ mol",
respectively. Under these conditions, the hydrolysis of 1 mol ATP“(aq)
results in the extraction of up to 31kJ of energy that can be used to do non-
expansion work, such as the synthesis of proteins from amino acids, muscular
contraction, and the activation of neuronal circuits in our brains. (a) Calculate
and account for the sign of the entropy of hydrolysis of ATP at pH = 7.0 and
310K. (b) Suppose that the radius of a typical biological cell is 10µm and
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41 The following data describe an enzyme-catalyzed reaction (hydrolysis of
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method, and determine values for KM and Vmax
Velocity (mM.sec-)
0 024
0 036
0 053
0 060
0 061
0 062
Substrate Concentration (mM)
25
50
10 0
15 0
200
25 0
42 If the KM of an enzyme for its substrate remains constant as the concentration of the
inhibitor increases, what can be said about the mode of inhibition and why?
43 Calculate the turnover number for an enzyme, assumıng Vmax IS 05 M sec1 and the
concentration of the enzyme used is 0 002 M Why is it useful to know this?
44 Dıscuss the mechanism of the Bohr effect that occurs during the interactions of Hb
with oxygen under physiological conditions in the lungs and tissues Make use of
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Please give four seperate factors in point form. Two similarities and two differences 4 overall.
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Question:
A. To explore the consequences of coupling ATP hydrolysis under physiological conditions to a thermodynamically unfavorable biochemical reaction, consider the hypothetical transformation X⟶Y, for which Δ?′°=20.0 kJ/mol.
What is the ratio of [Y]/[X][Y]/[X] at equilibrium?
B.
Suppose XX and YY participate in a sequence of reactions during which ATP is hydrolyzed to ADP and Pi. The overall reaction is
X+ATP+H2O⟶Y+ADP+Pi
Calculate [Y]/[X] for this reaction at equilibrium. Assume that the temperature is 25.0 °C and the equilibrium concentrations of ATP, ADP, and Pi are 1.00 M each.
C. We know that [ATP], [ADP], and [Pi] are not 1.00 M under physiological conditions. Calculate [Y]/[X] for the ATP‑coupled reaction when the values of [ATP], [ADP], and [Pi] are those found in rat myocytes.
Metabolite Concentration in rat myocytes (M)
ATP 8.05x10-3
ADP 0.93x10-3
Pi 8.05x10-3
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To evaluate inhibitory effects of the selected molecules, 10mM stock solutions of each molecule
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1 pt
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Bb 9146
Bb 1031
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[References]
You do an enzyme kinetic experiment and calculate a Vmax of 118 μmol per minute. If each assay used 0.10 mL of an enzyme solution that had a concentration of 0.20 mg/mL, what would be the
turnover number if the enzyme had a molecular weight of 128,000 g/mol?
(Enter your answer to two significant figures.)
turnover number =
sec-1
D
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D
is the substrate concentration multiplied by the
catalytic constant. KM is equivalent to the
substrate concentration multiplied by the ratio
of rate constants for the formation and
dissociation of the enzyme-substrate complex. KM
is equivalent to the substrate concentration. KM
is equivalent to the substrate concentration
divided by 2
A: KM is equivalent to the substrate
concentration…
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Please help me and explain question 1)
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Vmax = 5 umol min^-1, Km = 2.5 mM?
Vmax = 5 mmol min^-1, Km = 25 M?
Vmax = 5 umol min^-1, Km = 25 mM?
Vmax = 5 mol min^-1, Km = 2.5 mM?
Vmax = 5 mol min^-1, Km = 25 mM?
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