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School

Rio Salado Community College *

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Course

112

Subject

Electrical Engineering

Date

Feb 20, 2024

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docx

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Uploaded by ChefLemurPerson1026

PHY112 Lab 4 Name: Dami Esan Capacitors Section PHY 112 MEID: olu2158910 38/40 Access the PhET Capacitor Lab Simulation . Click the Play button and select the option to “Run CheerpJ Browser- Compatible Version”. Use the simulation to answer all the following questions. Part 1 – Capacitance 1. Check the boxes marked plate charge and voltmeter. Move the red voltmeter lead so that it touches the top plate, and move the black voltmeter lead so that it touches the bottom plate. Your simulation should look something like this:

2. Move the slider on the battery up to change the voltage between the capacitor plates. The voltage between the plates will match the voltage of the battery. Record the voltage and the resulting stored charge. Measure six different values and complete the data table below: Voltage ( V ) Stored Charge ( C ) 0 0 0.34 0.30 * 10 -13 0.38 0.34 * 10 -13 0.68 0.60 * 10 -13 0.82 0.73 * 10 -13 1.5 1.3 * 10 -13 3. Use Excel, another spreadsheet, or a graphing program to create a scatter plot graph of voltage versus charge data. Graph the voltage on the horizontal axis and the stored charge on the vertical axis. Make sure that your graph has an appropriate title and that you properly label both axis. Apply a linear fit to your graph and include the equation. Copy and paste your graph below:

0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 0 0 0 f(x) = 0 x + 0 R² = 0.96 Voltage (V) vs Stored Charge (C) Voltage (V) Stored Charge (C) It looks like your last point is the one that is throwing off your results. That last graphed point doesn’t match you’re the charge value in your data table of 1.3E-13 C. (-1)

4. Check the capacitance box on your simulation. How does the capacitance compare to the slope of your graph? What is the physical meaning or the significance of the graph slope? 5. If the voltage applied by the battery doubles, what happens to the amount of charge stored on the plates and the capacitance of the capacitor? 6. If you double the plate area, by what factor does the capacitance change? Explain the reason for this change. Don’t explain the math but explain the theory behind the math. The capacitance is greater than the slope of my graph. Capacitance is demonstrated by the equation Q=CV, where capacitance is proportional to the stored charge, meaning my graph’s slope is the capacitance. My graph shows a positive and slightly linear relationship between voltage and stored charge, mirroring the equation. Okay. Typically, this comes out much better than what you came up with. But you got the main point. If you had plotted that last point correctly, then the slope would have matched the simulation capacitance If the voltage doubles, the charge of the plates will double, but the capacitance will remain constant as the plate area is also constant. Correct Doubling the plate area of a capacitor reduces the charge repulsion and increases the energy storage. The capacitance is directly proportional to the plate area, so it also doubles. Good

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