Seperations Notbook (5)

How do I calculate mass %?

A 4.64 g sample of a laboratory solution contains 1.47 g of acid. What is the concentration of the solution as a mass percentage? % acid concentration: about us careers privacy policy terms of use contact us heip 440 4/13/2 DII FS %3* F7 PrtScn PgUp, F11 pgDn 12 Home End F10 F6 2$ & 4. 5 6. 8. 9. R Y K + I| 10 LL

4) During Run 1 (heated to 200°C), do you think that the sodium bicarbonate turned into NaOH, Na20, or Na2CO3? What about during Run 2 (heated to 400°C)? Did they form the same product, or different products? Was this expected or unexpected? Explain briefly.

Mass Aluminum Foil (g) 2.5415 Mass Filter Paper (g) 0.2777 Mass Filter Paper + Product (g) 35.6484 Mass Product (g) O 35.3708 g O 35.3705 g O 35.3707 g 35.3709 g O 35.3706 g Next

B. Percentage of Water in an Unknown Hydrate CUC2·X H20 UNKNOWN # mass of beaker and watchglass + unknown hydrate (before heating) 123.02 123.02 mass of beaker and watchglass 121.98 122.01 mass of unknown hydrate 122.81 122.78 mass of beaker and watchglass + anhydrous compound (after heating) nass of water (before heating - after heating) Show the calculation for the percentage of water for trial 1 (see Example Exercise 2). Percentage of water in the unknown hydrate Average percentage of water C. Water of Crystallization in an Unknown Hydrate 170.48 g/mol molar mass of anhydrous compound (AC) (see Instructor) percentage of water (see Procedure B) percentage of anhydrous compound (AC) Show the calculation for the water of crystallization (see Example Exercise 3). Water of crystallization НО AC• (Based on how rounding goes at various parts of this, there are two possible answers that I'll consider correct. Just put Formula of hydrate Analysis of Alum 138 down one of them.) 60

SHOW ALL CALCULATIONS. Mass of calcium phosphate sample plus weigling paper 2. 332 4 0.1849 Mass of weighing paper 2.332g-0.184g= 2.148 g Mass of calcium phosphate sample Ca3(Po4)2 40.08(3)+[30.97+16.00(4)]2= 310.18 g/mol Molar mass of calcium phosphate Number of moles of calcium phosphate 2.148 g x 1mole/310.18 g/mol= 0.006925 = 7.025 x 10° in your sample Moles of phosphorus in your sample Mass of phosphorus in your sample Percent phosphorus in your sample Percent of phosphorous in one mole of calcium phosphate

Please check my work. Analyze the data for the sample to get the Empirical formula of CxHy Given data for the sample compound with no oxygen: Mass of sample (g): 5.99 Mass of carbon dioxide collected (g): 19.25 Mass of water collected (g): 6.57

alculate the approximate volume of the vinegar sample needed for the analyses (Part A.1). Brand of vinegar or unknown no. Colauita tof White Wine Trial 1 1122809 Trial 2 Trial 1 Trial 2 e Guia 112.280g (12.822g 112.796 115 565 lis.9 1. Mass of flask (g) l15.603 2. Mass of flask + vinegar (g) 2.496 3.323 2,743 2,749 3. Mass of vinegar (g) B. Analysis of Vinegar Sample 2mL 7.5 23mL 32.コ 1. Buret reading of NaOH, initial (mL) 5.25mL 13ML amL 2. Buret reading of NaOH, final (mL) 33,3 31.2 1. Volume of NaOH used (mL) 2! mL a7.45 me 20.3 32.2 o i135 • 004 1 Molar concentration of NaOH (mol/L) Oi135 • 00 3 1003 , 063 5. Moles of NaOH added (mol) 6. Moles of CH,COOH in vinegar (mol) 7. Mass of CH,COOH in vinegar (g) 8. Percent by mass of CH,COOH in vinegar (%) 9. Average percent by mass of CH,COOH in vinegar (%) Calculations for Trial 1 of the first vinegar sample on next page. Experiment 10 137

Please can you help me fill in the blanks, with proper calculations thank you.

4. A new procedure for the determination of sulfur in coal was tested on a standard coal sample with a certified value of 2.14% sulfur by mass. The new procedure gave results of 2.11%, 2.07%, 2.04%, 2.06%, and 2.16% for five separate determinations.  a) Does the new procedure give the correct result at the 95% confidence level?  b) Does the new procedure give the correct result at the 90% confidence level?

Video Conferencing, Web Co X Illinois State University - CH X G What is the chemical formula x ð OneClass: Write the balance x ON What Is The Chemical Fo X G chemical formula table - Goc x + saplinglearning.com/ibiscms/mod/flcn/view.php?id=12024863 A Apps M Gmail YouTube Maps Translate GE News Reef – Class activi... sapling plue che My Print Center D Reef 2 Activity - Get l-PA... bartholomae.pdf Math help >> A Sapling Learning Ch 7 HW Aalyiah Washburn macmillan learning Sapling Learning > Illinois State University - CHE 110 - Fall20 - BOESDORFER > Activities and Due Dates > Ch 7 HW Assignment Score: Ex Give Up? O Hint 88.1% Resources Check Answer Attempt 3 N но What is the chemical formula for the limiting reactant in the reaction shown? chemical formula: H, + 2NO → N, + H,O Write the balanced chemical equation for the reaction, using lowest whole-number coefficients. © 2011-2020 Sapling Learning, Inc. |help about us careers privacy policy terms of use contact us !!!

4. A student conducted an experiment by heating BaCl₂ 2H₂O and reported the percent of water as 15.25%. Calculate the percent error (Hint: Use the calculated theoretical value).

A student uses a variety of techniques to separate four different compounds from 1.97 g of a mixture. After separation of the mixture, the student weighs each compound and finds 0.415 g of naphthalene, 0.277 g NaCI, 0.323 g of sand, and 0.646 g of iron. What is the total mass of solid recovered? mass: g What is the percent composition of naphthalene in the initial mixture? percent composition of naphthalene: % Compare the initial mass of the mixture to the amount recovered. What is the percent error for the separation? percent error:

Please don't provide handwriting solution

determine the mass percent of napthalene, NaCl, and sand from the following data. Also determine the total percent recovery. Mass of Beaker1: 45.845 g Mass of Beaker1 + sample: 47.500 g Mass of Beaker1 + sample after heating: 46.748 g Mass of filter paper: 2.000 g Mass of filter paper + sand: 2.574 g Mass of Beaker2 + boiling stone: 65.600 g Mass of Beaker2 + boiling stone + dried salt: 65.865 g

15. Laboratory analysis of a sample yielded the following data for the combustion of Nickel Ni(s) + O2(g) àNi O(s) i) Mass of a crucible = 30.02g ii) Mass of nickel (Ni) and crucible = 31.07 g iii) Mass of nickel oxide and crucible = 31.36 g Based on the above information, calculate the following iv) Mass of nickel (Ni) in sample = v) Mass of nickel oxide = c) Based on the above calculate the Theoretical Yield of Nickel oxide obtained from the mass of nickel in part (iv) above d) Calculate the percentage yield of nickel oxide

The formula to use for calculations of dilutions is 1. VịC = V½C2 %3D 2. VịC2 = V½C1 V2 3. a %3D 4. O 1 O 2 O 3 O 4 ||

please answer this question in the same format that's in the picture below. (Example picture.) answer correctly.Question: Calculate the mass in grams for: 0.75 mol hydrogen sulfide (H2S).

3. The 4.00 mL sample of vinegar had a mass of 4.056 g. Calculate the grams of vinegar in one liter. 4. Calculate the % acetic acid in the vinegar. % acetic acid = g acetic acid x 100 g vinegar 95

Determine the mass of the product from the following data.    Mass Aluminum Foil (g)      6.3284 Mass Filter Paper (g)      0.2489 Mass Filter Paper + Product (g)      86.2751 Mass Product (g)       Group of answer choices 86.0263 g    86.0262 g  86.0260 g    86.0264 g    86.0261 g

A student was able to separate the three components of a mixture via liquid chromatography. She obtained 1.27 g1.27 g of component A, 0.950 g0.950 g of component B, and 0.260 g0.260 g of component C. Determine the mass percent of each of the three components in the mixture.