WA 1 Dearing

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Thomas Edison State College *

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121

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Chemistry

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Apr 3, 2024

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Name: Eric Dearing College ID: 0550796 Thomas Edison State College General Chemistry I with Labs (CHE-121) Section no.: Semester and year: May 2014 Written Assignment 1: Introduction and Measurement Answer all assigned questions and problems, and show all work. 1. Do the following statements describe chemical or physical properties? (10 points) a. Oxygen gas supports combustion. - Chemical b. Fertilizers help to increase agricultural production. - Chemical c. Water boils below 100°C on top of a mountain. - Physical d. Lead is denser than aluminum. - Physical e. Uranium is a radioactive element. - Physical (Reference: Chang 1.11) 2. Classify each of the following as an element, a compound, a homogeneous mixture, or a heterogeneous mixture: (7 points) a. water from a well - Compound b. argon gas - Element c. sucrose - Compound d. air – Homogenous mixture e. dirt – Heterogeneous Mixture f. a rusty iron nail - Heterogeneous g. ozone - Compound 3. Express the answers to the following calculations in scientific notation: (12 points) a. 145.75 + (2.3 × 10 –1 ) = 145.98, 2.3 x 10 –1 = 0.23, 145.75 + 0.23 = 145.98 b. 79,500 ÷ (2.5 × 10 2 ) = 318, 2.5 × 10 2 = 250, 79,500 ÷ 250 = 318 c. (7.0 × 10 –3 ) – (8.0 × 10 –4 ) = 7.0 x 10 –3 – 0.8 × 10 –3 = 6.2 x 10 –3 = 0.0062 d. (1.0 × 10 4 ) × (9.9 × 10 6 ) = (1.0 × 9.9) = (1.0 × 9.9)(10 4+6 = 10 10 ) = 9.9 x 10 10 =99,000,000,000 (Reference: Chang 1.31) 1
4. What is the number of significant figures in each of the following measurements? (8 points) a. 4867 mi, 4 significant figures b. 56 mL, 2 significant figures c. 60,104 ton, 5 significant figures d. 2900 g, ambiguous case, number may contain 4 (2.900x10 3 ), 3 (2.90x10 3 ), 2 (2.9x10 3 ) e. 40.2 g/cm 3 , 3 significant figures f. 0.0000003 cm, 1 significant figures g. 0.7 min, 1 significant figures h. 4.6 × 10 19 atoms, 2 significant figures (Reference: Chang 1.33) 5. Express the results in the proper number of significant figures. (12 points) a. 5.6792 m + 0.6 m + 4.33 m 5.6792 m + 0.6 m = 6.2792 m + 4.33 = 10.6, 3 significant figures b. 3.70 g – 2.9133 g = 0.79 g, 2 significant figures c. 4.51 cm × 3.6666 cm = 16.54 cm, 4 significant figures d. (3 × 10 4 g + 6.827g)/(0.043 cm 3 – 0.021 cm 3 ), 1g = 1 cm 3 30,000 g + 6.827 g =30,006.827 g 0.043 cm 3 – 0.021 cm 3 = 0.022 cm 3 6.827 ÷ 0.022 = 310.318 g, 6 significant figures (Reference: Chang 1.35) 6. Carry out the following conversions: (16 points) a. 22.6 m to dm, 1m=10dm, 22.6x10= 226 dm b. 25.4 mg to kilograms, 1 million mg = 1 kg - or - 1 kg = 1.0 x 10 -6 25.4 mg x 10 -6 = 2.54x10 -5 kg or 0.0000254 kg c. 556 mL to liters = 1000 ml = 1 liter, 556 ÷ 1000 = .556 liters d. 10.6 kg/m 3 to g/cm 3, , 1000 kg/m 3 = 1 g/cm 3 , 10.6 ÷ 1000 = 0.0106 g/cm 3 (Reference: Chang 1.39) 7. The average speed of helium at 25°C is 1255 m/s. Convert this speed to miles per hour (mph). (4 points) 1255 x 3600 (seconds in hour) = 4,518,000 ÷ 1609.344 (1 mile = 1609.344 meters) 2807.355047 mph or 2807.4 mph (Reference: Chang 1.41) 2
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