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15. The following technology allows multiple access using spread-spectrum technology and a different code assigned to each transmitter:a. CDMEb. 4Gc. GSMd. None of the provided options is correct 17. A Router with has two interfaces - one with 192.168.111.1/24 and another one with 10.20.5.1/24. In the routing table 127.0.0.1 is found. this entry is used for:a. A IPv6 addressb. A dynamic routec. Gateway addressd. The loop back address

1- Convert the following 8-bit binary number to decimal: 10110011 2- Convert the decimal number 254 to its binary equivalent 3- Given a network IP address of 192.168.5.0/ subnet mask 255.255.255.252, howmany subnets, and valid host IP addresses can be created?

Packet Tracer - Basic Device Configuration 10.4.3 Packet Tracer - Basic Device Configuration(1).pka Topology You will receive one of three possible topologies. Addressing Table Device Interface IP Address Default Gateway Floor14 G0/0 172.14.5.1/24 N/A Floor14 G0/0 2001:DB8:CAFE:1::1/64 N/A Floor14 G0/0 FE80::1 N/A Floor14 G0/1 172.14.10.1/24 N/A Floor14 G0/1 2001:DB8:CAFE:2::1/64 N/A Floor14 G0/1 FE80::2 N/A Room-145 VLAN 1 172.14.5.35/24 blank Room-146 VLAN 1 172.14.10.35/24 blank Manager-A NIC 172.14.5.50/24 blank Manager-A NIC 2001:DB8:CAFE:1::50/64 blank Reception-A NIC 172.14.5.60/24 blank Reception-A NIC 2001:DB8:CAFE:1::60/64 blank Manager-B NIC 172.14.10.50/24 blank Manager-B NIC 2001:DB8:CAFE:2::50/64 blank Reception-B NIC 172.14.10.60/24 blank Reception-B NIC 2001:DB8:CAFE:2::60/64 blank Objectives · Complete the network documentation. · Perform basic device configurations on a router and a…

ICMP is used for addressing error reporting routing forwarding Which of the following is an example of a private IP address? 12.127.18 65.20.10 169.200.224 100.20.2 ARP provides a mapping between IP addresses and MAC Addresses Domain Names Phone Numbers Network Addresses

16) a layer 4 connection, what action should a system take if it receives a synchronize packet? Send PSK No Action Send ACK Send CTS

If the IP address is 192.168.1.5 , the mask is 255.255.255.240,(1) convert the P address and mask in binary format, (2) give the class of the network, the number of bits for subnet, and the number of bits for hosts, (3) the (network id)/(\# of mask bit) in decimal format, (4) subnet broadcast address in decimal format, and (5) the range of valid hosts addresses in decimal format.

Explain in detail how a computer technician would go about statically setting up theIPv4 address 192.168.10.25 in Windows 10 with its default subnet mask and a Router and DNS address of 192.168.10.2

44. [Theoretical] A student has configured a software router and two workstations on a private LAN. He has set up the network with IP address 10.0.0.0 with subnetting that borrows bits 15, 16 and 17 (ONLY bits 15, 16 and 17, counting from the left) to create eight subnets (six useable).  The student has configured one workstation on the second useable subnet as the lowest available host IP address. The router has the highest usable address on this subnet for its interface connection to this network. The student has set up the other workstation using the 138th useable IP address on this subnet.   a. What are these three IP addresses in binary? b. What are these addresses in dotted decimal?

2 Given the IP address 192.168.0.0 and subnet mask 255.255.255.0, calculate the number of subnets and the number of hosts per subnet. Show your calculations

On Packet Tracer, Create your own NETWORK DESIGN (Science Building and U Building and G Building) 1. Have a Maximum of 3 Core Routers 2. Create your own IP Addressing 3. Implement VLAN  4. Implement Ether-Channel 5. Create VRRP/HSRP for redundancy 6. Each floor have 150 host

Lab - Build a Simple Network  Topology Addressing Table Device Interface IP Address Subnet Mask PC-A NIC 192.168.1.10 255.255.255.0 PC-B NIC 192.168.1.11 255.255.255.0 Objectives Part 1: Set Up the Network Topology (Ethernet only) Identify cables and ports for use in the network. Cable a physical lab topology. Part 2: Configure PC Hosts Enter static IP address information on the LAN interface of the hosts. Verify that PCs can communicate using the ping utility. Background / Scenario Networks are constructed of three major components: hosts, switches, and routers. In this lab, you will build a simple network with two hosts and a wireless router with at least two switchports. You will apply IP addressing for this lab to the PCs to enable communication between these two devices. Use the ping utility to verify connectivity. Required Resources 1 wireless router with at least two switchports 2 PCs running Windows with wired network cards installed 2…

ARP is necessary for the communication amongst the Hosts, justify this statement. Look at the following bits of ARP and clearly mention Source MAC Address, Destination MAC address, Type of ARP, Source IP & Target IP

Given the following IP Address 192.168.1.0/29 Write subnets, Broadcast Address, useable IP's, Block size and mask for each subnet.

You have been given the 192.168.34.0/24 address space to use in your network design. The network consists of the following segments: The Fa0/0 connected to router R1 will require enough IP addresses to support 97 hosts.  The Fa0/1 connected to router R1 will require enough IP addresses to support 72 hosts.     Assign the First valid host address of each subnet to the router interfaces. Assign the next valid host address of each subnet to PC’s.   For the first part, I understand that to accommodate 97 hosts, we need 128 user IPs which would be 7 bits for the host. I'm just lost on how to go from here.

55-  A network for a local office requires 4 LAN subnets as follows:      · Subnet A - North Office with 31 hosts;      · Subnet B - East Office with 15 hosts; and      · Subnet C - South Office with 7 hosts.      · Subnet D – West Office with 4 hosts.   Given the IP Address 192.168.15.0 /24 and above described network requirements: 1.     Design an optimal address scheme using Variable Length Subnet Mask (VLSM) method;    What will be the network address of Subnet C?  Select one: A. 192.16.15.128 B. 192.168.15.191 C. 192.168.15.96 D. 192.168.15.32

[ ] As the data packet moves from the lower to the upper  layers, headers are added. [ ] Every network device implements the transport layer.  [ ] In the Ring topology, each computer acts as repeater make error detection and boosts the signal before sending it on. [ ] In bus topology network media is inexpensive and easy to work with, so it is easier to trouble shoot than other topology. [ ] Error control only detects errors [ ] Ethernet is a LAN so it is placed in the second layer of the OSI reference model. [ ] UDP provides connectionless service and delivers packets quickly. In case of packet loss, UDP does not provide retransmission. [ ] UDP is the preferred over TCP for transferring a real-time voice over IP networks. [ ] In a bus topology, each station on the network is connected to two other stations, forming a loop or ring. [ ] IEEE international Telecommunication Union for creating protocols of internet. [       ] TCP protocol is slower than UDP?

1. Describe the steps involve in a distributed function using a simple carrier sense multiple access algorithm with an interframe space to transmit frame in a wireless LAN 2. Describe the 4 abstraction layer of TCP/IP 3. Describe a typical scenario involving 2 computer devices transferring a video file using an insecure ftp connection where tcp three way handshake is susceptible to vulnerability 4. Describe 4 units that makes IEEE 802.11 Architecture

Use VLSM to subnet the 128.153.0.0/22 network based on the following requirements shown on the topology diagram below. Subnets do not need to be provided for the router-to-router links.   Provide the network address, broadcast address, second usable IP address, as well as the subnet mask for each subnet. Provide the subnet mask in dotted-decimal notation (eg. 255.0.0.0). Subnet Network Address Broadcast Address Second Usable IP Address Subnet Mask A         B         C         D

How does STP (Spanning Tree Protocol) prevent or stop broadcast storms?a. It examines the source IP address field in each broadcast packet and temporarily blocks traffic from that address.b. It enables routers to choose one set of best paths and ensures that alternate paths are used only when the best paths are obstructed.c. It enables switches to calculate paths that avoid potential loops and artificially blocks the links that would complete a loop.d. It enables firewalls to keep access lists that name hosts known for high-volume broadcast traffic and block those hosts from transmitting to the network.e. It helps routers define the boundaries of a broadcast domain.

51-  A network for a local office requires 4 LAN subnets as follows:      · Subnet A - North Office with 31 hosts;      · Subnet B - East Office with 15 hosts; and      · Subnet C - South Office with 7 hosts.      · Subnet D – West Office with 4 hosts.   Given the IP Address 192.168.15.0 /24 and above described network requirements: 1.     Design an optimal address scheme using Variable Length Subnet Mask (VLSM) method; and   What will be the network address of Subnet A? Select one: A. 192.168.15.0 B. 192.168.15.32 C. 192.16.15.128 D. 192.168.15.1

Given each IP address and mask, supply the following information for each of these 9 examples: a) Size of the network part of the address (No. of network bits). b) Size of the subnet part of the address (No. of subnet bits). c) Size of the host part of the address (No. host bits). d) The number of hosts per subnet e) The number of subnets in this network f) The subnet address g) First address h) The broadcast address 1. 10.180.10.18, mask 255.192.0.0 2. 10.200.10.18, mask 255.224.0.0 3. 172.31.100.100, mask 255.255.224.0 4. 172.31.200.10, mask 255.255.248.0 5. 192.168.100.100, mask 255.255.255.240 6. 192.168.100.100, mask 255.255.255.248 7. 192.168.15.230, mask 255.255.255.252 1. Given each IP Address and Subnet mask, supply the following information for each of them: I. The class of IP Address II. Number of network bits III. Number of host bits IV. The appropriate subnet mask a) 10.10.2.1 number of hosts in the network 512 b) 172.160.10.2 number of hosts in the network 1200 c)…