hw 6

1 17U © Light and Color 5. Complementary colors of light are combinations of two light colors that can be mixed together in equal intensities to produce white light. Thus, the complementary color of ... a. ... red light is cAan light. b. ... greenlightis__ N{(.0 light. c. ... blue light is lJC‘ t)()V\/ light. 6. The Rule of Color Subtraction: An understanding of complementary colors assists in understanding the color appearance of objects when viewed under white light. Whenever an object subtracts a color from white light, it appears as the complementary color. If an object absorbs cyan light, then it will appear as red. Conversely, an object that appears as red is an object that absorbs cyan light. Use these ideas to complete the following statements. When viewed under white light (RGB), a ... a. ... red shirt will absorb n (616 light and reflect I'(d/ light. b. ... green shirt will absorb "'6 light and reflect Qreen light. c. ... blue shirt will absorb w light and reflect ue light. ... cyan shirt will absorb red. light and reflect g_%fl (6F (4 > light. e. .. magenta shirt will absorb _ (‘ izg;n _light and reflcclwgmh ( R *Gl light. f. ... yellow shirt will absorb 'UC light and reflect léfll lOw ‘ Gt8 SIight. g. ... black shirt will absorb &” A o(’_ light and reflect NO light. 7. Express your understanding of complementary colors and the rule of color subtraction by completing the following three diagrams. White light (red-green-blue) is shown incident on a sheet of paper that is painted with a pigment that absorbs one of the primary colors of light. For each diagram, label the color of the two reflected colors and label the color that the paper appears. RG R RKB R B GB 65 N S hY \ A N A Absorbs Blue Absorbs Green Absorbs Red Appears Appears _M%(QEL Appears _(.ygn_ 8. The mathematics of color has little to do with numbers and much to do with the addition and subtraction of colors. The addition of two colors of light results in a new color. Use the color wheel at the right and the concept of complementary colors to complete the following color equations. (W= white; R =red; G =green; B=blue; C=cyan; M =magenta; Y= o yellow) a.R+G= b.R+ B = l'_‘l cec. G +B = C dR+C=_W e G+M=_W £B+Y= W Arurd Gr g W-R = hw-6=M iw-B=_Y i‘W-C=_K KW-M= 0 LW-Y= mW-R-C= Bla® nWw-G-B-= A oW-M-G= Blade (Rr6+B)-R-(o18) (Rrer8) ~6-8 (Rr6+6) - (R+E) — 6 © The Physics Classroom, 2009 Page 8 '