MSIT 3250 Assignment 2 - Submission Sheet_Akhil_Banoth

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Jan 9, 2024

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MSIT 3250 –Assignment #2 Answer Submission Sheet IP Network Identification Exercise 1a For the following IP Address displayed in CIDR notation, determine the Network Identifier in Base-2: 114.35.138.223/20 Answer: 114.35.138.223/20 114.35.138.223 in binary: 01110010 00100011 10001010 11011111 First 20 bits are the network identifier: 01110010 00100011 1000 Network Identifier in Base-2: 01110010001000111000 Exercise 1b For the following IP Address displayed in CIDR notation, determine the Network Identifier in Base-2: 146.24.228.11/13 Answer: 146.24.228.11/13 146.24.228.11 in binary: 10010010 00011000 11100100 00001011 First 13 bits are the network identifier: 1001001 00011000 Network Identifier in Base-2: 1001001000011 Exercise 2a For the following IP Address, identify the Network Address and Broadcast Address: 28.132.93.17/27 Answer: 28.132.93.17/27 28.132.93.17 in binary: 00011100 10000100 01011101 00010001 First 27 bits are the network identifier: 00011100 10000100 01011101 000 Network Address: 28.132.93.0 Broadcast Address: 28.132.93.31
MSIT 3250 –Assignment #2 Answer Submission Sheet IP Network Identification Exercise 2b For the following IP Address, identify the Network Address and Broadcast Address: 00110100 11000010 00101011 01010110 (9 bits for Network Identifier) Answer: 00110100 11000010 00101011 01010110 (9 bits for network identifier) Network Identifier: 00110100 11000010 0010100 Network Address: 00110100 11000010 00101011 Broadcast Address: 00110100 11000010 001010111 Exercise 3a For the following IP Address, identify the Network Address: 177.224.132.227/26 Answer: Network Address: 10110001.11100000.10000100.11000000 In decimal form, this is: Network Address: 177.224.132.192 Exercise 3b For the following IP Address, identify the Network Address: 177.224.132.227/8 Answer: Network Address: 10110001.00000000.00000000.00000000 In decimal form, this is: Network Address: 177.0.0.0 So, the network address for the IP address 177.224.132.227/8 is 177.0.0.0. Exercise 3c For the following IP Address, identify the Network Address: 177.224.132.227/18
MSIT 3250 –Assignment #2 Answer Submission Sheet IP Network Identification Answer: Network Address: 10110001.11100000.10000000.00000000 In decimal form, this is: Network Address: 177.224.128.0 So, the network address for the IP address 177.224.132.227/18 is 177.224.128.0. Exercise 4a Represent the following CIDR mask length in dotted decimal notation: /8 Answer: The CIDR mask length "/8" is represented as the subnet mask 255.0.0.0 in dotted decimal notation. /12 Answer: The CIDR mask length "/12" is represented as the subnet mask 255.240.0.0 in dotted decimal notation. /27 Answer: The CIDR mask length "/27" is represented as the subnet mask 255.255.255.224 in dotted decimal notation Exercise 4b Represent the following dotted decimal subnet masks in CIDR mask length format: 255.224.0.0 Answer: /11 248.0.0.0 Answer: /5
MSIT 3250 –Assignment #2 Answer Submission Sheet IP Network Identification 255.255.255.240 Answer: /28 Exercise 5a Determine whether the following IP Addresses are on the same network. Be sure to show your work for full credit: 146.16.221.19/28 146.16.221.34/28 Answer: To determine whether the IP addresses are on the same network, we need to compare their network addresses. Here are the steps to calculate the network address: 1. Convert each IP address to binary: 10010010.00010000.11011101.00010011 146.16.221.19 10010010.00010000.11011101.00100010 146.16.221.34 2. Apply the subnet mask (prefix length /28) to each IP address: 10010010.00010000.11011101.00010000 146.16.221.16 10010010.00010000.11011101.00100000 146.16.221.32 3. Compare the network addresses to determine whether the IP addresses are on the same network: The IP addresses 146.16.221.19 and 146.16.221.34 have different network addresses (146.16.221.16 and 146.16.221.32, respectively). Therefore, they are not on the same network. Exercise 5b Some of the below IP Addresses may be on the same network. Determine which, if any, are. Be sure to show your work for full credit: a) 10.129.33.127/11 b) 00001010 10000111 00100001 10000001 (11 bits of mask length) c) 10.135.33.128/11 d) 00001010 10001001 00100010 00001100 (11 bits of mask length) e) 10.126.32.223/11 f) 11.17.32.33/11
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