FA23 CHEM 225 Exp9 HANDOUT_E2 Rxn_001 (1)
pdf
School
New York University *
*We aren’t endorsed by this school
Course
225
Subject
Chemistry
Date
Jan 9, 2024
Type
Pages
3
Uploaded by BaronMandrill3001
v.001
1
Experiment #9: Elimination Reactions
(Monday-Thursday, Nov. 13
th
-16
th
)
.
During this laboratory session you will use your knowledge of laboratory techniques to conduct a series of elimination
reactions to convert meso-stilbene dibromide into 1,2-diphenylethyne. The product will be purified by recrystallization.
The product will be characterized by chemical tests that involve advanced addition reactions, which you will soon be learning
in lecture. The product will also be analyzed by gas chromatography (GC) coupled with a flame ionization detector (GC-FID)
and a mass spectrometer (GC-MS).
Textbook Reading
:
G&M 6
th
ed. pg. 403-405 (alkynes)
G&M 6
th
ed. pg. 149-152 (Br
2
/CH
2
Cl
2
and Bayer tests)
Jones 5
th
ed. pg. 332-348 (elimination reaction)
The following text have all been previously assigned
:
G&M 6
th
ed. pg. 92-99 (recrystallization –
re-assigned
)
G&M pg. 196-206 (Gas Chromatography –
re-assigned
)
Jones 5
th
Ed. 370-371 (Chromatography –
re-assigned
)
Jones 5
th
Ed. 372-382 (Mass Spectroscopy –
re-assigned)
Some Key Terms (in the context of this experiment)
:
elimination reaction (first order vs second order), side
reaction/product, gas chromatography (GC), mobile
phase, carrier gas, stationary phase, equilibrium constant,
mass spectrometry, molecular ion, parent ion, isotopes,
molecular weight, exact mass, mass spectrometer (MS),
flame ionization detector (FID)
Video Instruction
:
The following videos have all been previously assigned
:
View these videos as part of your pre-laboratory
preparation. Be aware that these videos will show you a
general
technique/equipment
but
the
compounds,
solvents, quantities, and exact equipment may not be the
same as those you will use in the laboratory. Use these
videos to become familiar with set-ups, procedures, and
concepts but think carefully about how your experiment
may differ from the video.
•
Recrystallization: *
re-assigned
,
10 minutes
https://www.youtube.com/watch?v=XK0MZk3Q4jk&
feature=player_embedded#at=12
•
Gas Chromatography (GC): *
re-assigned
,
10 minutes
http://www.youtube.com/watch?v=dffeiLgeKx8
•
Mass Spectrometry (MS)
:
re-assigned
,
10 minutes ea.
http://www.youtube.com/watch?v=rBymrFzcaPM
http://www.youtube.com/watch?v=dq7xKVvXWew
http://www.youtube.com/watch?v=Ar1Zum1Phv8
http://www.youtube.com/watch?v=fr89hoF1QjE
Also see previously posted GC-FID and GC-MS lab
lecture videos posted on Brightspace, Media Gallery.
Safety Data Sheets
: Review SDS as usual.
Notebook
:
Prepare
your
notebook
as
usual
in
accordance with the Notebook Guidelines document.
Quizzes
may contain content from any of the previously
introduced content, particularly Mass Spectrometry and
NMR spectroscopy, which is also relevant for the current
experiment.
General Information
A meso-compound (meso-stilbene dibromide) is used
as the starting material and it is important to be aware of
a few mechanistic details. The first step involves a base
induced elimination of hydrogen halide to produce a
haloalkene intermediate. This transformation proceeds
through a concerted E2 mechanism where the hydrogen
and the departing halide are in an anti-periplanar
orientation. The second step involves a second base
induced elimination of hydrogen halide to produce the
final product, 1,2-diphenylethyne. This second step also
proceeds through a concerted E2 mechanism, however in
this rather rare case the hydrogen and the departing
halide are in a syn-periplanar orientation.
Figure 1
. Reaction scheme of the dehydrobromination of
meso-stilbene dibromide
REACTION AND PURIFICATION
To a small test tube add meso-stilbene dibromide (400
mg) to triethylene glycol (2 mL). Stir using the magnetic
spin vane and the stir plate. After stirring for 2 minutes,
add ~200 mg of potassium hydroxide (do not crush KOH
pellets).
CAUTION: Potassium hydroxide is highly corrosive and
must be treated with caution. It is also hydroscopic so
the source container must be closed immediately after
use.
Br
H
Br
H
meso-stilbene dibromide
Rotate 120
°
, so that the hydrogen
and bromide are anti-pariplanar
Br
H
H
Br
H
Br
KOH
triethylene glycol
1,2-diphenylethyne
KOH
triethylene glycol
v.001
2
Prepare to heat the stirring solution using the aluminum
heat block and ~5 layers of aluminum foil insulating the
first two centimeters of the test tube that are
above
the
heating block (but leave a small vertical opening so that
you may view the reaction solution. Be sure to position
the test tube exactly in the center of the hot plate.
Position and clamp a digital thermometer so that it
directly measures the temperature of the reaction
mixture, but does
not
impede the spin vain from stirring.
Include a diagram of this described setup in your
notebook.
Be sure that the hot plate cord not touching the top of the
hot plate. Heat the reaction mixture to 170
°
C for 15
minutes. There is a lot of action going on here at the
molecular level.
Then remove the heat source to allow the reaction
mixture to cool to room temperature.
Add ~4 mL of
water and stir vigorously with a wooden stick for ~1
minute.
Place
the
test
tube
in
an
ice-bath
for
approximately 5 minutes to enhance precipitation. Using
vacuum filtration, collect the crude product. Rinse the
product with ~2 mL of water.
Crude Product Sample
: At this point, save ~15 mg of
crude product to be used for analysis
in case
your
recrystallization
is
NOT
successful.
If
your
recrystallization
IS
successful, then you can discard this
crude product sample at the end of the lab session.
Purification by Recrystallization
Recrystallize the bulk crude product using 70:30
ethanol:water mixture (you prepare this mixture).
If no crystals form, consider your options for inducing
nucleation.
Collect the recrystallized product by vacuum
filtration (this is the “
Purified
Product Sample”).
ANALYSIS
At this point, you will proceed with analysis of
EITHER
your “
Crude
Product Sample” OR your “
Purified
Product Sample” (use the latter if you have >15 mg). Be
sure to make note of which you use in your notebook,
and inform your instructor of which you are using.
Bromine in Dichloromethane Test.
Place a small
amount (~5 mg) of your product in a test tube and add 1
drop of the pre-made bromine in dichloromethane
(Br
2
/CH
2
Cl
2
) solution. Observe if a change in color
occurs between the original solution and upon exposure
to the Br
2
/CH
2
Cl
2
solution. You do not need to know the
mechanism
but
you
must
understand
what/why
observation is expected for a successful reaction product.
Note: Br
2
is responsible for the yellow color of the pre-
made solution. See the G&M textbook for details on this
chemical test, and think about the limitations of this test.
Bayer Test.
Place a small amount (~5 mg) of your
product in a test tube and dissolve it in 2 mL of ethanol.
In a separate test tube add
only
2 mL of ethanol to use as
a control. Add 1 drop of the prepared potassium
permanganate solution to each test tube. Observe if a
change in color occurs between the test tube containing
the sample and the control. You do not need to know the
mechanism
but
you
must
understand
what/why
observation is expected for a successful reaction product.
See the G&M textbook for details on this chemical test,
and think about the limitations of this test. Also,
be sure
to dispose of this material in the special “permanganate
waste” bottle
.
GC-FID
: Samples will be analyzed by GC-FID analysis.
Sample preparation will be described/demonstrated
during the session. You should have an understanding of
how the GC-FID spectrum would look if there were
residual (left over) starting material compound and
intermediate (mono-bromo alkene) compound in the
final product mixture in the case where they were not
properly removed by the purification steps.
GC-MS
: Selected samples will be analyzed by GC-MS
analysis. You should have an understanding of how the
MS
spectrum
looks
for
the
starting
material,
intermediate, and product.
Mass
. Determine the mass of your sample.
Optional
:
Place your product sample in your 50 mL beaker. Use
tape to label it with (i) your name, (ii) your section #
Take your labeled sample to the drop-off location to be
dried (by Instructors) in the vacuum oven.
After your sample has been dried in the vacuum oven
determine the mass and melting point.
Sample Submission
Submit your sample in a SMALL vial. NEATLY fill out
and attach a white adhesive label prior to submission of
your sample to your section Instructor.
Required Data Prediction/Analysis
:
You will have the opportunity to carry out activities that
aim to enhance your ability to predict and interpret GC-
FID,
GC-MS,
NMR
and
IR
spectroscopy
data.
Instructions for Analysis Practice will be provided
during the laboratory session.
Further, there should be time left at the end of this
session for you to ask questions, if you have them
regarding any laboratory course content.
Post-Lab Assignment
See experiment folder on the laboratory Brightspace
website after your laboratory session.
v.001
3
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Documents
Related Questions
Reaction of propene (above) with HBr might, in principle, lead to a mixture of two alkyl bromide addition products. Name these two alkyl bromides.
arrow_forward
My Organic Chemistry textbook says about the formation of cyclic hemiacetals, "Such intramolecular reactions to form five- and six-membered rings are faster than the corresponding intermolecular reactions. The two reacting functional groups, in this case OH and C=O, are held in close proximity, increasing the probability of reaction."According to the book, the formation of cyclic hemiacetals occurs in acidic conditions. So my question is whether the carbonyl group in this reaction reacts first with the end alcohol on the same molecule or with the ethylene glycol. And, given the explanation in the book, if it reacts first with ethylene glycol before its own end alcohol, why would it? I don't need to know the final answer. I need to know WHY it would not undergo an intermolecular reaction prior to reacting with the ethylene glycol if that is the case. Please do not use an AI answer.
arrow_forward
Alkynes do not react directly with aqueous acid as do alkenes, but will do so in the presence of mercury(II) sulfate as a Lewis acid catalyst. The reaction occurs with Markovnikov
regiochemistry, so the OH group adds to the more highly substituted carbon and the H adds to the less highly substituted carbon. The initial product of the reaction is a vinyl alcohol, also called
an enol. The enol immediately rearranges to a more stable ketone via tautomerization.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
-X티
Hö:
H-O
-CH3
-CH3
H30*
arrow_forward
OH
NaOH
H3C
CH3
H3C
CH3
Alkyl halides undergo nucleophilic substitution and elimination reactions. When the kinetics of the reaction are
measured, if the rate of the reaction is found to be dependent only upon the concentration of the alkyl halide the
reaction is first order. The substitution reaction is thus termed Sy1, and the elimination reaction is termed E1. These
reactions are unimolecular and occur in two steps. The first step is rate-limiting and involves the loss of the leaving
group to form a carbocation. In the second, fast, step the nucleophile adds to the carbocation in the SN1 reaction or
elimination occurs to give an alkene in the E1 reaction. Because the carbocation is planar, the nucleophile can add to
either face and therefore racemization is usually observed although solvent effects can influence this somewhat. E1
elimination follows Zaitsev's rule and typically yields the most substituted alkene as the major product.
Conditions which favor the Sy1/E1 pathway include…
arrow_forward
[Review Topics]
[References]
HO
pyridine
1.
SOCIl,
+
sO2
+
H.
Aqueous acetone
H3C
H20
H3C
HBr
2.
Br H
OH
optically active
racemic
f = SN1 Nucleophilic substitution
g = SN2 Nucleophilic substitution
a = Proton transfer
d = E1 Elimination
b = Lewis acid/base
e = E2 Elimination
c = Electrophilic addition
The rections above involve synthesis or reactions of alcohols and ethers.
Identify the mechanism by which they proceed from among the mechanisms listed. Use the letters a - g for your answers.
1.
2.
arrow_forward
Only one of the chlorine atoms in the molecule, 3,4-dichloronitrobenzene, will undergo nucleophilic substitution. Indicate which position will react and provide the expected product for the given reaction using reaction intermediates (resonance structures).
arrow_forward
Functional groups such as alkynes react the same in complex molecules as they do in simpler structures. The following example of alkyne reaction were taken from syntheses carried out in the research group of E. J. Corey at Harvard University. You can assume that the reactions listed involve only the alkyne, not any of the functional groups present in the molecules. Draw the expected products for the following reaction .
arrow_forward
1. You are planning to carry out a reaction between butyne CH3CH₂C=CH, and sodium methoxide, CH3ONa. You
also need to choose an appropriate solvent for the reaction. Would H₂O be an appropriate solvent? Explain your
rationale.
arrow_forward
CH3
CH3
Br-
Br2
.CH3
CH2Cl2
CH3
H3C
H3C
Br
Electrophilic addition of bromine, Brɔ, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an
anhydrous solvent such as CH,Cl,.
In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks
the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
CH3
CH3
CH3
CH3
H3C
H3C
:Br:
:Br:
arrow_forward
Compare the two reactions shown below.
excess
LICH,CH3
excess
LICH,CH3
Both electrophiles, an ester and a ketone, are reacted with an excess amount of LICH2CH2. Which reaction will result in the formation of a product with the molecular formula C9H200 and why?
O A: Only the reaction with the ester. LICH2CH3 results in an addition mechanism with both starting materials. However, the product from the ketone reaction contains fewer than 9 carbons.
O B. Only the reaction with the ketone. LICH2CH3 results in an addition mechanism with both starting materials. However, the product from the ester reaction contains two oxygen atoms.
O C. Both reactions. LICH2CH3 results in an addition mechanism with the ketone. However, the ester goes through a SNAC mechanism because it contains a leaving group, which allows two equivalents of LICH2CH3 to attack.
O D. Neither reaction. LICH2CH3 results in a SNAC mechanism with both starting materials. Both products contain more than 9 carbons.
arrow_forward
i need help drawing the product
arrow_forward
A lab technician planned to synthesize 2-bromopentane using 2-pentanol, heat, and HBr. However, the labtechnician did not have HBr in the lab. What other reagent(s) can the technician use to synthesize 2-bromopentane using 2-pentanol as the starting material?
arrow_forward
4. Synthesize the following compound. You may use benzene, acetylene, ethanol and any
inorganic reagents.
O₂N
arrow_forward
Acyl transfer (nucleophilic substitution at carbonyl)
reactions proceed in two stages via a "tetrahedral
intermediate." Draw the tetrahedral intermediate as it is
first formed in the following reaction.
CI
H₂N
OH
• You do not have to consider stereochemistry.
• Include all valence lone pairs in your answer.
• Do not include counter-ions, e.g., Na+, I, in your
answer.
• In cases where there is more than one answer,
just draw one.
Sn [F
arrow_forward
Select the reagent that you would use to convert an alkene to a Markovnikov (more
substituted) alcohol without possibility of carbocation rearrangement.
o H2SO4, H2O
OBH3-THF, then H2O2, H2O, NaOH
Hg(OAc)2, H2O, then NaBH4
o OsO4, TBHP, H2O
arrow_forward
Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the
tetrahedral intermediate as it is first formed in the following reaction.
CI
+
H₂N
• You do not have to consider stereochemistry.
• Include all valence lone pairs in your answer.
OH
• Do not include counter-ions, e.g., Na+, I¯, in your answer.
• In cases where there is more than one answer, just draw one.
arrow_forward
Consider the reaction below to answer the following questions.
When dichlorocarbene is generated in the presence of an alkene, a dichlorocyclopropane is formed.
Cl. CL
CH₂
(
H₂C
H
C=C
H
+ CHCl3
KOH
H₂C---
CH3
H
H
Write the complete stepwise mechanism for the formation of dichlorocarbene, :CCl₂. Show all
intermediate structures and show all electron flow with arrows.
arrow_forward
Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral
intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction.
0
OH
CI
+
H₂N
• You do not have to consider stereochemistry.
• Include all valence lone pairs in your answer.
• Do not include counter-ions, e.g., Na+, I, in your answer.
In cases where there is more than one answer, just draw one.
A
ChemDoodle
Activate Windows
arrow_forward
Ff.154.
arrow_forward
4. When analyzing a synthesis, it is extremely important to identify functional groups
and the reactions that can make them. Fill in the following chart for the functional
groups you learned to make this semester. Note that there may be more than
one answer, and that X = Cl or Br here.
Functional Group
Starting Material
=
alkyne
E-alkene (trans)
Z-alkene (cis)
Å
epoxide
X
two anti halogens
on adjacent carbons
НО
anti halohydrin
OH
alcohol,
most substituted carbon
OH
alcohol,
least substituted carbon
halide,
most substituted carbon
.X
halide,
least substituted carbon
Reagents
arrow_forward
5 & 6
arrow_forward
4. Dissolvable sutures are often used in medicine and dentistry so that additional surgeries don't
need to be done to remove the stitches. Two examples of dissolvable sutures are:
fart
CH2
-CH2
Dexon®
and
-CH2
-CH2
-CH2
CH,
-CH2
PDS®
Using the organic chemistry you have learned so far, propose a mechanism for how they
dissolve.
arrow_forward
3
9
$
4
R
H₂C
B
%
5
1.
Aqueous ethanol
HBr
CH₁
2.
OH
a
Proton transfer
d
E1 Elimination.
f = SN1 Nucleophilic substitution
b Lewis acid/base.
e E2 Elimination
g= SN2 Nucleophilic substitution
c = Electrophilic addition
The rections above involve synthesis or reactions of alcohols and ethers.
Identify the mechanism by which they proceed from among the mechanisms listed. Use the letters a- g for
your answers.
1.
2.
Submit Answer
Retry Entire Group 9 more group attempts remaining
Previous
Next>
Save and Exit
Cengage Learning Cengage Technical Support
O
8:15 AM
6/20/2022
PrtScn
PgDn
F5
F6
T
B
CH₂
Nà Nha
^
6
Y
H
N
&
7
[Review Topics]
H₂C
U
8
M
CH₂
NH₂
K
[References]
H₂C
73°F Sunny
Home
(
9
O
L
End
0
G
F10
P
PgUp
4x
F12
□
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you

Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Related Questions
- Reaction of propene (above) with HBr might, in principle, lead to a mixture of two alkyl bromide addition products. Name these two alkyl bromides.arrow_forwardMy Organic Chemistry textbook says about the formation of cyclic hemiacetals, "Such intramolecular reactions to form five- and six-membered rings are faster than the corresponding intermolecular reactions. The two reacting functional groups, in this case OH and C=O, are held in close proximity, increasing the probability of reaction."According to the book, the formation of cyclic hemiacetals occurs in acidic conditions. So my question is whether the carbonyl group in this reaction reacts first with the end alcohol on the same molecule or with the ethylene glycol. And, given the explanation in the book, if it reacts first with ethylene glycol before its own end alcohol, why would it? I don't need to know the final answer. I need to know WHY it would not undergo an intermolecular reaction prior to reacting with the ethylene glycol if that is the case. Please do not use an AI answer.arrow_forwardAlkynes do not react directly with aqueous acid as do alkenes, but will do so in the presence of mercury(II) sulfate as a Lewis acid catalyst. The reaction occurs with Markovnikov regiochemistry, so the OH group adds to the more highly substituted carbon and the H adds to the less highly substituted carbon. The initial product of the reaction is a vinyl alcohol, also called an enol. The enol immediately rearranges to a more stable ketone via tautomerization. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions -X티 Hö: H-O -CH3 -CH3 H30*arrow_forward
- OH NaOH H3C CH3 H3C CH3 Alkyl halides undergo nucleophilic substitution and elimination reactions. When the kinetics of the reaction are measured, if the rate of the reaction is found to be dependent only upon the concentration of the alkyl halide the reaction is first order. The substitution reaction is thus termed Sy1, and the elimination reaction is termed E1. These reactions are unimolecular and occur in two steps. The first step is rate-limiting and involves the loss of the leaving group to form a carbocation. In the second, fast, step the nucleophile adds to the carbocation in the SN1 reaction or elimination occurs to give an alkene in the E1 reaction. Because the carbocation is planar, the nucleophile can add to either face and therefore racemization is usually observed although solvent effects can influence this somewhat. E1 elimination follows Zaitsev's rule and typically yields the most substituted alkene as the major product. Conditions which favor the Sy1/E1 pathway include…arrow_forward[Review Topics] [References] HO pyridine 1. SOCIl, + sO2 + H. Aqueous acetone H3C H20 H3C HBr 2. Br H OH optically active racemic f = SN1 Nucleophilic substitution g = SN2 Nucleophilic substitution a = Proton transfer d = E1 Elimination b = Lewis acid/base e = E2 Elimination c = Electrophilic addition The rections above involve synthesis or reactions of alcohols and ethers. Identify the mechanism by which they proceed from among the mechanisms listed. Use the letters a - g for your answers. 1. 2.arrow_forwardOnly one of the chlorine atoms in the molecule, 3,4-dichloronitrobenzene, will undergo nucleophilic substitution. Indicate which position will react and provide the expected product for the given reaction using reaction intermediates (resonance structures).arrow_forward
- Functional groups such as alkynes react the same in complex molecules as they do in simpler structures. The following example of alkyne reaction were taken from syntheses carried out in the research group of E. J. Corey at Harvard University. You can assume that the reactions listed involve only the alkyne, not any of the functional groups present in the molecules. Draw the expected products for the following reaction .arrow_forward1. You are planning to carry out a reaction between butyne CH3CH₂C=CH, and sodium methoxide, CH3ONa. You also need to choose an appropriate solvent for the reaction. Would H₂O be an appropriate solvent? Explain your rationale.arrow_forwardCH3 CH3 Br- Br2 .CH3 CH2Cl2 CH3 H3C H3C Br Electrophilic addition of bromine, Brɔ, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl,. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 CH3 CH3 H3C H3C :Br: :Br:arrow_forward
- Compare the two reactions shown below. excess LICH,CH3 excess LICH,CH3 Both electrophiles, an ester and a ketone, are reacted with an excess amount of LICH2CH2. Which reaction will result in the formation of a product with the molecular formula C9H200 and why? O A: Only the reaction with the ester. LICH2CH3 results in an addition mechanism with both starting materials. However, the product from the ketone reaction contains fewer than 9 carbons. O B. Only the reaction with the ketone. LICH2CH3 results in an addition mechanism with both starting materials. However, the product from the ester reaction contains two oxygen atoms. O C. Both reactions. LICH2CH3 results in an addition mechanism with the ketone. However, the ester goes through a SNAC mechanism because it contains a leaving group, which allows two equivalents of LICH2CH3 to attack. O D. Neither reaction. LICH2CH3 results in a SNAC mechanism with both starting materials. Both products contain more than 9 carbons.arrow_forwardi need help drawing the productarrow_forwardA lab technician planned to synthesize 2-bromopentane using 2-pentanol, heat, and HBr. However, the labtechnician did not have HBr in the lab. What other reagent(s) can the technician use to synthesize 2-bromopentane using 2-pentanol as the starting material?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning

Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning