Seperations Notbook (5)

How do I calculate mass %?

3a. Another student performed the same percent composition of a hydrate experiment, but kent the crucible completely covered throughout the entire experiment. What effect would this have on the experiment? Cor 3b. Would the student's calculated percent water in the hydrate be high, low, or unaffected? Explain why or why not.

The computed percent recovery was more than 100%. What does this signify, and what should be done about it?

A 4.64 g sample of a laboratory solution contains 1.47 g of acid. What is the concentration of the solution as a mass percentage? % acid concentration: about us careers privacy policy terms of use contact us heip 440 4/13/2 DII FS %3* F7 PrtScn PgUp, F11 pgDn 12 Home End F10 F6 2$ & 4. 5 6. 8. 9. R Y K + I| 10 LL

4) During Run 1 (heated to 200°C), do you think that the sodium bicarbonate turned into NaOH, Na20, or Na2CO3? What about during Run 2 (heated to 400°C)? Did they form the same product, or different products? Was this expected or unexpected? Explain briefly.

What is the % by mass of water in your hydrated copper (Il) sulphate? Mass of just anhydrous compound = mass of anhydrous compound - mass of beaker and rod 108.34g - 106.87g = 1.47g %D %3D = original compound mass - anhydrous compound mass = 3.00g - 1.47g = 1.53g Mass of just water %D

Mass Aluminum Foil (g) 2.5415 Mass Filter Paper (g) 0.2777 Mass Filter Paper + Product (g) 35.6484 Mass Product (g) O 35.3708 g O 35.3705 g O 35.3707 g 35.3709 g O 35.3706 g Next

B. Percentage of Water in an Unknown Hydrate CUC2·X H20 UNKNOWN # mass of beaker and watchglass + unknown hydrate (before heating) 123.02 123.02 mass of beaker and watchglass 121.98 122.01 mass of unknown hydrate 122.81 122.78 mass of beaker and watchglass + anhydrous compound (after heating) nass of water (before heating - after heating) Show the calculation for the percentage of water for trial 1 (see Example Exercise 2). Percentage of water in the unknown hydrate Average percentage of water C. Water of Crystallization in an Unknown Hydrate 170.48 g/mol molar mass of anhydrous compound (AC) (see Instructor) percentage of water (see Procedure B) percentage of anhydrous compound (AC) Show the calculation for the water of crystallization (see Example Exercise 3). Water of crystallization НО AC• (Based on how rounding goes at various parts of this, there are two possible answers that I'll consider correct. Just put Formula of hydrate Analysis of Alum 138 down one of them.) 60

SHOW ALL CALCULATIONS. Mass of calcium phosphate sample plus weigling paper 2. 332 4 0.1849 Mass of weighing paper 2.332g-0.184g= 2.148 g Mass of calcium phosphate sample Ca3(Po4)2 40.08(3)+[30.97+16.00(4)]2= 310.18 g/mol Molar mass of calcium phosphate Number of moles of calcium phosphate 2.148 g x 1mole/310.18 g/mol= 0.006925 = 7.025 x 10° in your sample Moles of phosphorus in your sample Mass of phosphorus in your sample Percent phosphorus in your sample Percent of phosphorous in one mole of calcium phosphate

5

Please can you help me fill in the blanks, with proper calculations thank you.

4. A new procedure for the determination of sulfur in coal was tested on a standard coal sample with a certified value of 2.14% sulfur by mass. The new procedure gave results of 2.11%, 2.07%, 2.04%, 2.06%, and 2.16% for five separate determinations.  a) Does the new procedure give the correct result at the 95% confidence level?  b) Does the new procedure give the correct result at the 90% confidence level?

Video Conferencing, Web Co X Illinois State University - CH X G What is the chemical formula x ð OneClass: Write the balance x ON What Is The Chemical Fo X G chemical formula table - Goc x + saplinglearning.com/ibiscms/mod/flcn/view.php?id=12024863 A Apps M Gmail YouTube Maps Translate GE News Reef – Class activi... sapling plue che My Print Center D Reef 2 Activity - Get l-PA... bartholomae.pdf Math help >> A Sapling Learning Ch 7 HW Aalyiah Washburn macmillan learning Sapling Learning > Illinois State University - CHE 110 - Fall20 - BOESDORFER > Activities and Due Dates > Ch 7 HW Assignment Score: Ex Give Up? O Hint 88.1% Resources Check Answer Attempt 3 N но What is the chemical formula for the limiting reactant in the reaction shown? chemical formula: H, + 2NO → N, + H,O Write the balanced chemical equation for the reaction, using lowest whole-number coefficients. © 2011-2020 Sapling Learning, Inc. |help about us careers privacy policy terms of use contact us !!!

4. A student conducted an experiment by heating BaCl₂ 2H₂O and reported the percent of water as 15.25%. Calculate the percent error (Hint: Use the calculated theoretical value).

Please don't provide handwriting solution

determine the mass percent of napthalene, NaCl, and sand from the following data. Also determine the total percent recovery. Mass of Beaker1: 45.845 g Mass of Beaker1 + sample: 47.500 g Mass of Beaker1 + sample after heating: 46.748 g Mass of filter paper: 2.000 g Mass of filter paper + sand: 2.574 g Mass of Beaker2 + boiling stone: 65.600 g Mass of Beaker2 + boiling stone + dried salt: 65.865 g

Answers accurate to 3 or 4 significant figures & show your work. 6. A 18.00-g sample of a mixture containing only FESO4.7H2O and SnCl4.5H2O was heated carefully to drive off the H2O (g) from the two hydrates. The remaining residue containing FeSO4 and SnCl4 weighed 11.75 grams. Show how you determine the percentage composition by mass of the two hydrates in the original mixture. You must show your work!

Using (i) a right triangular plot and (ii) an equilateral triangular plot, solve the following problem graphically. The following mixtures are completely mixed to form mixture D: Mixture Mass (kg) % NaCI % KCI % H2O A 50 50 50 В 100 20 80 C 75 40 60 1. Adding first mixtures A and B to yield the resultant mixture F. Then, add mixture F to mixture C to locate mixture D. 2. If 25 kg of H2O was removed from mixture D to produce mixture E, locate E and determine its composition.

15. Laboratory analysis of a sample yielded the following data for the combustion of Nickel Ni(s) + O2(g) àNi O(s) i) Mass of a crucible = 30.02g ii) Mass of nickel (Ni) and crucible = 31.07 g iii) Mass of nickel oxide and crucible = 31.36 g Based on the above information, calculate the following iv) Mass of nickel (Ni) in sample = v) Mass of nickel oxide = c) Based on the above calculate the Theoretical Yield of Nickel oxide obtained from the mass of nickel in part (iv) above d) Calculate the percentage yield of nickel oxide

7. In weighing by difference: Initial weight of the sample bottle containing the sample:10.0001g.Final weight of the sample bottle containing thesample:__g.Weight of the sample taken from the bottle is 6.0200 g   a 3.8901   b 3.9801   c 16.0201   d 16.020

750 g potassium iodide Oral Potassium 1 g per 237 mL per 950 g elemental iodine + 1.5 kgs potassium hydroxide Saturated iodide mL bottle Solution IC. SYNTHESIS AND PACKAGING % composition by mass of each compound

4

The formula to use for calculations of dilutions is 1. VịC = V½C2 %3D 2. VịC2 = V½C1 V2 3. a %3D 4. O 1 O 2 O 3 O 4 ||

The actual empirical formula of magnesium oxide is mgo. Explain any different between your result and the actual value.

please answer this question in the same format that's in the picture below. (Example picture.) answer correctly.Question: Calculate the mass in grams for: 0.75 mol hydrogen sulfide (H2S).