MSIT 3250 Assignment 2 - Submission Sheet_Akhil_Banoth

Question 9  Convert the following IPv4 address into dot decimal address, and determine which type of these addresses are. a) 10000001 00001011 00001011 11101111 b) 11000001 10000011 00011011 11111111 c) 11100111 11011011 10001011 01101111   Computer network  Full explain this question

Change the following IPv4 addresses from binary notation to dotted-decimal notation.       I. 10000001    00001011    00001011     11101111       ii.11000001   10000011     00011011     11111111 Show the original (unabbreviated) form of the following IPv6 addresses. FDEC: 74 :  :  BOFF : 0 : FFFO 0 : 15 :  : 1 : 12 :1213 Explain the term Network Address Translation (NAT). What is the need for the network layer?  State four advantages that IPv6 has over IPv4

Determine whether or not the following IPv6 address notations are correct:•::0F53:6382:AB00:67DB:BB27:7332•7803:42F2:::88EC:D4BA:B75D:11CD•::4BA8:95CC::DB97:4EAB•74DC::02BA•::00FF:128.112.92.116

Provide the compressed format for each of the following IPv6 addresses. Show both rule I and rule 2 of your answer: (i) (ii) FE80:02BD:0000:0000:6000:8001:00A7:B220 2001:0B02:0FC6:0000:0000:0000:0050:A000 2001:6075:75A0:0000:0000:0000:0009:ABBC

A 4000 octet user data is to be transmitted over a network which supports a maximum user data size of 536 octets. Assuming the header in each IP data gram requires 20 octets, derive the number of datagrams (fragments) required and the contents of the following fields: Identification Total length Fragment offset More Fragments flag

Show your work for the following conversion.  a) Convert the following block of IP addresses into CIDRized addresses:  11000110 10110111 10100000 00000000  to 11000110 10110111 10111111 11111111

Which of the following instructions falls in the category of data transfer instructions? JUMP LOAD ROTATE AND

Short Answer Questions Apply Rule 1 and Rule for the following IPv6 Addresses a) 3FFF:FF00:0000:0000:ACAD:0000:0000:0127 b) 3ABC:0001:ACAD:0000:0000:1234:0000:0005 c) 3FFF:FF00:0000:0000:ACAD:0000:0000:0127 Apply EUI-64 Process and generate interface id. d) 00:00:5E:00:53:AF Your answer

Thanks

13. The following figures plot the timeline for sending TCP segments by host A and TCP ACKS by host B, where “seq #” is the value of the sequence number in the TCP header, and "ACK #” is the value of the acknowledge number in the TCP header. Assume that every segment always includes 500 bytes of data, excluding the TCP header. A seg #: 1000 seq #: 1500 seq #: 2000 seq #: 2500 (1) B ACK #: a ACK #: b ACK #: c ACK #: d A seq #: 1000 seq #: 1500 seq #: 2000 seq #: 2500 (2) B ACK #: r ACK #: s TACK 1) In Figure (1), the second ACK sent out by host B gets lost in the network. a) What are the acknowledge numbers a, b, c, and d? b) Will sender A think the segment with seq#=1500 was lost because it never receives the acknowledgement from B containing ACK# = b? 2) In Figure (2), the second TCP segment from host A to host B gets delayed in the network but later arrives at B. What should be the value for the ACK number r, s and t?

Provide short answers to the following: How do you determine whether an IP address is a multicast address? What is the TTL field in the IP header used for? What is the maximum length of options bytes that can be carried in an IPv4 header? Why do we have to multiply the offset field of an IP datagram by eight to obtain the real offset for the first byte of the datagram?

Subject rcs511  In an IPv4 datagram, the M bit is 0, the value of HLEN is 10, the value of total length is 400 and the fragment offset value is 300. The position of the datagram, the sequence numbers of the first and the last bytes of the payload, respectively are

Q' Figure below shows the IPV4 datagram format. Fill the fields from 1 to 5 by choosing the right answers 2 16-bit identifier ID flags 3 4 32 bit source IP address 5 options Data (variable length, typically a TCP or UDP segment) 1- Field (1) is for: a- Time to live b- IP protocol version number c- Type of service d- Header checksum e- Upper layer protocol f- None of them 2- Field (2) is for: a- Time to live b- IP protocol version number c- Type of service d- Header checksum e- Upper layer protocol f- None of above 3- Field (3) is for: a- Time to live b- IP protocol version number c- Type of service d- Header checksum e- 32 bit destination IP address f- None of them

Just answer please without explanation

Determine what link interface the destination address of DA:  Please refer to image

Assume the maximum transmission unit (or MTU) of an IP packet on 100 Mbps Ethernet is set at 1500 bytes. Also, assume we are sending our file using IPv6 at the Network layer and UDP at the Transport layer. A typical IPv6 header consists of 40 bytes, a UDP header consists of 8 bytes. Answer the following three questions based on the information provided above. For all answers, enter a decimal integer value without formatting (no commas). 1. How many packets do we have to send in order to transfer a file of 24KB over 100 Mbps Ethernet? packets 2. How many bytes do we have to send at the network layer in order to transfer the above file entirely? bytes 3. How many bytes do we have to send at the data link layer in order to transfer the above file entirely? Assume that the Ethernet header is 14 bytes and the frame checksum is 4 bytes. bytes

Write the following

Answer the following questions based on the concept of IPV6 Addressing Valid / If invalid, give your S# IPV6 Address Invalid comment а. 1200:0000:AB00:1234:0000:2552:7777:1313 b. ABCD:2673:ABCD:EFAB:1234:5678:9ABC:7362 с. 1200::AB00:1234::2552:7777:1313 d. FFFF:AAAA:BBBB:CCCC:DDDD:EEEE:FFFF:1111 Apply Only Rule 2 е. 1000:0001:0001:1000:0001:1000:0001:0000 f. 91CA:DED3:ABCO:2F8B:02AA:0CFF:FD28:9DDA Apply only Rule 1 g. FC00:0000:0000:0000:8E00:1275:0000:0084 h. 2000:0000:0000:0000:0000:ABCD:0000:0025

IP datagrams on a specific network can carry a maximum of only 440 bytes in the data portion. A node on this network, running an application using TCP generates a TCP segment with 1,900 bytes in the data portion. How many IP packets are transmitted to carry this TCP segment, and what are their sizes (including the header of 20 bytes)?

In a TCP data packet, if the sequence number has the value 001111, ACK number has the value 010110 and the urgent pointer has the value 001100 assuming that URG flag is set. What is the last urgent byte in the data section of the packet? All numbers are in binary.

Match the addresses to their corresponding address type.

1) Show the shortest (abbreviated) form of the following IPv6 address: a. 2340:0000:006B:0000:0000: 0000:1328:0000 b. 2001:00BD:3C00:0015:0000:0000:1A20:002B C. 0010:0000:3003:0000:0000:0001:0000:0123

2.

For a given an IP v4 datagram, with header fields: HLEN - 5. Total length - 2220 and flag field (RDM) - 000. If this datagram is required to pass through a network of MTU - 1164 byte and need to be fragmented, choose the correct answer 1_For the given packet, the header size is 10 bytes 20 bytes 40 bytes 30bytes 2_The number of fragments to which the given packet is fragmented to pass through the network of MTU: 164: three Tour two Six Network Ineed answer after 30 min

Every host in an IPv4 network has a 1- second resolution real-time clock with battery backup. Each host needs to generate up to 1000 unique identifiers per second. Assume that each host has a globally unique IPv4 address. Design a 50-bit globally unique ID for this purpose. After what period (in seconds) will the identifiers generated by a host wrap around?

The given IPV6 subnet address is 2001:0DA7:FF00:FAF8: :/64. • Use the above IPV6 address for Subnet 0. • Increment the subnet field by 1 and find the IPV6 address for the remaining subnets. • Write simplified IPV6 address. Subnet IPV6 network address (Write simplified IPV6 address) Number 1 3. Complete the 2 following IPV6 addressing table 3 using IPV6 subnetting. Follow the instructions given below and write the IPV6 address in the table.

Answer with handwriting ple

e) Rewrite the following IPv6 address in abbreviated notation: FE80:0000:0000:8888:12E6:1000:0000:0001/64. marks] What is its prefix? [2

Refer to the network figure above, showing two Ethernet Subnets connected through an IP Router, answer the following question 1-5. The devices in each subnet are connected locally to each other through layer two intermediate devices such as Ethernet switch and ethernet hub. For each device in the subnets, both its Internet Protocol (IP )address and its MAC address (also called the Physical address or the Ethernet address are shown. The subnet mask used by all devices is 255.255.255.240 (which is the same as the prefix length “/28”). 1. If Client #1 wants to send a broadcast packet to all the devices on the left subnet (containing client #1, client #2, client #3) what destination IP address should be used? (Mention in both binary and decimal format.)  2. What is the first and last assignable IP address for the left subnet above (containing client #1 and #3)? (Mention in both binary and decimal format.)

P27. Host A and B are communicating over a TCP connection, and Host B has already received from A all bytes up through byte 126. Suppose Host A then sends two segments to Host B back-to-back. The first and second segments contain 80 and 40 bytes of data, respectively. In the first segment, the sequence number is 127, the source port number is 302, and the destination port number is 80. Host B sends an acknowledgment whenever it receives a segment from Host A. In the second segment sent from Host A to B, what are the sequence number, source port number, and destination port number? If the first segment arrives before the second segment, in the acknowledgment of the first arriving segment, what is the acknowledgment number, the source port number, and the destination port number? If the second segment arrives before the first segment, in the acknowledgment of the first arriving segment, what is the acknowledgment number? Suppose the two segments sent by A arrive in order at B.…

2) In an IPV4 packet, the value of the HLEN field is 1100 in binary. How many bytes of options field is being carried by this packet? a) 28 byte b) 20 byte c) 8 byte d) 40 byte

In IPV4, consider sending a 4,000 byte datagram (20 bytes of IP header) into a link that has an MTU of 1,500 bytes. The datagram will be allocated to fragments, and the offset value of the third segment is 3, 370 3, 185 4, 185 4, 370

Show the shortest and original (unabbreviated) form of the following addresses. a. 2340:0000:0000:0000:0000: 119A:AOO1:0000 0000:0000:0000:2340:0000:0000:0000:0000 0::0 0:AA::0 Is it possible that a host with IPv6 can communicate with a host of IPv4? Explain

Total length of IP datagram = 3620, (including 20 bytes of header). Apply IP fragmentation for following transmissions. a) Host A sends data to R1 with MTU = 3800 b) R1 Transmits data to R2 with MTU = 1800

List the three auxiliary protocols at the network layer of the TCP/IP suite that are designed to help the IPv4 protocol. When an IP datagram is travelling between networks, can the value of the TTL field in the IP datagram be any of the following? Explain your answer. 23 0 1 301 Which field(s) in the datagram are responsible for gluing together all fragments belonging to the original datagram?

For IP address: 175.30.101.205, use the provided version of the subnet mask to calculate the: slash notation binary subnet mask dotted decimal subnet mask Increment Network ID Broadcast ID Host Range Complete the Increment by determining the value of the last network bit for the given subnet mask. It is easiest to observe in the binary representation. Since network IDs will always be multiples of the increment (after the zero subnet) – in the octet that holds the last network bit, use the increment to determine the network ID, broadcast, and host range for the IP address displayed above