Rotodyne
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Physics department Student’s Name-
Arpanpreet Kaur Grade-
Experiment Title-
Moment of Inertia “Rotodyne” Apparatus
Experiment Number-
6 Date Performed-
11/15/2023
Labortaory Course
- PHYS-011B Section-
Laboratory Instructor-
Professor Angela Lukaszewski
Group Number-
3 Group Members- Arpanpreet Kaur
Abstract The objective of the lab is to simply show that the change in distribution of the mass, the
moment of inertia changes. The equations that were used were a=2h/t^2, α=a/r, and T= m(g-a) r.
The tools that were used were a meter stick, mass set, 4 additional masses, a stop pad and a
digital timer. The theoretical values for all three investigations did not fall within our experimental range.
Sketch of Apparatus
C
harts and Graphs 2a. Moment of Inertia of the Wheel Alone M falling Average time to fall
1m Acceleration a=2h/T
2
Angular Acceleration α=a/r
Applied Torque T=m(g-a)r
kg
sec
m/s
2
[m/s
2
]/m
Nm
0.040
2.15413
0.4310
2.155
0.07503
0.060
1.75283
0.6509
3.2545
0.10990
0.080
1.524
0.8611
4.3055
0.14318
0.100
1.3715
1.0632
5.316
0.17493
0.120
1.27463
1.2310
6.155
0.20589
Least Square Fit X
i
Y
i
X
i
Y
i
X
i
2
Y
b
= m
b
X
i
+ b (Y
b
-Y
i
)
2
2.155
0.07503
0.16168965
4.644025
0.074172
7.36164E-07
3.2545
0.10990
0.35766955
10.59177025
0.109795
1.1025E-08
4.3055
0.14318
0.61646149
18.53733025
0.143848
4.46224E-07
5.316
0.17493
0.92992788
28.259856
0.176588
2.74896E-06
6.155
0.20589
1.26725295
37.884025
0.203772
4.48592E-06
21.186
0.70893
3.33300152
99.9170065
8.4283E-06
Calculations
2b. Moment of Inertia of Wheel plus 4 additional masses at the maximum allowable distance
M falling Average time to fall
1m Acceleration a=2h/T
2
Angular Acceleration α=a/r
Applied Torque T=m(g-a)r
kg
sec
m/s
2
[m/s
2
]/m
Nm
0.040
3.0364
0.216926
1.08463
0.076744
0.060
2.2426
0.397673
1.988365
0.112947
0.080
2.1347
0.438890
2.19445
0.149937
0.100
1.906
0.550534
2.75267
0.185189
0.120
1.7497
0.653285
3.266425
0.219761
Least Square Fit X
i
Y
i
X
i
Y
i
X
i
2
Y
b
= m
b
X
i
+ b (Y
b
-Y
i
)
2
1.08463
0.076744
0.083238845
1.176422237
0.069520988
5.21719E-05
1.988365
0.112947
0.224579862
3.953595373
0.130613474
0.000312104
2.19445
0.149937
0.32902925
4.815610803
0.14454482
2.90756E-05
2.75267
0.185189
0.509764205
7.577192129
0.182280492
8.45942E-06
3.266425
0.219761
0.717832824
10.66953228
0.21701033
7.56619E-06
11.28654
0.744578
1.864444985
28.19235282
0.000409377
Calculations
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A bowling ball made for a child has 1/2 times the radius of an adult bowling ball. It is made of the same material (and
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2 Experiment_27_L...pdf
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E) 80
Lütfen birini seçin:
O A
OB
OD
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(3.0 x 10 N/m2)- (4.9 x 10 N/m²)- (6.0 x 10 N/m2)
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Sample Problem
You own a restaurant that is investigating new ways to deliver beverages to
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NEED FULLY CORRECT HANDWRITTEN SOLUTION FOR THIS.
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QUESTION 3
- The following equation refers to v-pendulum experiment:
T4 = (44 L ki g²)(8 m4L/g² )d, where :
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T: pendulum periodic time
d: distance between rods
k: pendulum constant
g: gravitational acceleration
Given that the slope of the graph (T4,d) = -14.2 s4/m, and y-intercept = 13.5 s4,
Find the value for g:
9.81 m/s2
O Can't be defined
a-
8.51 m/s2
a 10.5 m/s²
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READING:
T1 (C)
T2 ('C)
V(mv)
41
20
60
20
9.9
80
20
14.9
100
20
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34
m kg /s; m= 9.11 x 10
31
kg)
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0.8
04
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B. DIRECTION: Look at the graph below. Note that it shows the motion of a motorcycle accelerating from rest.
Perform what is asked on the next slide.
v(km/h)
How fast was the motorcycle
а.
100
moving at the following times:
2.0, 4.0, and 15.0 seconds?
50
b. Solve the acceleration
through the following time
intervals: 0 to 4.0 seconds; 4.0
to 10.0 seconds; and 10.0 to
15.0 seconds
15
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For years, the tallest tower in the United States was the Phoenix Shot Tower in Baltimore, Maryland. The shot tower was used from 1828 to1892 to make lead shot for pistols and rifles and molded shot for cannons and other instruments of warfare. Molten lead was dropped from the top of the 82.15 m tall tower into a vat of water. During its free fall, the lead would form a perfectly spherical droplet and solidify. Determine the velocity of the droplet right before it hits the ground. (Note: acceleration = -9.81 m/s/s) (Hint: think about the direction the droplet travels when considering its displacement.)
___________m/s
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Q--k->
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1.
An m-mass body slides a distance of d along a horizontal surface. The work done by the force
of gravity is:
а.
mgd
b.
Zero
-mgd
(mg sene)d
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d.
е.
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2.
Total work on a body is positive if:
the resulting force has the same direction of displacement
Theresulting force is perpendicular to displacement
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the object does not move
a.
b.
С.
d.
е.
3.
The unit of kinetic energy can be expressed as:
kgm/s
kgm/s?
m/(kgs)
kgs?
2/s'kgs?
а.
b.
С.
d.
е.
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- The following equation refers to v-pendulum experiment:
T4 = (44 L k/g²)-(8 mL/g² )d, where :
L: length of the string (2 meters).
T: pendulum periodic time
d: distance between rods
k: pendulum constant
g: gravitational acceleration
Given that the slope of the graph (T4,d) = -14.2 s/m, and y-intercept = 13.5 s4,
Find the value for g:
a-
a-
10.5 m/s²
9.81 m/s²
Can't be defined
of
●
a- 8.51 m/s2
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QUESTION 5
the following equation refers to V-pendulum experiment
T4 = (44 L k/g²)(8 m4L/g² )d, where :
L: length of the string (2 meters).
T: pendulum periodic time
d: distance between rods
k: pendulum constant
g: gravitational acceleration
Given that the slope of the graph (T4,d) = -14.2 s4/m, and y-intercept-13.5 s4,
Find the value for K:
1.91 m
O 2.00 m
O 19.1 m
2.10 m
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1) In your own words, explain was is expected of this experiment.
2) In your own words, explain what would the outcome of this experiment be.
3) Sum up the theory of this experiment in your own words.
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Pd
Pd
1. Let's consider a toy model of nuclear fission. Suppose an nucleus of Uranium-235 (92 protons, molar
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how it really happens, but it's a very simple model that actually gives fairly accurate results. The
radius of the original U-235 nucleus is about 7.4 x 10-15 m.
(a) If the Pd nuclei each have half the volume of the U nucleus, which is reasonable, and they are
"touching" right after the split, how far apart are their centers?
(b) Using conservation of energy, what will be the sum of the kinetic energies of the Pd nuclei
when they are far apart from each other?
(c) That's energy of one atom undergoing fission, so what, then, is the energy released by the
fission of 1 kg of U-235? Express this in Joules and also in kilotons of TNT, where 1 kt = 4.2x1012
J. (The Hiroshima bomb yielded about 15 kt)
(d) How many kwh (kilowatt-hours) of energy is this, (1 kwh = 3.6x10° J), and (if…
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Result: 9.85± 0.18
(b) Compare the result with the accepted value of g = 9.82 ± 0.02 m/s2.
(c) Does the student’s result agree with the accepted value? Explain.
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A non-homogeneous bar is 50 cm long and its linear density is given by the function λ(x)=32 + 25x² , where x is the position of the bar from one end, where λ is given g/m (grams per meter). a) Draw a sketch of the bar and mark where on the bar its center of mass is locatedb) Calculate the total mass of the rod.
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ASK YOUR TEACHER
PRACTICE ANOTHER
Since neutron stars consist totally of neutrons, they are extremely massive and have a density that is hard to imagine. A typical radius and mass for a neutron star are 1.65 x 10 m and
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(a) Determine the density of a neutron star.
kg/m
(b) Determine the weight (in pounds) of a penny (V = 360 mm-) if it were made from this material. (Assume 1 lb = 4.448 N.)
Ib
Additional Materials
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Need help with parts A and B pls.
Part B asks: What is this minimum value of mass of the child?
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- 8. What is the initial velocity of the marble that undergoes projectile motion in the given data in Item 6?arrow_forwardQuestion 12/ 13 An electron mnoves in a straight line with constant speed y= 1.1 x10" m's which has been measured with precision of 0.10%. What is the maximum possible precision in which its position could be measured? (h= 6.62 x 10 34 m kg /s; m= 9.11 x 10 31 kg)arrow_forwardI am working on this problem and have been getting wrong answers I am not sure if it is due to integration or not but what I have so far determined is that. Note y1 = y1(x) and y2 = y2(x) distance to dm (r)=x Differential Area (dA) = (y1 - y2) * dx Differential Mass (dm) = sigma * (y1-y2) * dx Differential Moment (dI) = x^2 * sigma(y1-y2)dxarrow_forward
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