Worksheet - Fire Suppression System

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School

Kent State University *

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Course

35040

Subject

Mechanical Engineering

Date

Dec 6, 2023

Type

docx

Pages

6

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Name:___ AERN 45030 – Aircraft Systems II Worksheet Lesson Two – Fire Suppression Systems DUE: 16 Feb - Beginning of class ___________________________________________________________________________________ This worksheet is designed to exercise both basic laws of physics while focusing on Pascal’s Law to better understand the methods behind the hydraulic/pneumatic design implementations considered within an aircraft’s fire suppression system. The exam will use variations of these formulas and relationship to exercise your knowledge. All diagrams and formulas WILL be provided on the exam as shown here. Complete/answer the following questions/problems. Calculate to the nearest hundredth (.00), show your work and make sure you provide the proper unit(s) with your work. Circle your answer. Formulas for finding area: Formulas for finding volume:
Relationship between Relationship between Force/pressure/area volume/area/distance Mechanical Advantage Use the formulas/relationship listed on the previous page to calculate the following: 1. Find the area of a circle with a 10 inch diameter:
2. Find the volume of a cylinder 8 inches high with a diameter of 6 inches: 3. How much force will a 1000 psi hydraulic system, acting on a piston with an area of 0.5 square inch produce? 4. The area needed for a 1000 psi hydraulic system to produce a force of 5000 pounds is? 5. How much pressure is needed to act on a piston with an area of 2 square inches to produce 5000 pounds of force? 6. How much fluid will be displaced when a piston with an area of 20 square inches is moved into a cylinder for a distance of 5 inches? 7. What area must a piston have to move 100 cubic inches of fluid from a cylinder with a piston movement of 5 inches? 8. How far must a 20 square inch piston move to displace 100 cubic inches of fluid? The formulas that relate to the following problems are shown below: P1 = P2 (since the pressures are equal throughout). Since pressure equals force per unit area, then it follows that
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