Copy of Iodine Clock Lab

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Chemistry

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Dec 6, 2023

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A Study on the Impact of Concentration Variation on Reaction Rate in an Iodine Reaction System By: Parker Tavis On June 5th, 2023 Table 1. Observations of the Change in Reaction Rate Depending on the Different Concentrations of an Iodate Solution to Distilled Water. Well number In Spot Plate Drops of Solution A (0.020mol/L) Drops of Water Time until color change (s) 1 1 9 *No change within time frame (12m) 2 2 8 502.91 3 3 7 256.25 4 4 6 127.64 5 5 5 96.08 6 6 4 82.93 7 7 3 57.96 8 8 2 54.32 9 9 1 50.35 10 10 0 36.86
Qualitative Observations: - When a well spot 10 was introduced, it resulted in the formation of a muddy brown color. As the reactions prior to that had lower concentrations of the iodate solution, the intensity of the brown color progressively decreased. Eventually, when 9 drops of water were added, there was no observable change in color. First Reaction IO 3 - (aq) + 3 HSO 3 - (aq) → 3 SO 4 2- (aq) + I - (aq) + 3H + (aq) Second Reaction 6 H + (aq) + IO 3 - (aq) + 5 I - (aq) → 3 I 2 (aq) + 3 H 2 O (l) Third Reaction I 2 (aq) + starch = blue-black complex Analyze and Evaluate a) What variables were measured/recorded and/or manipulated in this investigation? - The concentration amount of solution A - The concentration of water b) Calculate the concentration of iodate ions in each of the wells at the end of Step 2. In Step 2, the concentration remains unchanged as no water is added to the solution. However, in Step 3, when water is added, we can calculate the resulting concentration using the following formula: Calculated Concentration = (Concentration of Solution A (M)) x (Drops of Solution A) / (Total Volume) For instance, if Solution A has a concentration of 0.01 mol/L and 1 drop of it is added to a total volume of 10, the calculated concentration would be 0.01 M x 1 / 10 = 0.001 M. By repeating this step for all the concentrations of Solution A to water ratios, we can determine the resulting concentrations. Table.2 Concentration of Iodate Ions After Step 3 of the Process Well Number Concentration after step three (mol/L) 1 0.001 2 0.002 3 0.003 4 0.004
5 0.005 6 0.006 7 0.007 8 0.008 9 0.009 10 0.01 c) Calculate the concentration of iodate ions in each of the wells at the instant of mixing with an equal value of solution B. When an equal concentration of Solution B is added, the overall concentration of Iodate Ions in the mixture decreases since Solution B does not contain any Iodate Ions. As Solution B is consistently added in equal amounts (10 drops), we can calculate the resulting concentration using the formula: Calculated Concentration = (Concentration of Solution A (M)) x (Drops of Solution A) / (Total Volume) In this case, the total volume is now 20 drops due to the addition of Solution B. For the first well, the calculation would be 0.01 M (1 drop) / 20 drops = 0.0005 M, considering there is 1 drop of Solution A and a total volume of 20 drops. By applying this formula, we can determine the concentrations for the remaining wells, resulting in the following table: Table.3 Concentration of Iodate Ions at the Instant of Mixing 10 Drops of Solution B Well Number Concentration after Solution B (mol/L) 1 0.0005 2 0.001 3 0.0015 4 0.002 5 0.0025 6 0.003 7 0.0035
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8 0.004 9 0.0045 10 0.005 d) Using tables and graphs of your observations, identify the order of the reaction with respect to the concentration of iodate ions. Table.4 The Concentration of Solution A and Solution B in Comparison to Reaction Time Well number In Spot plate Initial [A] (Solution A) (mol/L) Initial [B] (Solution A) (mol/L) [A] in [B] (mol/L) Time until color change (s) 1 0.001 0.01 0.0005 *No change within time frame (12m) 2 0.002 0.01 0.001 502.91 3 0.003 0.01 0.0015 256.25 4 0.004 0.01 0.002 127.64 5 0.005 0.01 0.0025 96.08 6 0.006 0.01 0.003 82.93 7 0.007 0.01 0.0035 57.96 8 0.008 0.01 0.004 54.32 9 0.009 0.01 0.0045 50.35 10 0.01 0.01 0.005 36.86
- - The concentration of Solution B, [Solution B], does not impact the overall rate of the reaction since it remains constant. By examining Table 4, we can identify which concentrations are increasing and observe their effect on the overall reaction time, leading to a color change. - - From Figure 1, it is evident that the order of the reaction cannot be linear since the reaction time does not decrease linearly in relation to concentration changes. - - To determine the order of the reaction, we can compare the change in concentration to the change in reaction time. Using the general equation ([Well A]/[Well B])^x = (Time B/Time A), where x represents the order of the reaction with respect to Iodate Ions, [Well A]/[Well B] indicates the concentration change relative to A, and Time B/Time A signifies the change in reaction time relative to B. - - Analyzing Wells 2-4 using this equation, we observe that the time until the reaction shortens by approximately four times when [A] + [B] is doubled. - Calculations: Plugging the numbers in from well 2-4 we get: ((0.002)/(0.001)) x = 502.91/127.69 2 x = 3.94 2 x ≈ 4 (Round here for simplicity) x ≈ ln(4)/ln(2) x ≈ 2
The order of reaction with respects to Iodate Ions is 2 e) Answer the testable question using your results. Testable Question: In the iodine clock reaction system, how does the initial concentration of iodate ions affect the rate and/or sequence of the first two reactions? First Reaction IO 3 - (aq) + 3 HSO 3 - (aq) → 3 SO 4 2- (aq) + I - (aq) + 3H + (aq) Second Reaction 6 H + (aq) + IO 3 - (aq) + 5 I - (aq) → 3 I 2 (aq) + 3 H 2 O (l) Third Reaction I 2 (aq) + starch = blue-black complex - - The presence of Iodate Ions as a reactant in both the first and second reactions plays a crucial role in the overall reaction. An increase in the concentration of Iodate Ions promotes a shift of the net reaction to the right, as the reaction needs to produce more product to reach equilibrium and compensate for the increased amount of reactant. This increase in reactant concentration also leads to a higher reaction rate in the first two reactions, as more reactants result in a greater number of effective collisions over time, thus increasing the reaction rate. - - Furthermore, the second reaction can only proceed through the production of Iodide Ions (I-) in the first reaction. Similarly, the third reaction requires the presence of molecular Iodine (I2), which is generated during the second reaction. Therefore, the sequence of the reactions remains unchanged, as the second reaction relies on the formation of Iodide Ions, and the third reaction depends on the availability of molecular Iodine. -
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