PHY 101L Module Six Lab Report

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PHY 101L Module Six Lab Report Name: Thomas Hubert Date: 10/07/2023 Complete this lab report by replacing the bracketed text with the relevant information. Activity 1: Elastic Collision with Equal Masses Table 1A: Cart A Before Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v A 0.067 0.50 0.66 0.69 0.7246 0.73 0.68 Table 1B: Cart A After Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v A ’ 0.067 0.03 0.00 0.00 0.00 0.00 0.00 Table 1C: Cart B After Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v B ’ 0.067 0.50 0.53 0.693 0.7215 0.87 0.68 Calculations for Activity 1: Elastic Collision with Equal Masses Apply the law of conservation of momentum to the two-cart system by calculating the momentum before and after the collision. Helpful equations : Momentum before the collision = 𝑚 𝐴 𝒗 𝐴 + 𝑚 𝐵 𝒗 𝐵 Momentum after the collision = 𝑚 𝐴 𝒗 𝐴 + ′ 𝑚 𝐵 𝒗 𝐵 ′ 𝑚 𝐴 𝒗 𝐴 + 𝑚 𝐵 𝒗 𝐵 = 𝑚 𝐴 𝒗 𝐴 + ′ 𝑚 𝐵 𝒗 𝐵 ′ Percent difference = | first value − second value first value + second value 2 | x 100%

1. Calculate the momentum of the system before the collision (the left side of the equation) and after the collision (the right side of the equation). Before collision = 0.067 kg (0.7246 m/s) + 0.067 kg (0.7215 m/s) = 0.09689 kg*m/s After collision = 0.067 kg (0.00 m/s) + 0.067 kg (0.7215 m/s) = 0.04834 kg*m/s 2. Calculate the percent difference between the two values. Percent difference = |(0.09689 - 0.0483)/((0.09689 + 0.0483)/2)| x 100% = 66.93% 3. Explain any difference in the values before and after the collision. Most of the momentum was not conserved, this could be from friction and air resistance. Activity 2: Elastic Collision: Mass Added to Cart A Table 2A: Cart A Before Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v A 0.193 0.50 0.57 0.506 0.9881 0.48 0.47 Table 2B: Cart A After Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v A ’ 0.193 0.30 0.76 0.86 0.3488 1.01 0.81 Table 2C : Cart B After Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v B ’ 0.193 0.50 0.41 0.40 1.25 0.38 0.41 Calculations for Activity 2: Elastic Collision: Mass Added to Cart A Apply the law of conservation of momentum to the two-cart system by calculating the momentum before and after the collision. Helpful equations :

Momentum before the collision = 𝑚 𝐴 𝒗 𝐴 + 𝑚 𝐵 𝒗 𝐵 Momentum after the collision = 𝑚 𝐴 𝒗 𝐴 + ′ 𝑚 𝐵 𝒗 𝐵 ′ 𝑚 𝐴 𝒗 𝐴 + 𝑚 𝐵 𝒗 𝐵 = 𝑚 𝐴 𝒗 𝐴 + ′ 𝑚 𝐵 𝒗 𝐵 ′ Percent difference = | first value − second value first value + second value 2 | × 100% 1. Calculate the momentum of the system before the collision (the left side of the equation) and after the collision (the right side of the equation). Before Collision: (0.193 x 0.9881) + (0.67 x 1.25) = 1.0282 After Collision: (0.193 x 0.3488) + (0.67 x 1.25) = 0.9049 2. Calculate the percent difference between the two values. Percent difference = |(1.0282 - 0.9049)/((1.0282 + 0.9049)/2)| x 100% = 12.76% 3. Explain any difference in the values before and after the collision. Activity 3: Elastic Collision: Mass Added to Cart B Table 3A: Cart A Before Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v A 0.094 0.35 0.58 0.496 0.7056 0.42 0.49 Table 3B: Cart A After Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v A ’ 0.094 0.10 1.26 1.24 -0.0806 1.11 1.34 Table 3C: Cart B After Collision

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