Pre lab 4

tion 24 of 27 An empty beaker weighs 31.99 g.31.99 g. When completely filled with water, the beaker and its contents have a total mass of 405.55 g.405.55 g. What volume does the beaker hold? Use ?=1.00 g/mLd=1.00 g/mL as the density of water. volume:   mLmL How much would the beaker and its contents weigh if it was completely filled with mercury? The density of mercury is ?=13.5 g/mL.d=13.5 g/mL. total mass:

Bud N. Chemist must determine the density of a mineral sample. His five trials yield densities of 5.15 g/cm3, 4.83 g/cm3, 5.08 g/cm3, 4.97 g/cm3, 5.12 g/cm3. Independent studies found the correct density to be 5.06 g/cm3. Which of the following is incorrect? a. The mean of his analysis is 5.03 g/cm3 indicating an error of 0.03 g/cm3 from the correct density B.His data has a standard deviation of 0.017 g/cm3 C.His data has a relative standard deviation of 2.60% D. He can report his analyzed density as 5.0±0.2 g/cm3 at a 95% confidence level E. The true value (population mean) is found within the confidence interval of Bud’s work

Convert 234.0 x10^-4 to the proper exponential notation following thr rules of significant figures. A. 2.340x10^2 B. 2.340x10^ 0 C. 2.340x10^-2 D. 2.34x10 ^ 3 E. 2.340x10^ 3 F. 2.340x10^-1 G. 2.34x10^-2 H. 2.34x10^2 I. 2.34x10 ^-3 J. 2.340x10^ -3 K. 2. 349x10^1 L. 2.340

For the image attached Make a x and y axes graph of the average mass vs. year.

10) An experiment requires you to make several measurements. Based on the values in the table below, what would be the best statement that represents the data set if the true value is 0.2135? Trial A Trial B Trial C 0.2139 0.2893 0.2135 0.2130 0.3210 0.2134 0.2133 0.2999 0.3712 0.2135 0.2998 0.3715 A) The measurements in Trial A are accurate and precise, Trial B is neither accurate nor precise, and Trial C is accurate however, not precise. B) The measurements in Trial A are accurate and precise, Trial B is neither accurate nor precise, and Trial C is precise however, not accurate. C) The measurements in Trial A are accurate and precise, Trial's B and C are neither accurate nor precise. 11) Which of the following would be considered a physical change? A) burning paper B) boiling water C) digesting food 12) A salt water solution is classified as what type of matter? A) homogeneous mixture B) heterogeneous mixture C) pure substance 13) How many significant figures are in 0.0000401 kg? A)…

4. When you get your 5th correct answer, you will get a certificate that you can share with your teacher letting your teacher know how you did. Please provide a screenshot of your certificate showing you got this completed. DATA Part B: Measuring the Mass of Materials Top Loading Balance Mass Empty Beaker (g) Mass of Beaker + Paper Clips (g) Mass of Paper Clips (g) Analytical Balance Mass of Empty Beaker (g) Mass of Beaker + Paper Clips (g) Mass of Paper Clips (g) DATA ANALYSIS: 1. Show your calculation for the mass of paper clips using the top-loading and analytical balances. 2. Which of the balances, top-loading or analytical, has the most uncertainty per measurement? Explain. Page 10 of 14

2. A student performs an experiment Her data is below: Table 1. Masses Before and After Pulling Steel Wool Apart Trial 1 Trial 2 Trial 3 158.93 g 157.45 g 145.67 g Initial mass of steel wool Final mass of steel wool Difference AVERAGE 158.92 g -0.01 g 157.48 g 0.03 g -0.003 g 145.64 g -0.03 g Draw a diagram to show the particles before and after pulling: Before After

For the image attached Make a graph of the average mass vs year. Please label y and x axes

Done < AA www-awu.aleks.com MEASUREMENT Multiplication and division of... Decide whether each proposed multiplication or division of measurements is possible. If it is possible, v last column of the table. proposed multiplication or division Is this possible? result x10 (2.0 mg) - (0.020 g) = ? yes ola no Ar yes (4.0 g) · (6.0 mL) = ? no yes (2.4 em) · (0.30 m) = ? %3D no Explanation Check © 2021 McGraw-Hill Education. All Rights Reserved.

With explanation of why the chosen answer is wrong and why the new one is correct! Thank you.

How do I find the mass of water and volume of water that are empty. I know the formulas but which numbers do I use?

Twelve (12) samples were weighed on a balance, their combined mass is 13.62 g.  With the appropriate number of significant digits, what is the average mass of each sample?      1.1 g      1.14 g      1.135 g      1.1350 g      it is impossible to determine with the given information

Find the difference between the value of x2 and the sum of x1 plus x3.; let x4 be equivalent to the sum of x1 and x3 and let x5 be the difference between x2 and x5. This calculation scheme is shown below. Make notes about any similarities or differences between the values in your notes.  x4 = x1 + x3 x5 = x2 – x4  Data Analyis  This section will include all data collected during the lab.    Thermochemical Data    Tinitial (°C)  Tfinal (°C)  ΔT (°C)  moles NaOH  qreaction (kJ)  ΔHrxn  Reaction 1  25.0    30.3    +5.3    0.025  -1.11    -44.4  Reaction 2  25.0    37.0    +12.0    0.025  -2.51    -100.4  Reaction 3  25.0    31.7    +6.7    0.025  -1.40    -56.1    Reaction 1: NaOH(s) → Na+(aq) + OH-(aq) + x1 kJ  1g /39.977g/mol = 0.025 moles  Moles NaOH = 0.025  qsolution = (4.184 J/g °C) (50.0g) (30.3°C -25.0°C)  = -1108.76 J/ 1000  qreaction (kJ) = -1.11 kJ   ΔH = -1.11 kJ/ 0.025 moles  ΔHrxn = -44.4 kJ/mol…

1. All answers to be entered via short answer are in the NUMERICAL FORMAT and presented up to the 3rd decimal place. ADD TRAILING ZEROS if necessary, to complete your answer. NO NEED TO INCLUDE THE UNIT for now.For uniformity of answers, please be guided by the following examples:- If your answer is 5.627594, enter 5.628- If your answer is 3.129934, enter 3.130- If your answer is 8.38, enter 8.380- If your answer is 1.2, enter 1.200- If your answer is 25, enter 25.000- If your answer is less than the value of 1, always place a zero before the decimal point (E.g.: if 0.5, enter 0.500)2. In cases for answers in the EXPONENTIAL FORMAT, please be guided by the following examples and format:- Do not convert your answer to decimal format- If your answer from the calculator is 1.23454566 x 10E-4, enter 1.235x10^-4 (no spaces in between)- If your answer from the calculator is 7.379566 x 10E-5, enter 7.38x10^-5 (no spaces in between)3. The ATOMIC MASSES should be rounded to the NEAREST WHOLE…

significant figures and units. 3. Perform the following calculations and report the answer with the correct number of A. (9.2030 g)(0.00230 g) + 0.1020 g² = 00²0211237 0.10205² 0.123292 B. 234.020 g- 184.08 g 382.402 mL-326.322 mL (1 fl oz = 29.6 mL) 4. An aluminum beverage can contains 12.0 fluid ounces of liquid. Express this volume in liters. 12. uffaz X 560 080ML 49.949 = 0.8905g/mL CHE 1011 29.6mL = 355.2 mL Ift:0² (1 in = 2.54 cm) 5. What is the volume, in cubic centimeters, of a brick that is 4.0 in x 2.7 in × 8.0 in? 4.0A x 2,54 cm = 10.16cm liAcc 207 + x 2.54cm = 60858cm هذا 8.0MAX 2.54cm ITA 20032cm So volume 20.32cm x 6.858cm x 200320 1415.84 cm³ 6. The S.I. unit of energy is the joule, J (1 J = 1 kgom²/s²). Another energy unit, the erg, was once in widespread use (1 erg = 1 gocm²/s²). Calculate the number of ergs in 1.0 J. Page 2 of 2

5 nyoor X A the p X Spoti x A Chap x E * Par X Netfli X Goo 53. Calculate Make the following conversions. Express your answers in scientific notation. a. 14.8 g = ? ug b. 3.72 g = ? kg C. 66.3 L ? cm³ d. 7.5 x 104 J = ? kJ e. 3.9 × 10° mg = ? dg f. 2.1 X 10 dL = ? µL %3D %3D

7. A concentrated sulfuric acid solution is 65.0% H₂SO4 by mass and has a density of 1.55 g/mL at 20°C. What is the mass of 9.00 L of the concentrated sulfuric acid solution? A. 5.85 kg B. 9.00 kg C 21.4 kg D. 3.77 kg €13.9 kg 9.0L |1.559 0.001 = 13.95

None

One student calibrated a 50-ml burette by using the mass of water delivered. The student used an analytical balance which was previously calibrated by STEEL (density = 7.8 g/mL). During calibration, the temperature of water was found to be 19.0.C. The density of water at this temperature is 0.9984 g/ml The results of the calibration by the student is shown in the table below:   A B C  D E Apparent burette reading,mL 10.05 20.04 30.08 40.07 49.98 Weight H2O delivered, g 10.03 20.09 30.05 40.02 49.83 Note: All masses in mentioned in this section are understood to be in grams and all volumes mentioned are understood to be in milliliters. 35. What is the true mass of water delivered in A? A) 10.03 B) 10.04 C) 10.05 D) 10.06 E) 10.07 36. What is the true mass of water delivered in B? A) 20.12 B) 20.13 C) 20.14 D) 20.15 E) 20.1637. What is the true mass of water delivered in C? A) 30.13 B) 30.11 C) 30.10 D) 30.09 E) 30.08 38. What is the true mass of water delivered in D? A) 40.09…

Express each answer in scientific notation in the units indicated.a. (1.26 × 1 0 4 kg) + (2.5 × 1 0 6 g) in kgb. (7.06 g) + (1.2 × 1 0 -4 kg) in kgc. (4.39 × 1 0 5 kg) - (2.8 × 1 0 7 g) in kgd. (5.36 × 1 0 -1 kg) - (7.40 × 1 0 -2 kg) in g

For the image attached be sure your answers have the correct number of significant figures plus show calculations

No need to explain. Just give the answers directly. Thank you. 1. If your final answer is 4.5023485 grams, what will you input as your final answer? 2. Round off 0.274 to two (2) significant figures 3. Round off 20.0847 to two (2) significant figures

7. The density of copper is 8.96 g/cm³. Write this density as a conversion factor to convert: a. Mass to Volume 19/12="1000 b. Volume to Mass 21 cin² chime len³= Inic 1cm³ 40 0.11166714 g/ml 0.1 qime