CHEM 106 Lab 6
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Apr 3, 2024
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Experiment 6: VSEPR and Molecular Shape “How Does It Look”
Observations and Experimental
Data for Part 1
Molecule Name
Shape
Bond Angle
Predicted Bond
Angle
PF6-
Octahedral
89.8
90
[BrF6]-
Octahedral
91.8
90
I3-
Linear
180
180
ln(CH3)3
Trigonal Planar
116.2
120
[BeF4]2-
Tetrahedral
109.7
109.5
NH4+
Tetrahedral
110.3
109.5
[SbF6]-
Octahedral
89.9
90
Data for Part 2
Molecule Name
Shape
XeF5-
Square Planar
H2O
Bent
[ClF4]-
Square Planar
SbBr52-
Square Pyramidal
Data for Part 3
Molecules
Predicted
Geometry
Actual Crystal
Structure
Predicted Angles
Actual Angles
Di-bromodimethylsel
enium
Seesaw
Seesaw
180, 90
177.7, 98º
SO2
Bent
Bent
120
113.0
NH3
Trigonal
pyramidal
Trigonal
pyramidal
109.5
102.9
Dichloro-diphenyl-se
Tetrahedral
Seesaw
180, 90
175, 100
lenium
Boric acid
Trigonal
planar
Trigonal planar
120
120.7
Focus Question
1.
What is VSEPR theory, and how can it be used to predict molecular shapes?
The VSEPR theory is used to predict the 3D structure of a molecule by analyzing the
number of electron groups around the central atom. There are two components of this theory:
electron geometry and molecular geometry. Electron geometry only considers the electron
groups around the center, including lone pairs as a group, and gives an overall shape for the
molecule. Molecular geometry also looks at the electron group around the center but it considers
the impact lone pairs can have on a molecular structure. For structures with a lone pair, they have
different names from their electron geometry and a lower expected bond angle.
2.
a) Can the structure of simple molecular substances be illustrated by drawing or building
models? Why are why not?
This is possible because when given a simple molecular substance and its molecular
formula, its Lewis structure can be drawn, which can help us to determine the number of electron
groups around the central atom. This information can then be used to find the molecular
geometry, which can be easily drawn. These structures can also be built as shown in this
experiment.
b) What about more complex molecules? Explain.
Complex molecules are harder to draw since their molecular formula tends to have more
atoms to each element. For instance, in the experiment, di-bromodimethylselenium and
dichloro-diphenyl-selenium were given. From the compound name, it can be hard to know the
chemical formula. In drawing the Lewis structure, it gets more complicated to draw an accurate
structure. However, these molecules can be built on a program performed in this experiment.
Hence, it isn’t impossible to draw and predict the molecular structure, but it can be difficult
without the help of a program.
3.
How are models and theories useful in helping explain the structure and behavior of
matter?
Models and theories like the VSEPR theory can help predict the 3D structure of a
molecule – its shape, bond angle, and polarity. A molecule with a greater amount of lone pairs
will decrease in bond angle and length, impacting the way the molecule looks. It can also show
how atoms are positioned, helping us see the molecule’s shape and polarity – whether there is
symmetry or if the dipole moments cancel out.
Post-Lab Questions
1.
What are molecular geometries and how do they differ from electron domain geometry
Molecular geometry predicts a molecule’s structure by looking at the number of electron
groups around the central atom and the impact lone pairs from the center can have on the overall
structure. This is seen by the many names and shapes of molecules with different amounts of
lone pairs. For instance, a molecule with 5 electron groups and 1 lone pair is a seesaw structure
while a molecule with the same amount of electron groups but with 2 lone pairs is a t-shape
structure. Electron geometry does not consider the impact of lone pairs and solely looks at the
number of electron groups around the central atom.
2.
What is the electronic geometry about a central atom which has the following number of
regions of electron density? Give one example of each.
a.
Three regions of electron density
Trigonal Planar. An example is sulfur dioxide.
b.
Four regions of electron density
Tetrahedral. An example is methane.
c.
Five regions of electron density
Trigonal bipyramidal. An example is sulfur tetrafluoride.
3.
Is PH3 molecule symmetrical or unsymmetrical? What about BI3? Explain your
reasoning for both.
PH3 is not symmetrical because its molecular shape is trigonal pyramidal – a tetrahedral
electron structure with 1 lone pair. Although lone pairs aren’t shown in molecular structures, it is
still a part of the molecule and affects the overall symmetry of the molecule. It can decrease the
bond angle and length of atoms in the structure.
BI3 is symmetrical because it is a trigonal planar with no lone pairs. Boron is an
exception to the octet rule and only needs three bonds. Since it does not need a lone pair, the
structure remains symmetrical.
4.
Keeping the VSEPR model in mind, draw the Lewis structure for ethanol, (C2H5OH)
and dimethyl ether (CH3OCH3). Determine the electron pair geometry and molecular
geometry around the oxygen atom in each.
Ethanol
Electron Groups: 4
Electron geometry: Tetrahedral
Molecular geometry: Bent
Dimethyl Ether
Electron Groups: 4
Electron geometry: Tetrahedral
Molecular geometry: Bent
5.
Cubane C8H8 is a cubic-shaped
hydrocarbon with a carbon atom at each corner of the cube.
a.
According to the VSEPR theory, what should be the shape around each carbon
atom? What bond angle is associated with this shape?
The VSEPR theory would predict a tetrahedral shape around each carbon with a
bond angle of 109.5º.
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b.
If you assume an ideal cubic shape, what are the actual bond angles around each
carbon?
The bond angles would be 90º around each carbon.
c.
Explain how your answer to questions 5A and 5B suggest why this molecule is so
unstable.
Since cubane has a tetrahedral shape around each carbon, it is supposed to have a
bond angle of 109.5º. However, as shown in the given picture and mentioned in 5B, its
actual bond angle is closer to 90º. Since the actual bond angle is far from the expected
value for structures with four electron groups, it could explain why the molecule is
unstable.
6.
What are the steps to determine the shape of a molecule given the formula? Explain and
show a few examples.
In order to find the molecular or electron geometry, the Lewis structure for the molecule
must be drawn to determine the number of electron groups around the central atom – this
includes the lone pairs.To draw a Lewis structure, you need three pieces of information: total
number of electrons (with octet and duet rule), total electrons used in the structure, and number
of lone pairs. The total electrons of a molecule (unshared) can be found by adding the total
amount of electrons for each element. Most elements follow the octet rule except for hydrogen (2
electrons) and boron (6 electrons). Next, you find the total number of electrons in the structure
by looking at the group an element is in on the periodic table, and multiplying the amount
appropriately to the number of atoms it contains. After doing this to each element, you add them
all together to get the electrons in the structure – this includes bonded and lone electrons. To find
the lone pairs of the center, you subtract the first piece of information we found (electrons with
the octet/duet rule) by the electrons used. Using these pieces of information, you can construct
your Lewis structure.
After drawing the structure, you count the total amount of electron groups around the
center and determine the electron geometry. Linear– 2 groups, trigonal planar– 3 groups,
tetrahedral– 4 groups, trigonal bipyramidal– 5 groups, octahedral– 6. To find the molecular
structure, you find the electron geometry and count the number of lone pairs around the atom.
Each electron geometrical shape has a different structure depending on the number of lone pairs.
*
Example: H2O
Total e-: 8+2(2)= 12 e-
Electron groups: 4
E- in structure: 6+2(1)= 8 e-
Electron geometry: tetrahedral
Lone pairs: 12-8= 4 e- (2 lp)
Molecular geometry: bent
*You would determine the name from this list:
Lone pair= lp
Trigonal planar 1 lp– bent
Tetrahedral 1 lp – trigonal pyramidal, 2lp– bent
Trigonal bipyramidal 1 lp– seesaw, 2 lp– T-shape, 3 lp– linear
Octahedral 1 lp– square pyramidal, 2 lp– square planar, 3 lp– T-shape, 4 lp– linear
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