investigation 5 written argument

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East Carolina University *

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07

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Chemistry

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Dec 6, 2023

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3

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DATE: SECTION/GROUP: _____group 5_______________________ NAME: NAME: ______________sanaa hunter___________________________ NAME: NAME Zach Holtsclaw ________________________________________________________________ Investigation 5 Written Argument Guiding Question (2 pts): What is the stacking order for the 3 sugar solutions? Claim (5 pts): The stacking order of the 3 sugar solutions from dense to less dense would be sugar 2, sugar 1, and sugar 3. The stacking order depended on the density and the intermolecular force holding the molecules in the sugar solutions together.
Evidence (13 pts): Density- D = 𝑀 𝑉 Sample Calculation - = 0.97 5.32 5.50 Chart 1 Trial 1 Cylinder Mass (g) Cylinder Mass w/Liquid (g) Mass (g) Volume (mL) Density (g/mL) Sugar 1 N/A N/A N/A N/A 1.09g/mL Sugar 2 39.983g 46.500g 6.51g 5.60mL 1.16g/mL Sugar 3 39.067g 44.386g 5.32g 5.50mL 0.97mL Trial 2 Cylinder Mass (g) Cylinder Mass w/Liquid (g) Mass (g) Volume (mL) Density (g/mL) Sugar 1 N/A N/A N/A N/A 1.09g/mL Sugar 2 40.016g 46.995g 6.98g 6.20mL 1.13g/mL Sugar 3 39.098g 44.108g 5.01g 5.30mL 0.95g/mL
Justification of the Evidence (10pts) Density defines the concentration of the sugar solutions. The sugar molecules are held together with intermolecular forces. The weak force-bonded sugar molecules would be less dense because they can dissolve in water quicker and with less effort compared to the more dense strong-bonded sugar molecules. During the experiment, the sugar solutions were able to be separated based on their different densities without the fear of mixing the three solutions because the bonds were different and the strength of the bonds. The different densities allowed the sugar solutions to be stacked as the higher the density the lower the solution will sit. Sugar 2’s density is higher compared to the other sugars because the bond is stronger, so during the experiment, it was able to be poured into the cylinder first without being mixed with the other sugar solutions. The concentration for Sugar 2 was higher compared to the other sugar solutions because more sugar was in this solution while the others had more water. Sugar 2’s density for Trial 1 (1.16 grams/milliliters) was higher than Sugar 1 (1.09 grams/milliliters) and Sugar 3 (0.97 grams/milliliters). These density measurements prove that the order of the stacking will be sugar 2, sugar 1, and lastly sugar 3. Sugar 3’s molecular bond force was weaker compared to Sugar 2 and Sugar 1, so the solution was poured last. When Sugar 1’s solution was added on top of Sugar 2’s solution, a small amount of the sugar solutions were mixed together because of the undissolved water left in the solutions. Once the sugar dissolved enough between the two, they were able to separate because no more sugar was left to be dissolved between the two sugar solutions. The same happened between the less dense solutions from Sugar 1 and Sugar 3. After trial one, a second trial was used in order to provide accurate results. In trial two the sugar solution densities went as follows Sugar 1 (1.09 grams/milliliters), Sugar 2 (1.13 grams/milliliters), and Sugar 3 (0.95 grams/milliliters). The results from trial two produced the same stacking order as trial one. Sugar 2 would be poured first into the bottom with Sugar 1 being stacked on top of Sugar 2. Sugar 3 would be poured on top of both of the other sugars. After being stacked on top of each other, none of the substances mixed, proving that the density measurements were correct and the stacking order of the three solutions were correct.
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