Homework Ch 8 and 9 ME240 FALL 2022

1. For the stress-strain curve shown below, please estimate the properties indicated. (a) Fracture Strain Please do your work on a separate sheet of paper, and put your answers in the boxes on the right. Be sure to include the proper symbol and units. Stress Strain 70 60 50 Stress (ksi) 240 30 20 10 70 0 0.000 60 50 Stress (ksi) 40 20 10 KULL 0 0.000 0.010 0.050 0.100 Strain (in/in) Stress Strain 0.020 0.030 Strain (in/in) 0.040 0.150 0.050 (b) Ultimate Tensile Stress (c) Fracture Stress (d) Proportional Limit (e) Elastic Modulus (1) Yield Stress (g) Tensile Toughness (Modulus of Toughness) (h) Modulus of Resilience

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The theoretical failure strength is significantly higher than the empirical failure strength of polycrystalline materials, even when they are highly polished because: a) Polycrystalline materials have little or no capacity for plastic deformation, so they have lower failure stresses b) Plastic deformation in polycrystalline materials adsorbs energy which reduces their failure strength c)The energy needed to break the atomic bonds in crystal lattices is lower in polycrystalline materials as compared to in single crystals d)Polycrystalline materials contain internal discontinuities

option e and f plz

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!A tension test performed on a metal specimen to fracture produced the stress- strain relationship shown in Figure Pi.14. Graphically determine the following (show units and all work): a. Modulus of elasticity within the linear portion. b. Yield stress at an offset strain of 0.002 m/m. c. Yield stress at an extension strain of 0.005 m/m. d. Secant modulus at a stress of 525 MPa. e. Tangent modulus at a stress of 525 MPa. 750 600 450 300 150 0.002 0.004 0.006 0.008 0.01 0.012 Strain, m/m FIGURE P1.14 Stress, MPa

9) An aircraft component is made of an aluminum alloy that has a fracture toughness of 60MPavm. When a crack of 2.5mm exists in the component, the material fractures when a stress of 440MPA is reached. If a crack of 5.5mm exists in the material, what stress would need to be reached to cause failure?

1. Plot the engineering stress & strain diagram of an alloy having a tensile test result found in Table 1. The tensile test specimen has a diameter of 12.5mm and a gage length of 50.0mm. The given alloy is used to make a 30.0mm diameter cylinder, which is placed inside a hardened circular steel casement with a 30.01mm inner diameter. Table 1: Tensile test results of an alloy Change In Length (mm) Change In Diameter (mm) Load (kN) 0.000 0.0000 0.0000 4.364 0.0254 -0.0019 13.092 0.0762 -0.0057 21.819 0.1270 -0.0095 30.547 0.1778 32.729 0.7620 34.911 3.0480 30.01 mm Ø F Rigid Plate Cylindrical Alloy - Steel casement Figure 1: Section view of the steel casement encapsulating the cylindrical alloy 2. Determine the required minimum value of F such that the cylindrical alloy would touch the walls of the steel casement.

Question 1 You are working on a design team at a small orthopaedic firm. You have been asked to select a cobalt- chrome-molybdenum (CoCr) material that will not experience plastic deformation under a specific mechanical test, as follows... A tensile stress is applied along the long axis of a solid cylindrical rod that has a diameter of 10 mm. An applied load of some magnitude F produces a 7x10-³ mm change in diameter (see figure below, original shape is blue, elongated shape is unshaded). Q1G: If your design required using the new material to create a wire, what is the largest diameter that would lead to ductile behavior while still avoiding plastic deformation when exposed to the above loading conditions?

Please explain each step briefly.

material engineering

Question 1 You are working on a design team at a small orthopaedic firm. You have been asked to select a cobalt- chrome-molybdenum (CoCr) material that will not experience plastic deformation under a specific mechanical test, as follows... A tensile stress is applied along the long axis of a solid cylindrical rod that has a diameter of 10 mm. An applied load of some magnitude F produces a 7x10³ mm change in diameter (see figure below, original shape is blue, elongated shape is unshaded). Q1H: Provide a brief rationale based on calculations used to support your answer. That is, how would you explain the behavior of the "new alloy" material to your design team? Table of properties: Assume Poisson's ratio is 0.3 for all materials Process Elastic Modulus (GPa) Material CoCr F75 As cast/Annealed 210 CoCr F90 Hot forged New alloy Z X ↑ F df O 210 110 Yield Strength (MPa) 450-517 900-1200 600 Tensile Strength (MPa) 655-890 1400-1600 700

Question 1 You are working on a design team at a small orthopaedic firm. You have been asked to select a cobalt- chrome-molybdenum (CoCr) material that will not experience plastic deformation under a specific mechanical test, as follows... A tensile stress is applied along the long axis of a solid cylindrical rod that has a diameter of 10 mm. An applied load of some magnitude F produces a 7x10³ mm change in diameter (see figure below, original shape is blue, elongated shape is unshaded). Q1C-D: Using the table of material properties below, calculate the magnitude of stress (o) and applied load (F) required to produce the 7x10-³ mm change in diameter for rods fabricated from F75 CoCr alloy (as cast) and F90 CoCr alloy (hot forged) materials.

Define failure theories used in mechanical design

i need clear ans and solve very very fast in 20 min and thank you DYBALA Given the engineering stress-engineering strain diagram for an aluminum alloy initially 11 mm in diameter and 50 mm in length, calculate the following: 1. elongation at fracture 2. True stress at an engineering strain of 0.04. 3. True strain at an engineering strain of 0.04, 4. Elongation (AL) when a load of 25 kN is applied. 5. Why does the engineering stress-strain curve peak and drop where as the true stress- strain curve keep on going up? Stress (MPa) 400 300 200 100 0 0 10³ psi MPa 50r 300 100 40 200-30 20 10- لله اه 0.05 0.005 0.010 0.10 Strain 0.15 60 50 -40 30 20 0.20 10

No wrong answer please , i could downvote The piece of suture is tested for its stress relaxation properties after cutting 3 cm long sample with a diameter of 1mm. The initial force recorded after stretching 0.1 cm between grips was 5 Newtons. Assume the suture material behave as if it has one relaxation time. The gage length was 1 cm. a. Calculate the initial stress. b. Calculate the initial strain. c. Calculate the modulus of elasticity of the suture if the initial stretching can be considered as linear and elastic. d. Calculate the relaxation time if the force recorded after 10 hours is 4 Newtons.

Learning Goal: As shown, a differential element of material is distorted after it is subjected to stresses resulting in a state of plane strain given by = -1 -360.0 x 10-6 in/in, Ey = 225.0 x 10-6 in/in, and H Yzy = 110.0 x 10-6 in/in.(Figure 1) Figure E dy y Yxy 2 & dr- dx BO Part A - In-plane principal strains and their orientation Determine the in-plane principal strains €₁ and 2 and their orientations that are associated with the differential element of material. Express your answers to four significant figures separated by commas. ► View Available Hint(s) €1, €2, p = Submit ΠΫΠΙ ΑΣΦ | VE Previous Answers vec Ĵ he X Incorrect; Try Again; 4 attempts remaining Part B - Maximum in-plane shear strain and its orientation MED ? in/in, in/in, rad Determine the magnitude of the maximum in-plane shear strain, in plane and its orientation relative to the differential element of materi Express your answers to four significant figures separated by a comma.

Question 5 A solid circular cross-section rod made up of aluminium having 20 mm diameter and 300 mm length is subjected to a tensile test. At the load of 30 kN, the rod showed 0.4 mm of extension, and started to yield. a) Calculate the yield stress of this type of aluminium in MPa. b) Calculate the Young Modulus of this type of aluminium in GPa. c) If the fracture stress for this sample is 50 MPa and the max elongation just before the fracture was 2 mm, calculate the total length of the rod after the fracture.

A manufacturing process that unintentionally introduces cracks to the surface of a part was used to produce load-bearing components. The design requires that the component be able to withstand a stress of 450 MPa. The component failed catastrophically in service. You are a failure analysis engineer who must determine whether the component failed due to an overload in the service or flaws from the manufacturing process. The manufacturer claims that the components were polished to remove the cracks and inspected to ensure that no surface cracks were larger than 0.5 mm. the manufacturer believe the component failed due to operator error. It has been independently verified that he 5 cm diameter part was subjected to a tensile load of 1 MN (106 N) The material from which the component is made had a fracture toughness of 75 MPaÖm and ultimate tensile strength of 600 MPa. Assume external cracks for which f = 1.12. Who is at fault for the component failure, the manufacturer or the operator?…

1) sketch a cantilever beam subjected to a uniformly distributed beam load over its entire length and a concentrated load at its free end. State the bending stress formula with clear indication of each parameter.

Stuck need help! Problem is attached. please view attachment before answering.  Really struggling with this concept. Please show all work so I can better understand ! Thank you so much.

hings The following results were obtained during a tensile test to destruction on a mild steel test piece of diameter 15.96mm and 80mm gauge length Extension for a load of 40KN = 0.08mm Maximum load applied during test = 93kN Diameter at fracture = 12.85mm %3D Final length between gauge points 106mm From these results, determine: i) The modulus of elasticity for mild steel ii) The tensile strength iii) Percentage of elongation iv) Percentage of reduction in area

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Request: Can you please help me with answering the following question? Thank you. Question: A specimen of a ceramic material having an elastic modulus of 250 GPa (36.3 x 106 psi) is pulled in tension with a stress of 750 MPa (109,000 psi).  Will the specimen fail if its “most severe flaw” is an internal crack that has a length of 0.20 mm (7.87 x 10-3 in.) and a tip radius of curvature of 0.001 mm (3.94 x 10-5 in.)?  Why or why not?

You are called in to evaluate the failure of a component produced from a nickel superalloy (Inconel). The evaluator is not sure what they are looking at. You are sent the following micrograph. Educate this young engineer. a. Detail everything that you can see in terms of the characteristics of failure. b. Define if you can whether this is a ductile or brittle failure. c. Can you interpret the direction of fracture progression?

Define the given terms related to mechanical properties of materials. 1. Nanoindentation 2. Neckling 3. Newton’s material 4. Notch sensitivity test 5. Offset strain value