Laboratory Exercise - Pill bug Behavior (1)

Please use the image attached This is For Meal Worm Data:  •  During 2 weeks(14 days) in 6 Celsius temperature from 10 meal worm none shedded and none died • During 2 weeks(14 days) in 26 Celsius temperature 2 meal worms out of 10 shedded and 1 died having only 9 alive   •  During 4 weeks(28 days) in 6 Celsius temperature from 10 meal worms none shedded and none died they are just slow • During 4 weeks(28 days) in 26 Celsius temperature 2 meal worms out of 10 shedded and 1 died having only 9 alive also there was 1 pupae and they got slow because before they were fast    Please please Site your sources for the information you found and Avoid saying: GROW, PROVE, IN THIS EXPERIMENT   Common problems with poorly written lab reports. •Use the abstract to introduce the report instead of to summarize. •Refer to the specimen by common name instead of by scientific name. •Refer to errors that may have occurred without discussing the evidence that those errors actually did occur   Can you…

Please use the image attached This is For Meal Worm Data: • During 2 weeks(14 days) in 6 Celsius temperature from 10 meal worm none shedded and none died • During 2 weeks(14 days) in 26 Celsius temperature 2 meal worms out of 10 shedded and 1 died having only 9 alive • During 4 weeks(28 days) in 6 Celsius temperature from 10 meal worms none shedded and none died they are just slow • During 4 weeks(28 days) in 26 Celsius temperature 2 meal worms out of 10 shedded and 1 died having only 9 alive also there was 1 pupae and they got slow because before they were fast Please please Site your sources for the information you found and Avoid saying: GROW, PROVE, IN THIS EXPERIMENT Common problems with poorly written lab reports. • Use the abstract to introduce the report instead of to summarize. • Refer to the specimen by common name instead of by scientific name. • Refer to errors that may have occurred without discussing the evidence that those errors actually did occur Can you…

What does this figure from the bee paper show? a) Different bees are active at different times of the day b) The bees in the colonies observed were active almost exclusively during the hours of 8 am-midnight c) the bees can detect UV light, allowing them to center their activity at certain times of day d) Bees are more active at dawn and dusk than the other times of day

The following case study is a  paraphrase from "Good Clinical Practice. Standard Operating Procedures for Clinical Researchers" (Kolman, J., Meng, P. and Scott, G. editors; John Wiley and Sons publishers, 1998): “While a study subject and a relative were walking in town one day during the summer, a hanging flower basket fell on a study subjects head, resulting in the study subject falling down and becoming unconscious. The subject’s relative called for an ambulance. On arrival at a local hospital’s Emergency Department, in which the subject regained consciousness but could not recall the event, a x-ray revealed a fractured skull. The subject’s consciousness level at this point was deteriorating and after further tests a subdural hematoma was diagnosed, which was evacuated under general anesthesia. Postoperative recovery was uneventful and progressing well until day four, when the patient developed acute dyspnea (shortness of breath) at rest during visiting time. An emergency lung scan…

What are the analyzed cues based on the recognized cues? Recognized cues given -ICU -The bed is at the lowest setting and locked in place. -The call light is right beside the patient on her right side. -The patient has a telemonitor. -IV pole on the right side of the patient -Sitter at the bedside -No sharp objects near the bed -No bags near the bed -No tubing near patient

Non-specific interactions present a real challenge to co-IP experiments because non-physiological binding to the target complex is likely to occur. Group of answer choices True False

Describe the ways in which human error can be viewed according to Reason (Reason, 2000) and the strategies that can be used to increase resilience according to the Swiss cheese model (Figure 14.6).

If 70% of drunk drivers fail to pass a sobriety test (walking a straight line for 5 meters) in 30 seconds, while only 20% of sober drivers fail to pass this same sobriety test in 30 seconds, then this test has: a specificity of 20%, and a sensitivity of 70% a specificity of 20%, and a sensitivity of 30% a specificity of 30%, and a sensitivity of 80% a specificity of 80%, and a sensitivity of 70% a specificity of 30%, and a sensitivity of 20%

a experiment of Brown Anole Lizard Distribution is conducted to perform my experiment I will choose 4 spots in a park such as a lake, a shaded tree, a boardwalk, and a sidewalk. then to quantify my results I will go three times a day for five weeks and count how many lizards I see in each area.  what would the control would be

False False Pre-Analytical Variables Tests Affected Rationalization Increase Decrease Ex. CK, AST and LD One of the major tissue sources for these enzymes include the muscles. Exercise Fasting Diet Posture and Position Tourniquet Application Tobacco smoking Alcohol Ingestion Stress (Anxiety) Drugs Diurnal Variation

For this experiment, you will be able to manipulate only one variable. First, the amount of water; this means the water in the experimental group is more or less than the control, hopefully not killing the experimental group, but just altering the growth rate of the experimental group compared to the control group. Second the amount of nutrients; nutrients can be varied if you have some plant food or fertilizer at home to use.  Third, simulated herbivory is an interesting variable to use. If used herbivory as your experimental variable, decide on a pattern and amount of herbivory to inflict on the plants of the experimental group and write down the procedure in detail.    Experiment to test how one of the following variables impacts the growth of Brassica rapa: Water, Nutrient Availability, and  Herbivory. 1) Write down just one name of the variable. This is the independent variable. 2) Write down a question to address by manipulating the variable. 3) Next, formulate a hypothesis that…

Consider the effects of the same climate change scenario (+3°C) for a small frog with high cutaneous resistance, Litoria bicolor  and cane toads Rhinella marina . The characteristics of the 3 species are show in the table below. The main differences among these 3 spreadsheets are the body masses and cutaneous resistances. Another difference is that, unlike Litoria caerulea, the other two species are assumed to be outside during the day rather than in a tree hollow. The wind speed inside a hollow is very low, and the humidity is higher. But the air temperatures are the same for all 3 models. Under the climate change scenario, were these 2 species exposed to lethal conditions for either water loss or body temperature?   Species Mass (g) Cutaneous resistance (s/cm) Critical Thermal Maximum Temperature (°C) Litoria caerulea 50 14 37.5 Litoria bicolor 1 63 41.0 Rhinella marina 1, 50 or 500 1.7 37.5

You can choose one or more than one option    The dissociation constant (Kd) of a receptor is:    the concentration of a ligand that produces 100% occupancy of the receptor  the concentration of a ligand that produces 50% of the maximal effect.  the measurement of specificity between ligand and its receptor.  the measurement of speed by which a ligand will dissociate from its receptor.  the measurement of affinity between a ligand and its receptor and the inverse of the association constant.

None

A person wants to know if the Florida Cottonmouth and Northern Cottonmouth differ in toxicity (strength of their venom). Which would be the best experimental design to answer this question?   Question 4 options:   Two snakes - one of each species - each bite a mouse. The mouse that dies more quickly tells you which snake has more toxic venom.   Venom from 60 snakes - 30 of each species - is injected into a mouse. The mouse that dies more quickly tells you which snake has more toxic venom.   Venom from two snakes - one of each species - is injected into a mouse. The mouse that dies more quickly tells you which snake has more toxic venom.   60 snakes - 30 of each species - each bite a mouse. The group of mice with the most deaths tells you which snake has more toxic venom.

Give two possible reasons (hypotheses) why pest control specialists experience fewer fatalities from stinging insects, despite having many more encounters with them.

For your summer research project, you decide to repeat Lillian Tuttle’s (2017) experiment testing the effect of lionfish on other fish that are cleaners and clients. You do this new experiment at a new location (Bonaire), but use basically the same experimental approach and BACI design as Tuttle. a)     You do not separate resident and transient clients (as Tuttle did), and below is a graph of your results showing the effect of the treatment on the total density of client fish in the community. Please explain your result. Imagine that you are planning to publish your experiment and that your answer to this question will be part of the “Results” section of your paper. Please do not worry about hypothetical statistical tests; just assume that the obvious patterns displayed in the graph can be interpreted at face value.

Please help explain this figure

Part A How can an understanding of enzymes and biological receptors guide medicinal chemists? Match the words in the left column to the appropriate blanks in the sentences on the right. Submit an increase will not less more a decrease will Request Answer Reset Help 1. A better understanding of biological processes such as the behavior of enzymes and biological receptors be beneficial for medicinal chemists. Chemists can design drug molecules effectively to resemble biological molecules and their actions. The new medicines and materials can be developed quickly and safely, leading to in both energy usage and cost.

Which of the following are the correct order of steps needed for guard cells to respond to ligth? Select one: O a. Light hits guard cells, guard cells actively pump potassium and chloride out, water follows the ions out(lower water potential), guard cells lose water and open O b. Light hits guard cells, guard cells actively pump potassium and chloride out, water follows the ions out(lower water potential), guard cells lose water and close O c. Light hits guard cells, guard cells actively pump protons out, protons escort chloride ions in, water follows the ions (lower water potential), guard cells become turgid and open O d. Light hits guard cells, guard cells actively pump protons in, water follows the protons (lower water potential and concentration gradient), guard cells become turgid and close

Table 2: DCMU     Time (min) A600 Control "Low" DCMU "High" DCMU 0 1.200 1.300 1.300 2 1.000 1.100 1.300 4 0.730 0.960 1.300 6 0.430 0.850 1.300 8 0.330 0.720 1.300 10 0.310 0.560 1.300 12 0.300 0.520 1.300 The negative control is "high" dcmu. 3. Why do we need this negative control for Part 2?

Please help me with this question within an hour urgently

Briefly do the analysis of the following data and the graph.

Fill up the table

What color should the contents of tubes 3 and 4 be at the end of the experiment? What is the reason for the colors that you predicted in Part A for tubes 3 and 4? Explain your response in terms of the processes responsible for the color changes and the organism(s) involved in each case. If tube 4 was placed in the dark for the duration of the experiment, predict the color of the contents of tube 4 at the end of the experiment. Explain your response.

Octopamine is a neurotransmitter in many species of invertebrates. In foraging bees, octopamine can influence how the bees obtain their food and it can determine their dance behavior, which is used as a form of communication between members of the colony. A study compared the difference in the water and nectar collected by two colonies of foraging bees that were treated with either a dose of octopamine or a control treatment. Which of the following statements identifies the likely outcome of the two colonies? A - Based on the decreased frequency of water foraging done by colony 1, it will have lower amounts of food stored within their hive than colony 2. B - Based on the increased frequency of water foraging done by colony 2, it will have lower amounts of food stored within their hive than colony 1. C - Bees that underwent octopamine treatment in colony 2 would produce greater amounts of food for their hive than those that underwent the treatment in colony 1. D - Bees that were the…

The world is rapidly aging. The challenge of providing a smart living environment for the elderly so as to reduce health hazard and risk, improve quality of living (both physical and mental) and expand their social connectivity is in need of new ideas and technological innovation. Building on what you learned in class about the basics of smart sensor and control, propose the design of a new smart device/application that can improve the safety and quality of living for the elderly on the daily basis. In the proposal, provide the following key points: (1) justification for the particular problem/difficulty for the elderly that you intend to address with your new tech design; (2) the specific design of the new device/application, in particular highlighting the innovative components; (3) the potential technical challenges when realizing the design into actual product; (4) aspects of the design that can be further improved and developed.

You can choose one or more than one option    The dissociation constant (Kd) of a receptor is:  BIOCHEMISTRY basic  the concentration of a ligand that produces 100% occupancy of the receptor  the concentration of a ligand that produces 50% of the maximal effect.  the measurement of specificity between ligand and its receptor.  the measurement of speed by which a ligand will dissociate from its receptor.  the measurement of affinity between a ligand and its receptor and the inverse of the association constant.    During an experiment with Drosophila, it was discovered that all females had red eyes. unlike males. A conclusion based on this observation would be: MOLECULAR BIOLOGY basic  The gene for eye color is located on the X chromosome. The females are homozygotes The gene for eye color is dominant. The eye color results from multigenic linkage. The eye color phenotype is sex-linked    A secondary lysosome: CELL BIOLOGY advanced  a lysosome that provides a backup to the primary…

True or false?  The goal of randomization in RCTs is to make the treatment and control groups similar on all factors except the exposure. True False

Please help me, idk if my answer is correct and I am trying to use this to study!!