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True or False: Chromosomes are in a condensed
form through most of the cell cycle.
false
Match the following each of the following terms
with the correct description
Plasma Membrane.. protects
nuclear membrane.. dissolves
nucleus... contain
er... studded
cytosol.. jelly like
Which of the following is correct
Centrioles are responsible for the formation of spindle fibers.
At which cell cycle phase does the nuclear
membrane break down?
Prophase
The genetic flow of material between organisms is
NOT dependent on which of these criteria?
Independent assortment of the genes
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DNA is condensed within the nucleus (cellular
compartment) by coiling around ____(1)____ proteins.
Modification of these ____(2)____charged proteins
alters them to become either neutral or negatively
charged. Thus, the interaction with ____(3)____charged
DNA is interrupted, and the interactions loosen.
1. histone 2. positively 3. negatively
Interphase marks the period of the cell cycle just
before active cell division. Label the rest of the cell
cycle in order, from 1-5.
1
2
3
4
5
s-phase
prophase
metaphase
anaphase
telophase
Which of the following is true about anaphase?
Chromatids undergo disjunction to travel to opposite poles
A chiasma is a point during meiosis at which the
non-homologous sister chromatids
Intertwine
Which of the following statements is correct?
Incorrect segregation of X and Y chromosomes (for instance, a female with XXX or
X genotype) can produce viable offspring, albeit usually with some problems.
True or false: Linked genes are part of the same
chromosome.
true
Consider genes A, B, and C, which are located on a
chromosome in that order. If genes A and B cross
over 30% of the time, and genes B and C cross over
30% of the time, what is the probability of a double
crossover between A B and C?
(0.3) * (0.3) = 0.09, 9% chance of this crossover
Determination of sex in humans is located on the
_(1)_ chromosome, specifically on the __(2)__ gene.
1. Y
2. SRY
The sex disorder that exhibits an XXY phenotype is
known as ___(1)___. This disorder is found on the __(2)__
sex chromosome
1. Klinefelter syndrome
2. male
Indicate whether each of the following statements
is True or False. 1. G0 is an actively dividing cell
cycle phase. False 2. Cells enter G0 when the
environmental conditions are not ideal for survival.
True 3. Cells in G0 do not undergo active
replication. True 4. When conditions become
normal, cells may go back into the cell cycle. True
false
true
true
true
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Match each of the following terms with the correct
description.
Kinetochore
spindle fibers
centrioloes
metaphase plate
cyclins
flank
made
cytoplasmic
area
blind
kinases
cohesin
histones
shugoshin
phosphorylate
protein complex
hold DNA
protects
A fertilized egg that is the result of fusion of two
gametes is called a ________.
zygote
True or False: The primary male gamete is the
sperm, and the primary female gamete is the
oocyte
true
Which of the following criteria must be met in order
to successfully map genes
Enough offspring should be produced to give a representative sample
True or False: At fertilization, the phenotype of a
male or female is immediately evident.
false
True or False: At fertilization, the phenotype of a
male or female is immediately evident.
G0
The X and Y sex chromosomes are known as _______
chromosomes
Heteromorphic
Why is modification of histone proteins critically
important to DNA transcription?
Modifications of the histone proteins allow for them to either wrap tightly around
DNA or to loosen their grip on DNA. This is very important for transcription
because when histones loosen their grip on DNA, it allows access to the
transcriptional machinery so that DNA can be transcribed. Conversely, when the
histones are tightly wrapped with the DNA, transcription is shut off because the
machinery cannot access the DNA within the space
True or false: The eggs of a female undergo meiosis
I before she is even born, but they undergo meiosis
II after fertilization occurs.
true
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Pointy ears and knobby knees are dominant genes
over round ears and smooth knees. What would be
the result of an F1 cross between one homozygous
parent for pointy ears and knobby knees and one
homozygous for round ears and smooth knees?
What would the F2 cross look like if the F1 was bred
to F1?
If the parents are PPKK x ppkk, then the F1 generation is entirely PpKk and will have
pointy ears and knobby knees. The F2 generation will be as follows: 9:3:3:1- 1 round
ear, smooth knee; 3 round, knobby; 3 pointy, smooth; 9 pointy, knobby
Consider the following 4 independent dominant
traits: short, red, glossy, and tall. Use the product
law to predict the likelihood of inheriting three of
these dominant traits and one recessive trait
3 dominant + 1 recessive = (3/4) (3/4) (3/4) * (1/4) = 27/256
Explain why an individual who is heterozygous for a
genetic disorder may go for a very long time as a
carrier of that disorder without realizing that they
have it?
If an individual is heterozygous for a gene that causes a disorder, the gene that
expresses the normal allele may compensate and produce proteins in enough
quantity that it can function normally. This effect is known as the threshold effect
and essentially can go undetected unless that individual produces offspring that
inherit the recessive gene for the disorder from both individuals. When the
recessive gene from two unaffected individuals are expressed in the offspring,
there is no gene activity produced and the phenotype of the disorder is seen.
The presence of the ABO antigens on the surface
of blood cells is an example of codominance. If a
mother is Type AB (AB) and the father is Type A
(AO), what are the possible combinations for the
child's blood type?
Type A (AA or AO), Type B (BO), Type AB (AB) are all possible.
In the case of determining the likelihood of
inheriting 5 independent alleles, would you use a
Punnett square to make these calculations? If not,
what would you use instead and why?
In determining the likelihood of inheriting 5 independent alleles, you would use the
product law because it will make the calculations much simpler than writing out all
the many possibilities of 5 different traits in an individual.
True or False: A person can only be homozygous or
heterozygous for a given gene.
True
What is the purpose of a testcross, and how is it
done?
A test cross is used to determine whether a plant that is exhibiting a dominant
phenotype is homozygous or heterozygous for that trait. To do a testcross, the
organism with the unknown genotype and dominant phenotype is crossed with a
known homozygous organism.
A homozygous individual will yield all dominant phenotypes whereas a
heterozygous individual will yield a 1:1 mixture of phenotypes.
Let us put the testcross to work. The gene for
yellow flowers is dominant on our favorite plant.
The gene for white flowers is recessive. Our plant
has yellow flowers, but we are unsure of its
genotype. When we crossbreed our unknown with
a plant with white flowers, we get 3 plants with
yellow flowers and 3 plants with white flowers.
What does that tell us about the genotype of the
yellow plant? Draw it out.
If the unknown was YY (homozygous), then YY x yy would yield offspring of Yy, Yy,
Yy, and Yy - all yellow.
If the unknown was Yy (heterozygous), the Yy x yy would yield offspring of Yy, Yy,
yy, and yy - half yellow and half white.
Therefore, our unknown yellow plant must be heterozygous for the yellow gene
(Yy)
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I have been stuck for hours on the final 3 genetic problems at the end of this lab. I really need help. I’ve answered the entire blood typing and genetics section but I’m stuck with this. There are 3 questions. The pheno / Geno chart needs to be applied. I have so many variations on my answer but I can’t sit and type them all in to this box. Please help me.
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9
Which example does not directly support the good gene hypothesis?
peacocks with larger eyespots have babies with higher survival rates
female (peahens) prefer male (peacocks) with long tail feathers
a male peacock with more of eye spots has larger babies
peacocks with more ornaments on their tails were less likely to be eaten by a fox
10 11 12 13
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Wa
FILE
PAGE 3 OF 3
HH
HOME INSERT DESIGN PAGE LAYOUT
198 WORDS
Q
Type here to search
KARYOTYPING ANALYSIS lab activity (1) - Microsoft Word
REVIEW VIEW FOXIT READER PDF
REFERENCES
MAILINGS
3.Cut out the following chromosomes (if you can't have it printed, you may draw them but
please make sure you get the exact size and shape of the chromosome ), arrange them in
pairs, and compare with the normal human karyotype. You can scan your output (or take
pictures) and submit the e copy (comment it below this post ) together with the discussion
on the genetic disorder involved. Discuss your answer briefly.
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Copy of Genetics PUNNETTSX
ELGwRo/edit
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4. The punnett square below shows brown
eyed mom and blue eyed dad.
Complete the punnett square (Double
click the image to complete in Google
Drawing)
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Edio | Calendar X
Edio | Student Da x
days/1089977/lessons/1533969/variants/2439102/take/10/
A Q
TEXT ANSWER
The inheritance patterns for some traits in guinea pigs are listed in the table below.
1. Identify the phenotype of a guinea pig with the genotype HhBBrr.
2. Using the allele symbols in the table, identify the genotype of a guinea pig that is
recessive for hair length, heterozygous for hair color, and homozygous dominant for
hair texture.
Trait
Dominant Allele
Recessive Allele
hair
short (H)
long (h)
length
hair color
black (B)
white (b)
rough (R)
smooth (r)
hair
texture
BIUG X₁ X¹
EEAA
H
Normal
:
√x
Enter your answer here
ŏooooo
Questions Answered
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Ω Ο Τ
Edio | Calendar X
RepostExchange X
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questions below: Aura and Ryan are expecting a child. Aura has dark eyes and
Ryan has light eyes. Aura's mother has light eyes.
Draw a Punnett square and be sure to include the following information for full
credit:
1. Place the parents alleles at the top and on the left side.
2. Write in the allele crosses inside the Punnett squares.
3. Write out the genotypes probabilities for an offspring.
4. Write out the phenotype probabilities for an offspring.
5. What is the probability that Aura and Ryan could have a child with light eyes,
even if light is recessive to dark?
Note: For this question, you will have to go further back into the family tree to
get Aura's genotype.
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TOPIC : Genetics
Example's for Question
GENE = Hair Color
ALLELE = Straight, Curly
DOMINANCE = BB
RECESSIVE = bb
GENOTYPE = BB, Bb, bb
PHENOTYPE = Blue, Black
HOMOZYGOTE = BB (Blue eye), bb (Black eye)
HETEROZYGOTE = Bb (Blue eye)
MONOHYBRID = Aa
DIHYBRID = AaBb
TRIHYBRID = AaBbCc
POLIHYBRID = AaBbCcDd
MENDELLIAN GENETICS = Hair Color
NON MENDELLIA = Blood Type
QUESTIONS:
Give Example of the following fo differentiate, DO NOT GIVE THE MEANING! (Follow the instructions above!)
1. MONOHYBRID CROSS = ?
DIHYBRID CROSS = ?
2. BACK CROSS = ?
TEST CROSS = ?
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Understanding Gregor Mendel Si X
Untitled document - Google Docs X
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rmal text
Roboto
10.5
BIUA
1.
3
Explain why Mendel's experiments demonstrated that parent's traits do not simply blend in the
offspring, but are determined by separate alleles. Provide SPECIFIC evidence to support your
reasoning|
hp
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Edugence -
dugence.com/student/studentformative/
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Juan Bonilla Velasquez > Nimitz 20-21: CA Biology Pros
G.
Question 14
(2014 6E) Sickle-shaped red blood cells result from a mutation in the gene that codes for hemoglobin. This mutation results in sickle-cell anemia. A partial
sequence of bases from a normal hemoglobin gene and a sequence that results in sickle-cell anemia are shown below.
Normal hemoglobin:
T-G-A-G-G-T-C-T-C-C-T-C
Sickle-cell hemoglobin: T-G-A-G-G-T-C-A-C-C-T-C
What type of mutation is depicted in the sequence?
Answer
Substitution
G
Insertion
Deletion
J Frameshift
Question 14
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A mother has a genotype of AaBBCs and father has a gentotype AaBbCc. What is the probability that their offspring is AaBBCc
No copied internet answers just real answers you know that you can help me with by showing work and explanation.
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Directions: Match the word on the left to the correct picture on the right. Write the # in the circle.
Word
Picture
1. Dominant
2. Recessive
3. Trait
4. Punnett Square
Aa
aa
5. Pedigree
a
Aa
aa
6. Gregor Mendel
7. Genotype
8. Phenotype
AaBb
9. Genetics
Father's Genes
10. Heteozygous
G GG Gg
9 Gg g9
B BB
Bb
11. Homozygous
12. Hybrid
bBb
bb
13. Allele
14. Heredity
Crossing between a red rose and a
white rose producing a pink phenotype.
15. Incomplete
Dominance
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0.2 Genetics vocabulary: genotype and phenotype NRK
Questions
answered
In a group of dogs, some individuals have short fur and others have long fur. In this group,
the gene for the fur length trait has two alleles. The allele Fis for short fur, and the allele fis
for long fur.
68
Marley, a dog from this group, has long fur. Marley has two alleles for long fur.
Time
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Based on this information, what is Marley's phenotype for the fur length trait?
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short fur
FF
long fur
Ff
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Genetics Lab Exercise (by Dr. Lapik)
Question 2.
田
BB = black
Analyze the following dihybrid cross:
Bb = black
Parents:
bbLI
bb = white
LL = short hair
U = short hair
Gametes:
U= long hair
Punnett Square:
How many of the offspring are:
Black, Short
Black, Long
White, Short
White, Long
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Tay-Sachs is a recessive genetic disease in humans. If one parent is homozygous normal
(CC)and the other is a carrier (heterozygous-Cc), what are the chances that their child
will have this full-blown disease with symptoms?
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Lab
Introduction:
A dihybrid cross is a cross between individuals that involves two pairs of contrasting traits. To Predict the results of a dihybrid, cross all possible combinations of the four alleles from each parent must be considered.
You will examine a dihybrid cross involving both color and texture. Purple (P), is dominate to yellow (p), and smooth texture (S) is dominant to wrinkled (s). Both parent plants are heterozygous for both traits.
Review genetics and the use of Punnett squares in a biology text before doing this experiment.MATERIALS:
Assume you have ear of Corn.
You need a heterozygous X heterozygous 9:3:3:1, purple/yellow, starchy/sweet.
PROCEDURE:
From above please write out:
The crop
The parental (P) cross phenotype, genotype, gametes
The F1 progeny Genotype and Phenotype
Cross between two F1
Selfed
testcross
The F1 gametes
The expected F2 results, genotype, phenotype, genotypic ratio, phenotypic ratio.
1.…
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- I have been stuck for hours on the final 3 genetic problems at the end of this lab. I really need help. I’ve answered the entire blood typing and genetics section but I’m stuck with this. There are 3 questions. The pheno / Geno chart needs to be applied. I have so many variations on my answer but I can’t sit and type them all in to this box. Please help me.arrow_forwardKindly review my answers on the genotypes part. Please give me the correct answers if incorrect. Thank you.arrow_forwardCan you please help me solve all these questions? Please please?arrow_forward
- >> Remaining Time: 25 minutes, 51 seconds. * Question Completion Status: L Unce started, this test must be completed in one sitting. Do not le Your answers are saved automatically. 20 Question 4 O 4 5 6 7 8 A Moving to another question will save this response. 9 Which example does not directly support the good gene hypothesis? peacocks with larger eyespots have babies with higher survival rates female (peahens) prefer male (peacocks) with long tail feathers a male peacock with more of eye spots has larger babies peacocks with more ornaments on their tails were less likely to be eaten by a fox 10 11 12 13 A Moving to another question will save this response.arrow_forwardWa FILE PAGE 3 OF 3 HH HOME INSERT DESIGN PAGE LAYOUT 198 WORDS Q Type here to search KARYOTYPING ANALYSIS lab activity (1) - Microsoft Word REVIEW VIEW FOXIT READER PDF REFERENCES MAILINGS 3.Cut out the following chromosomes (if you can't have it printed, you may draw them but please make sure you get the exact size and shape of the chromosome ), arrange them in pairs, and compare with the normal human karyotype. You can scan your output (or take pictures) and submit the e copy (comment it below this post ) together with the discussion on the genetic disorder involved. Discuss your answer briefly. 30°C Haze □4) ? Microsoft account 7:49 PM 5/1/2022 95%arrow_forwardCopy of Genetics PUNNETTSX ELGwRo/edit * O 4. The punnett square below shows brown eyed mom and blue eyed dad. Complete the punnett square (Double click the image to complete in Google Drawing) & 7 DELL u B 0 b m * 8 ¡ k O b - 0 MAYA SALEM-Genetics Hyper X + 9 O ) O Sign out р b **** Feb 2 9:17 0 0 US +11 : A } bacarrow_forward
- Please help!arrow_forwardPlease help with this question!arrow_forwardCould you please help me with figuring out the answers to these Genetics practice questions? My professor does not provide the answers and I have done however do not know if I am right. I have two more pictures of problems from where the submitted ones end of.arrow_forward
- Edio | Calendar X Edio | Student Da x days/1089977/lessons/1533969/variants/2439102/take/10/ A Q TEXT ANSWER The inheritance patterns for some traits in guinea pigs are listed in the table below. 1. Identify the phenotype of a guinea pig with the genotype HhBBrr. 2. Using the allele symbols in the table, identify the genotype of a guinea pig that is recessive for hair length, heterozygous for hair color, and homozygous dominant for hair texture. Trait Dominant Allele Recessive Allele hair short (H) long (h) length hair color black (B) white (b) rough (R) smooth (r) hair texture BIUG X₁ X¹ EEAA H Normal : √x Enter your answer here ŏooooo Questions Answered 中山川 Ω Ο Τ Edio | Calendar X RepostExchange X Practice All Changes Saved Continuearrow_forwardquestions below: Aura and Ryan are expecting a child. Aura has dark eyes and Ryan has light eyes. Aura's mother has light eyes. Draw a Punnett square and be sure to include the following information for full credit: 1. Place the parents alleles at the top and on the left side. 2. Write in the allele crosses inside the Punnett squares. 3. Write out the genotypes probabilities for an offspring. 4. Write out the phenotype probabilities for an offspring. 5. What is the probability that Aura and Ryan could have a child with light eyes, even if light is recessive to dark? Note: For this question, you will have to go further back into the family tree to get Aura's genotype.arrow_forwardTOPIC : Genetics Example's for Question GENE = Hair Color ALLELE = Straight, Curly DOMINANCE = BB RECESSIVE = bb GENOTYPE = BB, Bb, bb PHENOTYPE = Blue, Black HOMOZYGOTE = BB (Blue eye), bb (Black eye) HETEROZYGOTE = Bb (Blue eye) MONOHYBRID = Aa DIHYBRID = AaBb TRIHYBRID = AaBbCc POLIHYBRID = AaBbCcDd MENDELLIAN GENETICS = Hair Color NON MENDELLIA = Blood Type QUESTIONS: Give Example of the following fo differentiate, DO NOT GIVE THE MEANING! (Follow the instructions above!) 1. MONOHYBRID CROSS = ? DIHYBRID CROSS = ? 2. BACK CROSS = ? TEST CROSS = ?arrow_forward
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