Lab 2 PHY 105N
.pdf
keyboard_arrow_up
School
University of Texas *
*We aren’t endorsed by this school
Course
105N
Subject
Electrical Engineering
Date
Dec 6, 2023
Type
Pages
5
Uploaded by parkenmia
Lab 2: Lenses and Uncertainty Propagation
Part 1:
Equations
Optical Power →
𝑃 =
1
𝑓
Optical Equation →
1
𝑓
=
1
?
+
1
?
Equipment Chosen
PASCO light source, PASCO optics track, meter stick, convex lens, and screen
Intro + Prediction
According to the model, an object placed at “p” distance away from a lens will result in an image being
produced at a distance of “q” from the lens. Moreover, the p value is the distance between the object and the lens
and the q value is the distance between the lens and the image formed. The optical power equation above shows
that P is equal to
which is equal to
, and that P is a constant. Thus, in this experiment, we hypothesize
1
𝑓
1
?
+
1
?
that by placing an object at different locations and measuring the corresponding distances, p and q, our subsequent,
calculated P values will all be the same.
Method
To test our hypothesis regarding the fact that P is a constant, we will be using a convex lens to focus the
image from the PASCO light source onto the image screen on the optics track, and we will be using the included
meter stick on the optics track to measure p and q . We will conduct 3 trials per each lens over varying distances of
p and q to determine if the model is valid. We will then calculate P for each trial. To calculate the constant P, we
will propagate the uncertainties of p and q to find the uncertainty of P, δP. The uncertainty of q will be the range in
which the image begins to appear clear to where it begins to become blurry again. Our goal is to minimize this
uncertainty.
Data
CONVEX LENS
Trial
P (cm)
δ
p +/-
p (cm)
δ
q +/-
q (cm)
δ
P =
1
?
+
1
?
T-Scores
1
0.002
42.0 +/- 0.05
40.8 +/- 2.7
0.048
Trial 1&2 = 0
Measured optical power (P) is indistinguishable from
the original calculated value of the optical power.
2
0.008
67.4 +/- 0.05
30.0 +/- 7.3
0.048
Trial 1&3 = 0
3
0.001
35.4 +/- 0.05
50.0 +/- 2.8
0.048
Trial 2&3 = 0
Mean
0.004
0.048 cm
-1
Mean P:
= 0.048 cm
-1
0.048 + 0.048 + 0.048
3
Standard Deviation of P: 0.004 cm
-1
P = 0.048 +/- 0.004 cm
-1
Propagation of Uncertainty Equation:
δ𝑃 =
−1
?
2
×
δ?
(
)
2
+
−1
?
2
×
δ?
(
)
2
Sample Calculation
(Trial 1)
= 0.0016 → 0.002 cm
δ𝑃 =
−1
42.0
2
×
0. 05
(
)
2
+
−1
40.8
2
×
2. 7
(
)
2
GLASS BALL
Trial
P (cm)
δ
p +/-
p (cm)
δ
q +/-
q (cm)
δ
P =
1
?
+
1
?
T-Scores
1
0.16
9.6 +/- 0.05
5.0 +/- 4.1
0.048
Trial 1&2
0
2
0.03
8.4 +/- 0.05
7.0 +/- 1.6
0.048
Trial 1&3
0
3
0.01
5.0 +/- 0.05
10.0 +/- 1.1
0.048
Trial 2&3
0
Mean
0.067 cm
-1
0.048 cm
-1
Mean P:
= 0.048 cm
0.048 + 0.048 + 0.048
3
Standard Deviation of P: 0.067 cm
P = 0.048 +/- 0.067 cm
-1
Propagation of Uncertainty Equation:
δ𝑃 =
−1
?
2
×
δ?
(
)
2
+
−1
?
2
×
δ?
(
)
2
Sample Calculation
= 0.16 cm
δ𝑃 =
−1
9.6
2
×
0. 05
(
)
2
+
−1
5.0
2
×
4. 1
(
)
2
T-Score Calculations
●
Convex Lens
= 0
0.048 − 0.048
|
|
0.002
2
+ 0.008
2
= 0
0.048 − 0.048
|
|
0.002
2
+ 0.001
2
= 0
0.048 − 0.048
|
|
0.008
2
+ 0.001
2
●
Glass ball
= 0
0.048 − 0.048
|
|
0.16
2
+ 0.03
2
= 0
0.048 − 0.048
|
|
0.16
2
+ 0.01
2
= 0
0.048 − 0.048
|
|
0.03
2
+ 0.01
2
Conclusion
In this lab, we measured values of p and q using both a +200mm PASCO convex lens and a glass ball to
confirm if P, optical power, is truly constant. For each type of lens, three trials were conducted to find a P value,
and then we calculated the mean P value and the standard deviation of the mean to determine how much the P
values differed from each other between trials. Our goal was to minimize the uncertainty of our measurements in
order to ensure that our measured values of P are indistinguishable. To do this, we propagated the uncertainty and
calculated t-scores between our calculated P values to determine if they were indistinguishable or not.
All of our T-Scores between the P values of the glass ball and the convex lens were calculated to be 0. This
means that our calculated P-values are indistinguishable from one another and thus, our hypothesis was proved to
be valid. Moreover, our experiment proved that P is constant.
To minimize the uncertainty in our next experiment, we could implement numerous different techniques.
First, when determining the range of values over which the image is clear, we could be more precise in determining
this value which will lead to a smaller uncertainty in q and thus a smaller overall uncertainty for P. In addition,
more trials over a larger range of distances would be sufficient to minimize our uncertainty as well in future
iterations of this experiment.
Part 2:
Equipment Chosen
PASCO optics track, PASCO light source, eye model, eye model lens set
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Questions
how do you solve these missing parts??
WILL RATE.
( Please type answer note write by hend )
arrow_forward
Note: Please do not handwritten.
arrow_forward
4. Can you please respond to question in attached image? Thank you so much have a nice day.
arrow_forward
4) Listen
Calculate the voltage on the secondaty side: Given: Number of turns on the
secondary side is 3000 turns, voltage on the primary side is 0.48 kV, number of turns
on the primary śide is 2400 turns.
arrow_forward
Graph:
Take a graph sheet and divide it into 4 equal parts. Mark origin at the center of the graph sheet.
Now mark +ve X-axis as Vf, -ve X-axis as Vr, +ve Y-axis as Ifand –ve Y-axis as Ir.
Mark the readings tabulated for Si forward biased condition in first Quadrant and Si reverse biased condition in third Quadrant.
arrow_forward
Graph:
Take a graph sheet and divide it into 4 equal parts. Mark origin at the center of the graph sheet.
Now mark +ve X-axis as Vf, -ve X-axis as Vr, +ve Y-axis as Ifand –ve Y-axis as Ir.
Mark the readings tabulated for Si forward biased condition in first Quadrant and Si reverse biased condition in third Quadrant.
arrow_forward
The main feature of photo-detectors made of high energy gap semiconductors is that:
Select one:
O A. Their total current is extremely large.
O B. They have very small dark current.
O C. NON of the answers is correct.
O D. Their absorption coefficients are quite large.
O E. Thin samples are needed for such detectors
arrow_forward
Light of wavelength 589nm is used to view an object under a microscope. If the aperture of the objective has a diameter of 0.9cm and if the light is in the visible range, what would be the maximum limit of resolution for this microscope?
arrow_forward
Choose the correct answer
arrow_forward
Question 777
Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this line
arrow_forward
So the question becomes, how much of a contribution do solar cells make to GPS?
arrow_forward
A11
arrow_forward
An object with a height of -0.07 m points below the principal axis (it is inverted) and is 0.130 m in front of a diverging lens. The focal length of the lens is -0.34 m. (Include the sign of the
value in your answers.)
(a) What is the image distance?
(b) What is the magnification?
m
(c) What is the image height?
arrow_forward
The wave power per length is 1407 W/m, the device-width of the wave energy system is 7.5 m, the capture
width ratio is 0.4, the rated power is 12772 W. Determine the percentage degree of utilization.
29.74
28.09
33.05
O 36.35
arrow_forward
Choose the correct answer
arrow_forward
The distance difference between propagated
rays in an optical fiber cable should be
a. Integer multiple of rt
b. Integer multiple of /2
C.
None of the given answers
d. Integer multiple of A
e. Integer multiple of 2n
Clear my choice
arrow_forward
Thanks
arrow_forward
A laser with emission line
width B has been reduced
to two-thirds of its original
length. The number of N2
modes will be:
N2=(3/2) N1 O
N2 = N1
N2 = (2/3) N1
All options are wrong
arrow_forward
answer the following question. topic: oscilloscope
1. What is/are the function of the horizontal sensitivity (TIME/DIV)?
2.What is/are the function of the vertical sensitivity (V/DIV)?
3.. What are the functions of Oscilloscope? Function Generator?
arrow_forward
QUESTION 4:
i. A Laser is used in a network to transmit light from a source, with the aid of suitable diagrams, discuss the principles of operation of the injection laser.
ii. If a p–n photodiode is used at the receiver explain the detection process. Compare this device with the p–i–n photodiode.
iii. Given the optical fiber preform explain the drawing process of the fiber. What are the advantages and disadvantages of the drawing method used?
arrow_forward
Antenna for a 3GHz radar costs $100000 per mm physical antena area .aperature efficency is 88% and avilabale budget has $300000 what is the maximum gain that can be purchased for avialable budget SNR requried maximum range 300 kms what is the maximum total lose that this radar can sustain
arrow_forward
Difference between Lumen and Candela?
List down the advantages and disadvantages of using
the 3 different types of artificial
light.
What is cavity ratio (CR)? How to solve it?
What are effective cavity reflectances? How to solve
it?
What is the coefficient of utilization? How to solve it?
arrow_forward
this question related to Optoelectronics and Nanophotonics
a) List the wavelength ranges for the three optical communication windows andb) identify their sub bands (all in terms of wavelength). Finally,c) give two examples for the uses of each main optical communication window.
d) What is griffin ?What is important?
arrow_forward
Type your question here Define the Spectrum
arrow_forward
Consider a slab of silicon 5 um thick. Determine the percentage of photon
energy that will pass through the slab if the absorbtion cofficient is 10^3 cm-1
99.5%
91.5%
95.5%
90.4%
arrow_forward
Q1.)
A CRT deflection plates of (60mm) long and (0.5cm) apart. The screen is (22cm)
away from the center of deflection plates. The electrons enter the plates with velocity of
(2.445x10 m/sec). If an input signal is applied, it will produce (3cm) deflection on the screen
with an angular deflection of (7.77°). Determine:
1- Acceleration voltage.
2- Deflection potential.
3- The coordinate of electrons beam at the center of deflection plates.
4- The time taken by electrons beam in its traveling from the end of deflection plates to the
screen.
Note:
m= 9.1x10-³¹ kg
e=1.6x10-¹⁹C
arrow_forward
For a standard AM receiver with an RFcarrier of 1500 kHz and Q = 150, determine
a. Local oscillator frequency in MHz Blank 1
b. low inject Image frequency in kHz Blank 2
arrow_forward
Solve the following parts
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
Electricity for Refrigeration, Heating, and Air C...
Mechanical Engineering
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Cengage Learning
Related Questions
- 4) Listen Calculate the voltage on the secondaty side: Given: Number of turns on the secondary side is 3000 turns, voltage on the primary side is 0.48 kV, number of turns on the primary śide is 2400 turns.arrow_forwardGraph: Take a graph sheet and divide it into 4 equal parts. Mark origin at the center of the graph sheet. Now mark +ve X-axis as Vf, -ve X-axis as Vr, +ve Y-axis as Ifand –ve Y-axis as Ir. Mark the readings tabulated for Si forward biased condition in first Quadrant and Si reverse biased condition in third Quadrant.arrow_forwardGraph: Take a graph sheet and divide it into 4 equal parts. Mark origin at the center of the graph sheet. Now mark +ve X-axis as Vf, -ve X-axis as Vr, +ve Y-axis as Ifand –ve Y-axis as Ir. Mark the readings tabulated for Si forward biased condition in first Quadrant and Si reverse biased condition in third Quadrant.arrow_forward
- The main feature of photo-detectors made of high energy gap semiconductors is that: Select one: O A. Their total current is extremely large. O B. They have very small dark current. O C. NON of the answers is correct. O D. Their absorption coefficients are quite large. O E. Thin samples are needed for such detectorsarrow_forwardLight of wavelength 589nm is used to view an object under a microscope. If the aperture of the objective has a diameter of 0.9cm and if the light is in the visible range, what would be the maximum limit of resolution for this microscope?arrow_forwardChoose the correct answerarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Electricity for Refrigeration, Heating, and Air C...Mechanical EngineeringISBN:9781337399128Author:Russell E. SmithPublisher:Cengage Learning
Electricity for Refrigeration, Heating, and Air C...
Mechanical Engineering
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Cengage Learning