Introduction to Laboratory Glassware and Measurement (1)

docx

School

University of South Florida *

*We aren’t endorsed by this school

Course

2045L

Subject

Chemistry

Date

Apr 3, 2024

Type

docx

Pages

6

Uploaded by AmbassadorElk685

Report
Introduction to Laboratory Glassware and Measurement Makayla Pearson Section #012 Part A: Determination of water density using different glassware. Table 1: Density determination of water with different glassware Glassware Trial Volume of water (mL) Mass of water (g) Density (g/mL) Mean Density (g/mL) Standard Deviation (g/mL) Percent (%) Error (g/mL) Graduated Cylinder 1 2 3 49.00 mL 49.00 mL 49.00 mL 47.93 g 48.16 g 48.35 g 0.98 g/mL 0.98 g/mL 0.95 g/mL 0.97 g/mL 0.017 g/mL 2.827% Beaker 1 2 3 50.00 mL 50.00 mL 50.00 mL 23.96 g 24.44 g 25.27 g 0.48 g/mL 0.49 g/mL 0.51 g/mL 0.49 g/mL 0.015 g/mL 50.91% Erlenmeyer flask 1 2 3 50.00 mL 50.00 mL 50.00 mL 40.08 g 41.43 g 42.04 g 0.82 g/mL 0.83 g/mL 0.84 g/mL 0.82 g/mL 0.01 g/mL 17.85% Volumetric flask 1 2 3 50.00 mL 50.00 mL 50.00 mL 49.66 g 49.72 g 49.75 g 0.99 g/mL 0.99 g/mL 0.99 g/mL 0.99 g/mL 0 g/mL 0% Calculations : Density (m/v) o Graduated Cylinder 47.93 g/49.00 mL = 0.968163265 g/mL ≈ 0.97 g/mL o Beaker 23.96 g/50.00 mL = 0.4792 g/mL ≈ 0.48 g/mL o Erlenmeyer Flask 40.80 g/50.00 mL = 0.816 g/mL ≈ 0.82 g/mL o Volumetric Flask 49.66 g /50.00 mL = 0.9932 g/mL ≈ 0.99 g/mL
Mean Density - (Σm/ Σv) o Graduated Cylinder Σ 144.55 g / Σ 147 mL = 0.98333 g/mL ≈ 0.98 g/mL o Beaker Σ 73.67 g/ Σ 150 mL = 0.491133333 g/mL ≈ 0.49 g/mL o Erlenmeyer Flask Σ 123.55 g / Σ 150 mL = 0.82366667 g/mL ≈ 0.82 g/mL o Volumetric Flask Σ 149.13 g/ 150 mL =0.9942 g/mL ≈ 0.99 g/mL Standard Deviation σ = √(∑(x−¯x) ( x − x ¯ ) 2 /n)) o Graduated Cylinder o 0.0006 g/mL ÷ 2 g/mL o = 0.0003 g/mL o √0.0003 g/mL o = 0.017320508075689 g/mL o ≈ 0.017 g/mL o Beaker o 0.00046666666666667 g/mL ÷ 2 g/mL o = 0.00023333333333333 g/mL o √0.00023333333333333 g/mL o 0.015275252316519 g/mL o ≈ 0.015 g/mL o Erlenmeyer Flask o 0.0002 g/ml ÷ 2 g/mL o = 0.0001 g/mL o √0.0001 g/mL o = 0.01 g/mL o Volumetric Flask o 3.6977854932235E-32 g/ mL ÷ 2 o = 1.8488927466117E-32 o √1.8488927466117E-32
o = 1.3597399555105E-16 o ≈ 1.36E-16 Percent Error- Percentage Error = ((Estimated Number – Actual Number)/ Actual number) x 100. o Graduated Cylinder |−0.028224/0.998224 | x 100% = | -0.028274215 | ×100% 0.028274215×100 =2.8274215 ≈ 2.827% o Beaker | −0.508224/0.998224| x 100% = | −0.509128212 |× 100% 0.509128212×100 = 50.9128212 ≈ 50.913% o Erlenmeyer Flask | −0.178224/0.998224 | x 100% = |−0.178541089|×100% 0.178541089×100 =17.8541089 17.854% o Volumetric Flask |0/0.998224|×100% = |0|×100 0×100 = 0 ≈ 0% Post Lab Summary Questions Part A 1. The glassware that provides the most accurate measurement of density is the volumetric flask. It has a percent error of 0 and deviates the least, causing it to be the most precise as well. The least accurate glassware is the beaker. This glassware has a standard deviation of 50.91% and a standard deviation of 0.015. I can conclude that in order from left to right, the volumetric flask is the most precise, followed by the Erlenmeyer flask, beaker, and the graduated cylinder based of their standard deviation. 2. The cases where an Erlenmeyer flask should be used is for mixing solutions, titration, or holding chemicals. This is because you can always be precise of how much solution you have. It is not ideal for measuring because it only has one measurement. a. A graduated cylinder would be used to mix a solution and measure volume. A graduated cylinder has numerous ticks to measure various amounts of given substance unlike a flask. b. A beaker could be used to hold solutions, chemical reactions, volume measurement or holding mixtures. A beaker is the ‘bowl’ in chemistry. You can give an estimate of how much substance you need but you can never be entirely accurate. This glassware is used to hold things.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
c. A volumetric flask can be used for volume measurement and holding chemicals. It will always be the most accurate when performing volume measurements because of its singular neck tick. Otherwise, it is only used to hold chemicals. Part B: Determination of the nature of an unknown metal. Table 2: Unknown metal block density using volume displacement Trial Mass of metal (g) Initial water volume (mL) Final water volume (mL) Water volume displaced (mL) Density of Metal (g/mL) Mean Density (g/mL) Standard deviation (g/mL) Percent (%) Error) 1 35.22g 26.00 mL 30.00 mL 4.00 mL 1.174 g/mL 1.174 0 0% 2 35.22g 26.00 mL 30.00 mL 4.00 mL 1.174 g/mL x x x 3 35.22g 34.00 mL 38.00 mL 4.00 mL 1.174 g/mL x x x Calculations : Volume Displaced o Trial 1 30.00 mL – 26.00 mL = 4.00 mL o Trial 2 30.00 mL – 26.00 mL = 4.00 mL o Trial 3 30.00 mL – 26.00 mL = 4.00 mL Density (m/v) o Trial 1 35.22 g/ 30.00 mL
= 1.174 g/mL Percent Error- Percentage Error = ((Estimated Number – Actual Number)/ Actual number) x 100. o Trial 1 | 1.174 - 1.174/ 1.174 | x 100 = | 0/ 1.174 | x 100% =|0| x 100 = 0% o Trial 2 | 1.174 - 1.174/ 1.174 | x 100 = | 0/ 1.174 | x 100% =|0| x 100 = 0% o Trial 3 | 1.174 - 1.174/ 1.174 | x 100 = | 0/ 1.174 | x 100% =|0| x 100 = 0% Table 3: Unknown metal block density using the ruler Trial Mass of Metal (g) Diameter (cm) Height (cm) Density (g/mL) Mean Density (g/mL) Standard Deviation (g/mL) Percent (%) Error 1 35.22 g 1.00 cm 5.00 cm 8.962 g/mL 8.962 g/mL 0 0% 2 35.22 g 1.00 cm 5.00 cm 8.962 g/mL x x x 3 35.22 g 1.00 cm 5.00 cm 8.962 g/mL x x x
Density (m/v) o Trial 1 Volume = 3.93 ( 𝜋 ⋅ 0.5 2 ) 5 Density = 35.22/3.93 ≈ 8.962 g/mL Percent Error- Percentage Error = ((Estimated Number – Actual Number)/ Actual number) x 100. o Trial 1 0/2 = 0 √0 =0% o Trial 2 0/2 = 0 √0 =0% o Trial 3 0/2 = 0 √0 =0% Post Lab Summary Questions Part B 1. The standard deviation for my metal using both the ruler and volume displacement is 0. a. The density and mean density of the metal is 8.962 while the standard deviation is 0. Based on this I can conclude that the metal is consistent with a pure metal such as aluminum, copper, or lead. It is a solid, bronze, and shiny metal. However, it could also be a mixture of those metals. This could be determined through further testing such as finding the melting point. 2. My metal is copper, I concluded this due to the theoretical density being so similar to the actual density. My percent error is 0, and due to the distinct color I could easily make this determination.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help