ABE 325 2018 Economics and Standards - KEY

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Purdue University *

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Industrial Engineering

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Jan 9, 2024

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ABE 32500 Soil and Water Resources Engineering 1 Economics and Standards Homework #14 (11 pts) 1. (2 pts) You take out a 10-year loan at 5% interest to pay for a $150,000 tractor. How much do you pay annually including interest over the life of the loan? How much interest do you pay on this loan? Using the amoritization table you get: 0.13 * $150,000 = $19,500 Interest is total payments minus original cost: 10 x $19,500 - $150,000 = $45,000 2. (2 pts) Use the techniques described in the video on Present Worth Analysis ( https://www.youtube.com/watch?v=4rZ-DPszlZE ) to determine which of the two systems described are more cost-effective over a 20 year life span given 7% annual interest: (A) A concrete lined channel that will cost $35,000 to build, must be resealed every year at a cost of $500, has an expected life-span of 20 years at which time is can be crushed and sold for $2,000 as fill material. (B) An earth lined channel that will cost $15,000 to build, must be mowed annually at a cost of $1,000, and dredged every 5 years at a cost of $8,000 per event. ࠵? ! = −35,000 − 500 ( (1.07) "# − 1 0.07(1.07) "# . + 2,000 (1.07) "# = −$39,780.17 ࠵? $ = −15,000 − 1000 ( (1.07) "# − 1 0.07(1.07) "# . − 8,000 (1.07) % 8,000 (1.07) &# 8,000 (1.07) &% 8,000 (1.07) "# = −$40,331.62 P A the concrete lined channel is slightly more cost effective (present worth is less) than P B the earth lined channel. 3. (2 pts) A farmer is contemplating adding irrigation to his fields at an added cost of $175 / acre / year. The expected yield benefit for the local Maumee soils is 35 bushels / acre, and the farmer expects to get $3.75 / bushel / year. Calculate the breakeven yield and the breakeven price. Would you advise the farmer to move forward with the investment in irrigation? Breakeven yield = $175 / $3.75 = 46.7 bushels / acre Breakeven price = $175 / 35 = $5.00 /bushel Cost of the irrigation system will require higher than projected price, or yield boost to be cost effective. Do not recommend for the farmer.
ABE 32500 Soil and Water Resources Engineering 2 5. (3 pts) Estimate the cost to construct a 2 acre pond with average depth of 10 ft on a sparsely forested property. You have a large excavator with a 4 cubic yard bucket. After excavation you must install an erosion control blanket to cover the pond rim to a width of 5 feet. Material must be removed from site. Use the 2015 engineering pricing guide for Howard County (posted to Blackboard under Term Project -> Cost Estimation Resources), and Figure A.17 from the Means Heavy Construction Handbook (same location). 6. (2 pt) Complete the vocabulary portion of the home on Blackboard. Pond area 2 acres 9680 square yards 4840 square yards to acre 87120 square feet 9 square feet per square yard Pond depth 10 ft Pond volume 20 acre-ft 32267 cubic yards 1613.33 cubic yards per acre-ft 871198 cubic feet 27 cubic feet per cubic yard Excavator Large Bucket 4 cubic yards Pond perimeter 1181 ft assume square pond 393.5 yards 1046 ft assume circular pond 348.8 yards Site Preparation Costs Clearing 3,370.00 $ per acre from 2015 guide for clearing sparse stand Total for clearing 6,740.00 $ Excavation Costs Excavation cost 3.92 $ per cubic yard from 2015 guide for clearing sparse stand Removal cost 41.00 $ per cubic yard from 2015 guide for clearing sparse stand material total 1,449,415.67 $ total for all removal Excavation rate 330 cubic yards per hour from Means Appendix A.17, assuming common earth Large Excavator 162.00 $ per hour from 2015 guide for large excavator Excavation time 97.8 hours Excavation time costs 15,839.97 $ Erosion blanket installation Width of blanket 2 yards erosion control blanket 2.00 $ per square yard from 2015 guide for installed erosion blanket blanket area 787.1 square yards square pond 697.5 square yards circular pond installation cost 1,574.19 $ square pond 1,395.09 $ circular pond Total estaimted installation cost 1,473,569.83 $ square pond 1,473,390.73 $ circular pond
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