Lab 1 Assignment (4)

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St. John's University *

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126

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Biology

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Dec 6, 2023

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BIOLOGY 126 – PHYSIOLOGICAL BASIS OF LIFE LAB 1 – STANDARD CURVE Mark: ______ /32 Section: BIOL-126-001A Due Date: NOTES: 1. Wherever you have a number, you must have a unit associated with that number (an exception is absorbance values, which reflect unit-less ratios). In a table, there is normally a separate heading for each column that includes the units, so the units don’t have to be repeated with each individual value. 2. Absorbance must always be associated with a wavelength (e.g., A 660 ). PART 1 – DILUTION SERIES FOR A COLOURED SOLUTION 1. Fill in the following table. Make sure to add appropriate units to the column headings. (4 marks) Table 1. Absorbance of green coloured solutions at different concentrations. Cuvette Number Volume of green coloured solution Volume of water Green coloured solution concentration in cuvette A 628 ( mL ) ( mL ) ( M ) 1 0 7 0 0 2 0.5 6.5 0.25 0.200 3 1.0 6.0 0.5 0.396 4 1.5 5.5 0.75 0.568 5 2.0 5.0 1.0 0.752 6 2.5 4.5 1.25 0.958 7 3.0 4.0 1.5 1.05 8 3.5 3.5 1.75 1.21 9 4.0 3.0 2 1.58 2. In the space below, show a sample calculation for the concentration of the green coloured solution in Cuvette #4. (2 marks) C 1 V 1 = C 2 V 2 C 2 = 5.25M 7 C 2 = (3.5M)(1.5 mL ) 7mL C 2 = 0.75M C 2 = (3.5M)(1.5) /2 3. Using the green coloured solution concentration and absorbance data from Table 1 above, create a properly formatted standard curve and paste into the space below. Refer back to the formatting Page 1 of 4
BIOLOGY 126 – PHYSIOLOGICAL BASIS OF LIFE LAB 1 – STANDARD CURVE requirements from the Lab Introduction prior to submitting your graph. Also, be sure to add a trendline and include the equation of the line on the graph. (7 marks) 0 0.25 0.5 0.75 1 1.25 1.5 1.75 2 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 f(x) = 0.18 x − 0.17 Figure 1: Change in absorbance of Green Solution when diluted in water Column2 Linear (Column2) Concentration (mL) Absorbance A628 PART 2 – DETERMINING CONCENTRATION OF A COPPER SULPHATE SOLUTION 4. Calculate the molarity of your initial copper sulphate solution. Show your work! (2 marks) m = mass of compound (g) / molecular weight of compound (g/mole) volume of solution (L) m = 1 / 249.7 0.01L m = 0.004m 0.01L m = 0.4 /2 5. Show the calculation for how you prepared 30ml of a 0.1M copper sulphate solution. (1 mark) Page 2 of 4
BIOLOGY 126 – PHYSIOLOGICAL BASIS OF LIFE LAB 1 – STANDARD CURVE V 1 C 1 = V 2 C 2 V 1 = (0.1 M ) (30mL) V 1 = 3mL 0.4M 0.4 V 1 = (0.1) (30mL) V 1 = 7.5mL 0.4 /1 6. Fill in the following table. Make sure to add appropriate units to the columns. (5 marks) Table 2. Absorbance of different concentrations of CuSO 4 solutions. Cuvette number CuSO 4 concentration (M) Volume of CuSO 4 ( mL ) Volume of water ( mL ) A 700 1 0.0 0 5 0 2 0.02 1 4 0.104 3 0.04 2 3 0.235 4 0.06 3 2 0.357 5 0.08 4 1 0.532 6 0.1 5 0 0.671 Unknown 0.39 7. In the space below, show a sample calculation for the concentration of CuSO 4 in Cuvette #2. (2 marks) C 1 V 1 = C 2 V 2 V 1 = (0.02M) (5mL) V 1 = 0.1mL 0.1M 0.1 C 1 = 0.1M V 1 = (0.02) (5mL) V 1 = 1mL V 1 = ? 0.1 C 2 = 0.02M V 2 = 5mL /2 8. Using the CuSO 4 solution concentration and absorbance data from Table 2 above, create a properly formatted standard curve and paste into the space below. Refer back to the formatting requirements Page 3 of 4
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BIOLOGY 126 – PHYSIOLOGICAL BASIS OF LIFE LAB 1 – STANDARD CURVE from the Lab Introduction prior to submitting your graph. Also, be sure to add a trendline and include the equation of the line on the graph. (7 marks) 0 0.02 0.04 0.06 0.08 0.1 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 f(x) = 0.05 x + 0.07 Figure 2: Change in absorbance of Copper Sulphate when diluted in water Series 3 Linear (Series 3) CuSO4 Concentration Absorbance A700 9. Use the equation of the trendline to calculate the concentration of the unknown copper sulphate solution. Show your work and final answer in the space below. (2 marks). Unknown CuSO 4 Absorbance = 0.39 (y) m = 0.136 --------------------------------------------------------------------------------------- y = mx + b 0.39 = 0.136x 0.39 = x 0.136 X = 2.867 /2 Page 4 of 4