LW6 - NPN and PNP BJT Characterization
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Electrical Engineering
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Dec 6, 2023
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College of Engineering and Applied Science
Department of Electrical Engineering and Computer Science
EECE 2070L LW6 NPN and PNP BJT Characteristics Background:
Diodes, NPN and PNP BJTs can be characterized using a device called a curve tracer. We have two of these devices in the department, they are very useful for quickly characterizing a Semiconductor device that has been designed by researchers. However often in industry this device is a luxury because of its limited use and high price tag. In this lab you will learn how to use a DMM to perform a test on a BJT that will ensure that it is still functional. You will also characterize an NPN and PNP transistor using the Analog Discovery 2 curve tracer board. Objective: Observe the relationship between the collector current and the base current for the 2N3904 NPN and the 2N3906 PNP Bipolar Transistor (BJT). Procedure:
Part 1: Diode Functionality Test
Some DMMs have an h
fe measurement, like the DMM in your kit. 1.
Using the DMM in your kit use the h
fe measurement, keep in mind these are not the best meters and it might not work. Either way, I need you to record what screen displays and take a picture of it. If you do not have it with you, borrow one. a.
DMM h
fe measurement = 207
h
fe
1b
EECE 2070L
Updated Sept 2023
College of Engineering and Applied Science
Department of Electrical Engineering and Computer Science
Measured value of hfg for the NPN transistor using handheld DMM. Figure 0: DMM hfg measurement
The Diode check function of DMM can be used to test if a BJT is operational. This works 99.9 percent of the time. There has been only one instance in over 8 years where the transistor was faulty, and this test said it was OK. The curve tracer characterization of that BJT indicated it was faulty. A BJT has three regions, in the case of an NPN BJT, you have small lightly doped P-type material at the Base sandwiched between a heavily doped N-type Emitter and lighter doped N-
type Collector. A diode has just the N and P type material sandwiched together. This means that the diode test can be used to verify that these junctions are still intact. Figure 1 is a schematic of a NPN test example. In the reverse bias a word should be displayed, type that word in the table provided. 1.
Using the Diode Test on the DMM, Test a 2N3904 NPN BJT and record the junction combinations of transistor listed in Figure 2.
2b
EECE 2070L
Updated Sept 2023
College of Engineering and Applied Science
Department of Electrical Engineering and Computer Science
Q1
2N3904
B
E
C
B
C
E
XMM1
Figure 1: NPN Forward Bias Base to Emitter Test Example
NPN Test
Base/Collector Junction
Base/Emitter Junction
Positive lead on the Base
.70v
.70v
Negative lead on the base
Open
Open
Figure 2: NPN Diode Test Results
2.
Using the Diode Test on the DMM, test a 2N3906 PNP BJT and record the junction combinations of transistor listed in Figure 4.
Q1
2N3906
B
E
C
B
C
E
XMM1
Figure 3:
PNP Forward Bias Base to Emitter Test Example
PNP Test
Base/Collector Junction
Base/Emitter Junction
Positive lead on the Base
Open
Open
Negative lead on the Base
0.74v
0.74v
Figure 4: PNP Diode Test Results
Part 2: Curve Tracing using the Analog Discovery 2 (AD2)
Connect the AD2 to your laptop with the USB cord. Next plug the transistor into the breadboard so each pin is in its own row. Wire each transistor pin to the correct terminal ensuring that none of the wire insulation is caught in the connection clamp as seen in Figure 5. 3b
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Figure 5: Connection Example
3.
Next open the Waveforms software and follow the video on how to set up the WaveForms
transistor test. Use units of milliamps for current and round each value to 2 decimal places. Record your data in Figure 6. Depiction of the voltage and amperage of NPN Transistor Wave form for varying Vce and Ic. I
C
Ide
al
At V
CE = 4v
At V
CE = 5v
At V
CE = 6v
I
C
I
B
V
BE
V
C
E
I
C
I
B
V
BE
V
C
E
I
C
I
B
V
BE
V
CE
1.5
m
A
1.380
9mA
7.690
4 uA
0.67
183v
3.95
79v
1.380
9mA
7.723
7uA
0.67
183v
5.05
52v
1.417
6mA
7.6911
uA
0.67
15v
6.05
02v
2m
A
2.114
2mA
0.011
63mA
0.68
319v
3.97
98v
2.150
9mA
0.011
67mA
0.68
319v
4.97
84v
2.187
5mA
0.0116
7mA
0.68
319v
5.97
34v
3.5
m
A
3.397
5mA
0.018
17mA
0.69
554v
3.96
15v
3.397
5mA
0.018
14mA
0.69
521v
5.05
52v
3.434
1mA
0.0182
mA
0.69
521v
5.95
14v
4m
A
4.204
1mA
0.022
56mA
0.70
155v
3.97
62v
4.204
1mA
0.022
56mA
0.70
122v
5.06
99v
4.247
mA
0.0225
6mA
0.70
089v
5.96
61v
Figure 6: NPN I
C
Data 4.
Once your data is recorded. Take a screenshot of the entire UI (I want to see the settings and both axes) with traces visible. Insert it below give it an introduction sentence and caption. Your screen shots should look similar to the operating region of characteristic curves in your textbook on page 297 Figure 5.14
4b
EECE 2070L
Updated Sept 2023
College of Engineering and Applied Science
Department of Electrical Engineering and Computer Science
Trace curve of NPN transistor depicting values for Ic ideal equals 1.5mA and Vce ideal equals 4v.
Figure 6.1: NPN I
C
Data Trace Curve
5.
Using your data from Figure 6, calculate Beta (β) where, β
=
I
C
I
B
(1)
for all the Measured I
C
/I
B
combinations above. Fill in the table in Figure 7 with your derived Beta measurements. (A derived measurement is a value calculated from measurements with no assumed or “ideal” values in the calculation). I
C Ideal
Ideal β
From
Prework
β @
V
CE = 4V
β @
V
CE
= 5V
β @
V
CE
= 6V
5b
EECE 2070L
Updated Sept 2023
College of Engineering and Applied Science
Department of Electrical Engineering and Computer Science
1.5mA
145
180
179
184
2mA
150
182
185
189
3.5mA
160
188
188
189
4mA
165
188
188
189
Figure 7: NPN Beta Calculation Data
There could be significant differences between your calculated and measured values. This is okay … to an extent. If you calculate a Beta over 270 ask your in instructor or TA if it is okay. 6.
Remove the 2N3904 NPN transistor and replace it with the 2N3906 PNP transistor. Change the transistor type from NPN to PNP in the dropdown menu next to the RUN button in the Waveforms UI. You may need to adjust settings a little I would run it with your previous settings before adjusting anything. I
C
Id
eal
At V
CE = 4v
At V
CE = 5v
At V
CE = 6v
I
C
I
B
V
B
E
V
C
E
I
C
I
B
V
B
E
V
C
E
I
C
I
B
V
BE
V
CE
1
m
A
-
1.18
55m
A
-
8.41
816u
A
-
0.6
745
7v
-
3.9
834
3v
-
1.22
219
mA
-
8.45
147u
A
-
0.6
745
7v
-
5.0
808
v
-
1.258
85m
A
-
8.41
816u
A
-
0.6
745
7v
-
5.9
769
9v
2.
5
m
A
-
2.68
874
mA
-
0.01
654
mA
-
0.6
926
v
-
4.0
309
9v
-
2.72
54m
A
-
0.01
655
mA
-
0.6
922
7v
-
4.9
235
1v
-
2.798
73m
A
-
0.01
658
mA
-
0.6
722
7v
-
5.9
184
6v
3
m
A
-
3.23
87m
A
-
0.01
943
mA
-
0.6
972
8v
-
3.9
761
2v
-
3.34
869
mA
-
0.01
947
mA
-
0.6
966
1v
-
5.0
698
3v
-
2.835
39m
A
-
0.01
658
mA
-
0.6
922
7v
-
6.0
172
3v
4.
5
m
A
-
4.37
528
mA
-
0.02
535
mA
-
0.7
042
9v
-
4.0
602
5v
-
4.48
527
mA
-
0.02
535
mA
-
0.7
039
5v
-
5.0
515
4v
-
4.595
26m
A
-
0.02
538
mA
-
0.7
036
2v
-
6.0
428
3v
Figure 8: PNP I
C
Data 6b
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Trace curve of PNP transistor depicting values for Ic ideal equals 4.5 mA at Vce ideal equals 6v.
Figure 9.1: PNP I
C
Data Trace Curve 7.
Using your data from Figure 8, calculate Beta (β) where, 7b
EECE 2070L
Updated Sept 2023
College of Engineering and Applied Science
Department of Electrical Engineering and Computer Science
β
=
I
C
I
B
(1)
for all the Measured I
C
/I
B
combinations above. Fill in the table in Figure 6 with your derived Beta measurements. (A derived measurement is a value calculated from measurements with no assumed or “ideal” values in the calculation). I
C Ideal
Ideal β
From
Prework
I
B Ideal
From
Prework
β @
V
CE = 4V
β @
V
CE
= 5V
β @
V
CE
= 6V
1mA
150
.0067mA
140
145
150
2.5mA
150
.0167mA
163
165
170
3mA
155
.0194mA
167
173
172
4.5mA
155
.0290mA
173
177
182
Figure 10: PNP Beta Calculation Data
Principles of Operation: 1.
Within its operating range, what kind of source (voltage or current) does a BJT act like? How is it controlled? Explain.
A BJT acts like a current source when it’s in its operating range because the output current is dependent on the input currents which is given by the ratio of I
C
I
B
. A BJT uses the base current in order to control the flow of current from the emitter terminal to the collector end of the BJT.
Analysis: Using data from Figure 7, calculate the percent error between the Ideal beta you found on the
Data sheet and your derived measurements from lab. Show one example calculation typed out
with values from your data and then present your present error data in table below it. ¿
Theoretical
−
Experimental
∨
¿
Theoretical
∗
100%
%
Error
=
¿
¿
145
−
180
∨
¿
145
∗
100%
=
24.14%
%
Error
=
¿
Percent
Error β @
V
CE = 4V
Percent
Erro β @
V
CE
= 5V
Percent
Error β @
V
CE
= 6V
24.14%
23.45%
26.9%
21.33%
23.33%
26%
17.5%
12.5%
18.13%
14.0%
14.0%
14.55%
8b
EECE 2070L
Updated Sept 2023
College of Engineering and Applied Science
Department of Electrical Engineering and Computer Science
1.
Using data from Figure 9, calculate the percent error between the Ideal beta you found on
the Data sheet and your derived measurements from lab. Show one example calculation typed out with values from your data and then present your present error data in table below it. 2.
¿
Theoretical
−
Experimental
∨
¿
Theoretical
∗
100%
%
Error
=
¿
3.
%
Error
=
|
150
−
140
|
150
∗
100%
=
6.67%
I
C Ideal
Ideal β
From
Prework
Precent
Error β @
V
CE = 4V
Percent
Error β @
V
CE
= 5V
Percent
Error β @
V
CE
= 6V
1mA
150
6.67%
3.33%
0%
2.5mA
150
8.67%
10.0%
13.33%
3mA
155
7.74%
11.61%
11.61%
4.5mA
155
11.61%
14.19%
17.42%
Conclusion: 1.
How does the DMM test at the beginning of the lab help you with future lab experiments?
The DMM test will help in future labs to help troubleshoot. For example, we can use the test to see if our transistor or diode are even working using the diode test. Since our components are bought in bulk, some of the components may not even work as intended in the first place.
2.
In lab I typically use 0.7v for the base-emitter voltage drop (V
BE
). Looking at the V
BE
data
in Figures 6 and 8, based on your data:
a.
Do you feel this is still a safe design assumption? Why or why not?
Yes, because if you look at both figure 6 and 8, the V
BE
values tend to be right around the 0.7v range.
9b
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b.
Have you used a different value in your lecture class? If yes, what was/is it? Yes, in lecture we have used values such as 0.6 to solve example problems.
Appendix:
10b
EECE 2070L
Updated Sept 2023
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