Lab Report 3 Moles

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Princeton University *

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HEALTH ASS

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Chemistry

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Dec 6, 2023

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docx

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2

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Lab Report 3 Moles Name Abel Abad 1. Note the average atomic mass of the elements on the nano-balance. Add atoms to the larger balance until it registers the same number (in g) as the reading on the nano- balance (in u). Use the Exponent slider to help get the correct amount. Stop adding atoms when the readings on both balances match exactly. Element Atomic mass (units) How many atoms did you need to add? Cu 63.546 u 6.0221x10 23 C 12.011 u 6.0221x10 23 S 32.065 u 6.0221x10 23 Al 26.982 u 6.0221x10 23 2. Select Copper(I) oxide, Cu 2 O . Note that Cu 2 O is a compound composed of different types of ions bonded together. Place the formula unit of Cu 2 O on the nano-balance. A. What is the molar mass of Cu 2 O? 143.091 u B. Add molecules to the larger balance until its reading matches that of the nano- balance exactly. How many molecules did you need to add? 6.0221x10 23 3. Complete the following statements using the number of specific particles : A. 1 mole of any atomic element contains 6.0221x10 23 particles B. 1 mole of any molecular compound contains 6.0221x10 23 particles
4. For compounds, it is sometimes necessary to consider the number of atoms of each element within a compound. Select Iron (II) chloride. Note the image in the Gizmo. A. How many Fe atoms are within FeCl 2 ? 1 B. How many Cl atoms are within FeCl 2 ? 2 C. Use the nano-balance to find the mass of each of the independent atoms: Mass of Fe atom: 55.845 u Mass of Cl atom: 35.453 u D. Find the sum of their masses (1 Fe atom + 2 Cl atoms): 126.751 u Additional Questions 1. Solve each of the following problems using dimensional analysis (or another method). Show your work . A. 9.23 × 10 23 Al atoms = 1.533 moles of Al 9.23 x 10 23 atoms 6.022 x 10 23 atoms / moles = 1.533 moles of Al B. 75 g of KMnO 4 = 2.858 x 10 23 formula units of KMnO 4 KMnO 4 = 158.034 g/mol 75 g 158.034 g mol x 6.022 x 10 23 atoms moles = 2.858 x 10 23 formula units C. 0.75 moles of CO 2 = total carbon and oxygen atoms (0.75 moles)( 6.022 x 10 23 atoms / moles )= 4.517 atoms of CO 2 1.22 atoms of C 3.30 atoms of O
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