Statics_Practice_Problems_Set_5_Solution (1)

Please solve as fast as:

Find moment of inertia of the cross-sectional area about the X-axis, Y-axis, and X'-axis, given:  L1 = 60 mm,   L2 = 20 mm,   L3 = 60 mm,   L4 = 90 mm

H mm Bmm dmm find the moment of inertia about x-axis B=46 mm H=176 mm d= 20 mm

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Solve it correctly please. I will rate accordingly

Find the moment of inertia about centroidal X-axis and centroidal Y-axis of the given geometry Figure.

Find the moment of inertia about centroidal X-axis and centroidal Y-axis of the given geometry Figure: 2a and 2b

2. Compute for the moment of inertia about xo and yo of the following figures. a) b) y 100 mm 100 mm 75 mm y 25 mm 120 mm 50 mm 75 mm 180 mm | = |1 - 12 |= 11 + 12

Use the given values in problem to answer the following:  Find the moment of inertia and radius of gyration of the section of this bar about an axis parallel to x-axis going through the center of gravity of the bar. The bar is symmetrical about the axis parallel to y-axis and going through the center of gravity of the bar and about the axis parallel to z-axis and going through the center of gravity of the bar.   The dimensions of the section are: l=51 mm, h=29 mm The triangle: hT=15 mm, lT=18 mm and the 2 circles: diameter=7.4 mm, hC=8 mm, dC=7 mm. A is the origin of the referential axis. Provide an organized table and explain all your steps to find the moment of inertia and radius of gyration about an axis parallel to x-axis and going through the center of gravity of the bar. Does the radius of gyration make sense? In the box below enter the y position of the center of gravity of the bar in mm with one decimal.

Find the moment of inertia of the shape in the figure 90 mm 30 mm 30 mm 90 mm Empty (-) |=3200000 mm4 None of them I=5400000 mm4 |=4920000 mm4

2. Please calculate the moment of inertia values for each figures according to the defined rotation axises. Long, thin rod with rotation axis through center Long, thin rod with rotation axis through end ML² I = ! ML² Solid sphere Thin spherical shell ICM = MR² ICM = 2 MR² R R

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Find the moments of inertia of the shaded shape about the given centroidal x-axis (Ix) and centroidal y-axis (I). The equations for a single rectangle's moment of inertia about its own centroidal axis is given below. 4 h + y с A = bh Rectangular area X I₂ = 1/2bh³ bh³ Iy = 1 in 2 in 2 in y 1 in 2 in y' x' 2.375 in X

The moment of inertia of a triangle of base 'b' and height 'h' about Y - Y axis passing through its center of gravity is Select one: dh³/36 bh/36 bh³/12 dh³/12 Shear forces and friction forces always acts along the surfaces and are an example of indirect forces. Select one: True False

2 Show the Moment of Inertia About an Arbitrary Axis IAa = Įxxu} + Iyyu²} + IzzU² − 21xyUxUy − 21yzUyUz — ŽIzxUzUx - - dm b = r sin e

From the given figure, determine the following: a. Moment of Inertia along x and y with respect to the given axis b. Moment of Inertia along x and y with respect to the centroidal axis c. Polar Moment of inertia with respect to the given axis d. Polar Moment of inertia with respect to the centroidal axis

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5 Parallel axis theorem transfer the moment of inertia of a area from its own axis to another perpendicular axis Select one: True False

Answer is wrong. Please proviode correct answer

Compute for the moment of inertia about xo and yo of the following figure

wrong

The moment of inertia of a body is also called as second moment.   Select one: True False

For the section below: а. Determine the moment of inertia with respect to the X-axis. b. Determine the moment of inertia with respect to the Y-axis. C. Determine the moment of inertia with respect to the X'-axis. 40 mm 80 80 30° tw = 40 mm 40 mm 200 mm 9. 300 mm 220 mm

Question-2 Find the moment of inertia about centroidal X-axis and centroidal Y-axis of the given geometry Figure: 2a and 2b

find neutral axis + moment of inertia